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Python gallery.poisson函数代码示例

原作者: [db:作者] 来自: [db:来源] 收藏 邀请

本文整理汇总了Python中pyamg.gallery.poisson函数的典型用法代码示例。如果您正苦于以下问题:Python poisson函数的具体用法?Python poisson怎么用?Python poisson使用的例子?那么恭喜您, 这里精选的函数代码示例或许可以为您提供帮助。



在下文中一共展示了poisson函数的20个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于我们的系统推荐出更棒的Python代码示例。

示例1: setUp

    def setUp(self):
        self.cases = []

        A = poisson((5000,), format='csr')
        self.cases.append((A, None, 0.4, 'symmetric',
                           ('jacobi', {'omega': 4.0 / 3.0})))
        self.cases.append((A, None, 0.4, 'symmetric',
                           ('energy', {'krylov': 'cg'})))
        self.cases.append((A, None, 0.5, 'symmetric',
                           ('energy', {'krylov': 'gmres'})))

        A = poisson((60, 60), format='csr')
        self.cases.append((A, None, 0.42, 'symmetric',
                           ('jacobi', {'omega': 4.0 / 3.0})))
        self.cases.append((A, None, 0.42, 'symmetric',
                           ('energy', {'krylov': 'cg'})))
        self.cases.append((A, None, 0.42, 'symmetric',
                           ('energy', {'krylov': 'cgnr'})))

        A, B = linear_elasticity((50, 50), format='bsr')
        self.cases.append((A, B, 0.32, 'symmetric',
                           ('jacobi', {'omega': 4.0 / 3.0})))
        self.cases.append((A, B, 0.22, 'symmetric',
                           ('energy', {'krylov': 'cg'})))
        self.cases.append((A, B, 0.42, 'symmetric',
                           ('energy', {'krylov': 'cgnr'})))
        self.cases.append((A, B, 0.42, 'symmetric',
                           ('energy', {'krylov': 'gmres'})))
开发者ID:ChaliZhg,项目名称:pyamg,代码行数:28,代码来源:test_aggregation.py


示例2: setUp

    def setUp(self):
        self.cases = []

        # Test 1
        A = poisson((5000,), format="csr")
        Ai = A + 1.0j * scipy.sparse.eye(A.shape[0], A.shape[1])
        self.cases.append((Ai, None, 0.12, "symmetric", ("jacobi", {"omega": 4.0 / 3.0})))
        self.cases.append((Ai, None, 0.12, "symmetric", ("energy", {"krylov": "gmres"})))

        # Test 2
        A = poisson((71, 71), format="csr")
        Ai = A + (0.625 / 0.01) * 1j * scipy.sparse.eye(A.shape[0], A.shape[1])
        self.cases.append((Ai, None, 1e-3, "symmetric", ("jacobi", {"omega": 4.0 / 3.0})))
        self.cases.append((Ai, None, 1e-3, "symmetric", ("energy", {"krylov": "cgnr"})))

        # Test 3
        A = poisson((60, 60), format="csr")
        Ai = 1.0j * A
        self.cases.append((Ai, None, 0.3, "symmetric", ("jacobi", {"omega": 4.0 / 3.0})))
        self.cases.append((Ai, None, 0.6, "symmetric", ("energy", {"krylov": "cgnr", "maxiter": 8})))
        self.cases.append((Ai, None, 0.6, "symmetric", ("energy", {"krylov": "gmres", "maxiter": 8})))

        # Test 4
        # Use an "inherently" imaginary problem, the Gauge Laplacian in 2D from
        # Quantum Chromodynamics,
        A = gauge_laplacian(70, spacing=1.0, beta=0.41)
        self.cases.append((A, None, 0.4, "hermitian", ("jacobi", {"omega": 4.0 / 3.0})))
        self.cases.append((A, None, 0.4, "hermitian", ("energy", {"krylov": "cg"})))
开发者ID:JulianCienfuegos,项目名称:pyamg,代码行数:28,代码来源:test_aggregation.py


示例3: setUp

    def setUp(self):
        self.cases = []

        # Test 1
        A = poisson((5000,), format='csr')
        Ai = A + 1.0j * scipy.sparse.eye(A.shape[0], A.shape[1])
        self.cases.append((Ai, None, 0.12, 'symmetric',
                           ('energy', {'krylov': 'gmres'})))

        # Test 2
        A = poisson((71, 71), format='csr')
        Ai = A + (0.625 / 0.01) * 1.0j *\
            scipy.sparse.eye(A.shape[0], A.shape[1])
        self.cases.append((Ai, None, 1e-3, 'symmetric',
                           ('energy', {'krylov': 'cgnr'})))

        # Test 3
        A = poisson((60, 60), format='csr')
        Ai = 1.0j * A
        self.cases.append((Ai, None, 0.35, 'symmetric',
                           ('energy', {'krylov': 'cgnr', 'maxiter': 8})))
        self.cases.append((Ai, None, 0.35, 'symmetric',
                           ('energy', {'krylov': 'gmres', 'maxiter': 8})))

        # Test 4 Use an "inherently" imaginary problem, the Gauge Laplacian in
        # 2D from Quantum Chromodynamics,
        A = gauge_laplacian(70, spacing=1.0, beta=0.41)
        self.cases.append((A, None, 0.25, 'hermitian',
                           ('energy', {'krylov': 'cg'})))
开发者ID:GaZ3ll3,项目名称:pyamg,代码行数:29,代码来源:test_rootnode.py


示例4: setUp

 def setUp(self):
     self.cases = []
     
     # Consider "Helmholtz" like problems with an imaginary shift so that the operator 
     #   should still be SPD in a sense and SA should perform well.
     # There are better near nullspace vectors than the default, 
     #   but a constant should give a convergent solver, nonetheless.
     A = poisson( (100,),  format='csr'); A = A + 1.0j*scipy.sparse.eye(A.shape[0], A.shape[1])
     self.cases.append((A, None))
     A = poisson( (10,10),  format='csr'); A = A + 1.0j*scipy.sparse.eye(A.shape[0], A.shape[1])
     self.cases.append((A, None))
开发者ID:gaussWu,项目名称:pyamg,代码行数:11,代码来源:test_aggregation.py


示例5: setUp

    def setUp(self):
        self.cases = []

        # Poisson problems in 1D and 2D
        N = 20
        self.cases.append((poisson((2*N,), format='csr'), rand(2*N,)))     # 0
        self.cases.append((poisson((N, N), format='csr'), rand(N*N,)))  # 1
        # Boxed examples
        A = load_example('recirc_flow')['A'].tocsr()                      # 2
        self.cases.append((A, rand(A.shape[0],)))
        A = load_example('bar')['A'].tobsr(blocksize=(3, 3))               # 3
        self.cases.append((A, rand(A.shape[0],)))
开发者ID:ChaliZhg,项目名称:pyamg,代码行数:12,代码来源:test_blackbox.py


示例6: setUp

    def setUp(self):
        self.cases = []

        # Poisson problems in 1D and 2D
        for N in [2, 3, 5, 7, 10, 11, 19]:
            self.cases.append(poisson((N,), format='csr'))
        for N in [2, 3, 7, 9]:
            self.cases.append(poisson((N, N), format='csr'))

        for name in ['knot', 'airfoil', 'bar']:
            ex = load_example(name)
            self.cases.append(ex['A'].tocsr())
开发者ID:ben-s-southworth,项目名称:pyamg,代码行数:12,代码来源:test_complexity.py


示例7: setUp

    def setUp(self):
        self.cases = []

        A = poisson((5000,), format="csr")
        self.cases.append((A, None, 0.4, "symmetric", ("energy", {"krylov": "cg"})))
        self.cases.append((A, None, 0.4, "symmetric", ("energy", {"krylov": "gmres"})))

        A = poisson((75, 75), format="csr")
        self.cases.append((A, None, 0.26, "symmetric", ("energy", {"krylov": "cg"})))
        self.cases.append((A, None, 0.30, "symmetric", ("energy", {"krylov": "cgnr"})))

        A, B = linear_elasticity((50, 50), format="bsr")
        self.cases.append((A, B, 0.3, "symmetric", ("energy", {"krylov": "cg"})))
        self.cases.append((A, B, 0.3, "symmetric", ("energy", {"krylov": "cgnr"})))
        self.cases.append((A, B, 0.3, "symmetric", ("energy", {"krylov": "gmres"})))
开发者ID:czielinski,项目名称:pyamg,代码行数:15,代码来源:test_rootnode.py


示例8: setUp

    def setUp(self):
        self.cases = []

        # Poisson problems in 2D
        for N in [2,3,5,7,8]:
            A = poisson( (N,N), format='csr'); A.data = A.data + 0.001j*rand(A.nnz)
            self.cases.append(A)
开发者ID:GaZ3ll3,项目名称:pyamg,代码行数:7,代码来源:test_aggregate.py


示例9: test_DAD

    def test_DAD(self):
        A = poisson((50, 50), format='csr')

        x = rand(A.shape[0])
        b = rand(A.shape[0])

        D = diag_sparse(1.0 / sqrt(10 ** (12 * rand(A.shape[0]) - 6))).tocsr()
        D_inv = diag_sparse(1.0 / D.data)

        DAD = D * A * D

        B = ones((A.shape[0], 1))

        # TODO force 2 level method and check that result is the same
        kwargs = {'max_coarse': 1, 'max_levels': 2, 'coarse_solver': 'splu'}

        sa = rootnode_solver(D * A * D, D_inv * B, **kwargs)

        residuals = []
        x_sol = sa.solve(b, x0=x, maxiter=10, tol=1e-12, residuals=residuals)

        avg_convergence_ratio =\
            (residuals[-1] / residuals[0]) ** (1.0 / len(residuals))

        # print "Diagonal Scaling Test:   %1.3e,  %1.3e" %
        # (avg_convergence_ratio, 0.4)
        assert(avg_convergence_ratio < 0.4)
开发者ID:GaZ3ll3,项目名称:pyamg,代码行数:27,代码来源:test_rootnode.py


示例10: test_solver_parameters

    def test_solver_parameters(self):
        A = poisson((50, 50), format='csr')

        for method in methods:
            # method = ('richardson', {'omega':4.0/3.0})
            ml = smoothed_aggregation_solver(A, presmoother=method,
                                             postsmoother=method,
                                             max_coarse=10)

            residuals = profile_solver(ml)
            assert((residuals[-1]/residuals[0])**(1.0/len(residuals)) < 0.95)
            assert(ml.symmetric_smoothing)

        for method in methods2:
            ml = smoothed_aggregation_solver(A, max_coarse=10)
            change_smoothers(ml, presmoother=method[0], postsmoother=method[1])

            residuals = profile_solver(ml)
            assert((residuals[-1]/residuals[0])**(1.0/len(residuals)) < 0.95)
            assert(not ml.symmetric_smoothing)

        for method in methods3:
            ml = smoothed_aggregation_solver(A, max_coarse=10)
            change_smoothers(ml, presmoother=method[0], postsmoother=method[1])
            assert(ml.symmetric_smoothing)

        for method in methods4:
            ml = smoothed_aggregation_solver(A, max_coarse=10)
            change_smoothers(ml, presmoother=method[0], postsmoother=method[1])
            assert(not ml.symmetric_smoothing)
开发者ID:pyamg,项目名称:pyamg,代码行数:30,代码来源:test_smoothing.py


示例11: test_DAD

    def test_DAD(self):
        A = poisson((50, 50), format="csr")

        x = rand(A.shape[0])
        b = rand(A.shape[0])

        D = diag_sparse(1.0 / sqrt(10 ** (12 * rand(A.shape[0]) - 6))).tocsr()
        D_inv = diag_sparse(1.0 / D.data)

        DAD = D * A * D

        B = ones((A.shape[0], 1))

        # TODO force 2 level method and check that result is the same
        kwargs = {"max_coarse": 1, "max_levels": 2, "coarse_solver": "splu"}

        sa = smoothed_aggregation_solver(D * A * D, D_inv * B, **kwargs)

        residuals = []
        x_sol = sa.solve(b, x0=x, maxiter=10, tol=1e-12, residuals=residuals)

        avg_convergence_ratio = (residuals[-1] / residuals[0]) ** (1.0 / len(residuals))

        # print "Diagonal Scaling Test:   %1.3e,  %1.3e" %
        # (avg_convergence_ratio, 0.25)
        assert avg_convergence_ratio < 0.25
开发者ID:JulianCienfuegos,项目名称:pyamg,代码行数:26,代码来源:test_aggregation.py


示例12: test_poisson

    def test_poisson(self):
        cases = []

        cases.append((500,))
        cases.append((250, 250))
        cases.append((25, 25, 25))

        for case in cases:
            A = poisson(case, format='csr')

            np.random.seed(0)  # make tests repeatable

            x = sp.rand(A.shape[0])
            b = A*sp.rand(A.shape[0])  # zeros_like(x)

            ml = ruge_stuben_solver(A, max_coarse=50)

            res = []
            x_sol = ml.solve(b, x0=x, maxiter=20, tol=1e-12,
                             residuals=res)
            del x_sol

            avg_convergence_ratio = (res[-1]/res[0])**(1.0/len(res))

            assert(avg_convergence_ratio < 0.20)
开发者ID:pyamg,项目名称:pyamg,代码行数:25,代码来源:test_classical.py


示例13: test_improve_candidates

 def test_improve_candidates(self):
     ##
     # test improve_candidates for the Poisson problem and elasticity, where rho_scale is 
     # the amount that each successive improve_candidates option should improve convergence
     # over the previous improve_candidates option.
     improve_candidates_list = [None, [('block_gauss_seidel', {'iterations' : 4, 'sweep':'symmetric'})] ]
     # make tests repeatable
     numpy.random.seed(0) 
     
     cases = []
     A_elas,B_elas = linear_elasticity( (60,60), format='bsr')
     #                Matrix                              Candidates    rho_scale
     cases.append( (poisson( (61,61),  format='csr'), ones((61*61,1)), 0.9 ) )
     cases.append( (A_elas,                           B_elas,       0.9 ) )
     for (A,B,rho_scale) in cases:
         last_rho = -1.0
         x0 = rand(A.shape[0],1) 
         b = rand(A.shape[0],1)
         for improve_candidates in improve_candidates_list:
             ml = smoothed_aggregation_solver(A, B, max_coarse=10, improve_candidates=improve_candidates)
             residuals=[]
             x_sol = ml.solve(b,x0=x0,maxiter=20,tol=1e-10, residuals=residuals)
             rho = (residuals[-1]/residuals[0])**(1.0/len(residuals))
             if last_rho == -1.0:
                 last_rho = rho
             else:
                 # each successive improve_candidates option should be an improvement on the previous
                 # print "\nimprove_candidates Test: %1.3e, %1.3e, %d\n"%(rho,rho_scale*last_rho,A.shape[0])
                 assert(rho < rho_scale*last_rho)
                 last_rho = rho
开发者ID:gaussWu,项目名称:pyamg,代码行数:30,代码来源:test_aggregation.py


示例14: test_symmetry

    def test_symmetry(self):
        # Test that a basic V-cycle yields a symmetric linear operator.  Common
        # reasons for failure are problems with using the same rho for the
        # pres/post-smoothers and using the same block_D_inv for
        # pre/post-smoothers.

        n = 500
        A = poisson((n,), format="csr")
        smoothers = [
            ("gauss_seidel", {"sweep": "symmetric"}),
            ("schwarz", {"sweep": "symmetric"}),
            ("block_gauss_seidel", {"sweep": "symmetric"}),
            "jacobi",
            "block_jacobi",
        ]
        rng = arange(1, n + 1, dtype="float").reshape(-1, 1)
        Bs = [ones((n, 1)), hstack((ones((n, 1)), rng))]

        for smoother in smoothers:
            for B in Bs:
                ml = smoothed_aggregation_solver(A, B, max_coarse=10, presmoother=smoother, postsmoother=smoother)
                P = ml.aspreconditioner()
                x = rand(n)
                y = rand(n)
                assert_approx_equal(dot(P * x, y), dot(x, P * y))
开发者ID:JulianCienfuegos,项目名称:pyamg,代码行数:25,代码来源:test_aggregation.py


示例15: test_symmetry

    def test_symmetry(self):
        # Test that a basic V-cycle yields a symmetric linear operator.  Common
        # reasons for failure are problems with using the same rho for the
        # pres/post-smoothers and using the same block_D_inv for
        # pre/post-smoothers.

        n = 500
        A = poisson((n,), format='csr')
        smoothers = [('gauss_seidel', {'sweep': 'symmetric'}),
                     ('schwarz', {'sweep': 'symmetric'}),
                     ('block_gauss_seidel', {'sweep': 'symmetric'}),
                     'jacobi', 'block_jacobi']
        Bs = [ones((n, 1)),
              hstack((ones((n, 1)),
                      arange(1, n + 1, dtype='float').reshape(-1, 1)))]

        for smoother in smoothers:
            for B in Bs:
                ml = rootnode_solver(A, B, max_coarse=10,
                                     presmoother=smoother,
                                     postsmoother=smoother)
                P = ml.aspreconditioner()
                x = rand(n,)
                y = rand(n,)
                assert_approx_equal(dot(P * x, y), dot(x, P * y))
开发者ID:GaZ3ll3,项目名称:pyamg,代码行数:25,代码来源:test_rootnode.py


示例16: test_coarse_solver_opts

    def test_coarse_solver_opts(self):
        # these tests are meant to test whether coarse solvers are correctly
        # passed parameters

        A = poisson((30, 30), format='csr')
        b = sp.rand(A.shape[0], 1)

        # for each pair, the first entry should yield an SA solver that
        # converges in fewer iterations for a basic Poisson problem
        coarse_solver_pairs = [(('jacobi', {'iterations': 30}), 'jacobi')]
        coarse_solver_pairs.append((('gauss_seidel',
                                     {'iterations': 30}), 'gauss_seidel'))
        coarse_solver_pairs.append(('gauss_seidel', 'jacobi'))
        coarse_solver_pairs.append(('cg', ('cg', {'tol': 10.0})))
        coarse_solver_pairs.append(('pinv2', ('pinv2', {'cond': 1.0})))

        for coarse1, coarse2 in coarse_solver_pairs:
            r1 = []
            r2 = []
            sa1 = rootnode_solver(A, coarse_solver=coarse1)
            sa2 = rootnode_solver(A, coarse_solver=coarse2)
            x1 = sa1.solve(b, residuals=r1)
            x2 = sa2.solve(b, residuals=r2)
            del x1, x2
            assert((len(r1) + 5) < len(r2))
开发者ID:karthicks123,项目名称:pyamg,代码行数:25,代码来源:test_rootnode.py


示例17: test_improve_candidates

    def test_improve_candidates(self):
        # test improve_candidates for the Poisson problem and elasticity, where
        # rho_scale is the amount that each successive improve_candidates
        # option should improve convergence over the previous
        # improve_candidates option.
        improve_candidates_list = [None, [("block_gauss_seidel", {"iterations": 4, "sweep": "symmetric"})]]
        # make tests repeatable
        numpy.random.seed(0)

        cases = []
        A_elas, B_elas = linear_elasticity((60, 60), format="bsr")
        #                Matrix                       Candidates    rho_scale
        cases.append((poisson((75, 75), format="csr"), ones((75 * 75, 1)), 0.9))
        cases.append((A_elas, B_elas, 0.9))
        for (A, B, rho_scale) in cases:
            last_rho = -1.0
            x0 = rand(A.shape[0], 1)
            b = rand(A.shape[0], 1)
            for improve_candidates in improve_candidates_list:
                ml = rootnode_solver(A, B, max_coarse=10, improve_candidates=improve_candidates)
                residuals = []
                x_sol = ml.solve(b, x0=x0, maxiter=20, tol=1e-10, residuals=residuals)
                del x_sol
                rho = (residuals[-1] / residuals[0]) ** (1.0 / len(residuals))
                if last_rho == -1.0:
                    last_rho = rho
                else:
                    # each successive improve_candidates option should be an
                    # improvement on the previous print "\nimprove_candidates
                    # Test: %1.3e, %1.3e,
                    # %d\n"%(rho,rho_scale*last_rho,A.shape[0])
                    assert rho < rho_scale * last_rho
                    last_rho = rho
开发者ID:czielinski,项目名称:pyamg,代码行数:33,代码来源:test_rootnode.py


示例18: test_nonsymmetric

    def test_nonsymmetric(self):
        # problem data
        data = load_example('recirc_flow')
        A = data['A'].tocsr()
        B = data['B']
        numpy.random.seed(625)
        x0 = scipy.rand(A.shape[0])
        b = A * scipy.rand(A.shape[0])
        # solver parameters
        smooth = ('energy', {'krylov': 'gmres'})
        SA_build_args = {'max_coarse': 25, 'coarse_solver': 'pinv2',
                         'symmetry': 'nonsymmetric'}
        SA_solve_args = {'cycle': 'V', 'maxiter': 20, 'tol': 1e-8}
        strength = [('evolution', {'k': 2, 'epsilon': 8.0})]
        smoother = ('gauss_seidel_nr', {'sweep': 'symmetric', 'iterations': 1})
        improve_candidates = [('gauss_seidel_nr', {'sweep': 'symmetric',
                                                   'iterations': 4}), None]
        # Construct solver with nonsymmetric parameters
        sa = rootnode_solver(A, B=B, smooth=smooth,
                             improve_candidates=improve_candidates,
                             strength=strength,
                             presmoother=smoother,
                             postsmoother=smoother, **SA_build_args)
        residuals = []
        # stand-alone solve
        x = sa.solve(b, x0=x0, residuals=residuals, **SA_solve_args)
        residuals = array(residuals)
        avg_convergence_ratio =\
            (residuals[-1] / residuals[0]) ** (1.0 / len(residuals))
        # print "Test 1  %1.3e,  %1.3e" % (avg_convergence_ratio, 0.7)
        assert(avg_convergence_ratio < 0.7)
        # accelerated solve
        residuals = []
        x = sa.solve(b, x0=x0, residuals=residuals, accel='gmres',
                     **SA_solve_args)
        residuals = array(residuals)
        avg_convergence_ratio =\
            (residuals[-1] / residuals[0]) ** (1.0 / len(residuals))
        # print "Test 2  %1.3e,  %1.3e" % (avg_convergence_ratio, 0.45)
        assert(avg_convergence_ratio < 0.45)

        # test that nonsymmetric parameters give the same result as symmetric
        # parameters for Poisson problem
        A = poisson((15, 15), format='csr')
        strength = 'symmetric'
        SA_build_args['symmetry'] = 'nonsymmetric'
        sa_nonsymm = rootnode_solver(A, B=ones((A.shape[0], 1)), smooth=smooth,
                                     strength=strength,
                                     presmoother=smoother,
                                     postsmoother=smoother,
                                     improve_candidates=None, **SA_build_args)
        SA_build_args['symmetry'] = 'symmetric'
        sa_symm = rootnode_solver(A, B=ones((A.shape[0], 1)), smooth=smooth,
                                  strength=strength, presmoother=smoother,
                                  postsmoother=smoother,
                                  improve_candidates=None, **SA_build_args)
        for (symm_lvl, nonsymm_lvl) in zip(sa_nonsymm.levels, sa_symm.levels):
            assert_array_almost_equal(symm_lvl.A.todense(),
                                      nonsymm_lvl.A.todense())
开发者ID:GaZ3ll3,项目名称:pyamg,代码行数:59,代码来源:test_rootnode.py


示例19: setUp

    def setUp(self):
        self.cases = []

        # random matrices
        np.random.seed(0)
        for N in [2, 3, 5]:
            self.cases.append(csr_matrix(np.random.rand(N, N)))

        # Poisson problems in 1D and 2D
        for N in [2, 3, 5, 7, 10, 11, 19]:
            self.cases.append(poisson((N,), format='csr'))
        for N in [2, 3, 5, 7, 8]:
            self.cases.append(poisson((N, N), format='csr'))

        for name in ['knot', 'airfoil', 'bar']:
            ex = load_example(name)
            self.cases.append(ex['A'].tocsr())
开发者ID:pyamg,项目名称:pyamg,代码行数:17,代码来源:test_aggregate.py


示例20: setUp

    def setUp(self):
        self.cases = []

        # random matrices
        numpy.random.seed(0)
        for N in [2,3,5]:
            self.cases.append( csr_matrix(rand(N,N)) + csr_matrix(1.0j*rand(N,N)))

        # Poisson problems in 1D and 2D
        for N in [2,3,5,7,10,11,19]:
            A = poisson( (N,), format='csr'); A.data = A.data + 1.0j*A.data;
            self.cases.append(A)
        for N in [2,3,7,9]:
            A = poisson( (N,N), format='csr'); A.data = A.data + 1.0j*rand(A.data.shape[0],);
            self.cases.append(A)

        for name in ['knot','airfoil','bar']:
            ex = load_example(name)
            A = ex['A'].tocsr(); A.data = A.data + 0.5j*rand(A.data.shape[0],);
            self.cases.append(A)
开发者ID:GaZ3ll3,项目名称:pyamg,代码行数:20,代码来源:test_strength.py



注:本文中的pyamg.gallery.poisson函数示例由纯净天空整理自Github/MSDocs等源码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。


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