本文整理汇总了TypeScript中ng-jhipster.PaginationUtil类的典型用法代码示例。如果您正苦于以下问题:TypeScript PaginationUtil类的具体用法?TypeScript PaginationUtil怎么用?TypeScript PaginationUtil使用的例子?那么恭喜您, 这里精选的类代码示例或许可以为您提供帮助。
在下文中一共展示了PaginationUtil类的3个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于我们的系统推荐出更棒的TypeScript代码示例。
示例1:
resolveFn: (paginationUtil: PaginationUtil, trans: Transition) => {
const stateParams = trans.params();
return {
page: paginationUtil.parsePage(stateParams['page']),
sort: stateParams['sort'],
predicate: paginationUtil.parsePredicate(stateParams['sort']),
ascending: paginationUtil.parseAscending(stateParams['sort'])
};
}
开发者ID:JimSpriggs,项目名称:sourdough,代码行数:9,代码来源:user-management.state.ts
示例2: constructor
constructor(
private userService: UserService,
private parseLinks: ParseLinks,
private alertService: AlertService,
private principal: Principal,
private $state: StateService,
private eventManager: EventManager,
private paginationUtil: PaginationUtil,
private paginationConfig: PaginationConfig
) {
this.itemsPerPage = ITEMS_PER_PAGE;
this.page = paginationUtil.parsePage($state.params['page']);
this.previousPage = this.page;
this.reverse = paginationUtil.parseAscending($state.params['sort']);
this.predicate = 'id';
}
开发者ID:JimSpriggs,项目名称:sourdough,代码行数:16,代码来源:user-management.component.ts
示例3: resolve
resolve(route: ActivatedRouteSnapshot, state: RouterStateSnapshot) {
const page = route.queryParams['page'] ? route.queryParams['page'] : '1';
const sort = route.queryParams['sort'] ? route.queryParams['sort'] : 'id,asc';
return {
page: this.paginationUtil.parsePage(page),
predicate: this.paginationUtil.parsePredicate(sort),
ascending: this.paginationUtil.parseAscending(sort)
};
}
开发者ID:chenshao0594,项目名称:eshop,代码行数:9,代码来源:book.route.ts
注:本文中的ng-jhipster.PaginationUtil类示例由纯净天空整理自Github/MSDocs等源码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。 |
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