本文整理汇总了Python中utilities.float_gt函数的典型用法代码示例。如果您正苦于以下问题:Python float_gt函数的具体用法?Python float_gt怎么用?Python float_gt使用的例子?那么恭喜您, 这里精选的函数代码示例或许可以为您提供帮助。
在下文中一共展示了float_gt函数的20个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于我们的系统推荐出更棒的Python代码示例。
示例1: jmax_and_vcmax_func
def jmax_and_vcmax_func(self, temp):
""" Maximum rate of electron transport (jmax) and of rubisco activity
Parameters:
-----------
temp : float
air temperature
Returns:
--------
jmax : float
maximum rate of electron transport
vcmax : float
maximum rate of Rubisco activity
"""
if float_gt(temp, 10.0):
jmax = (self.params.jmaxna * (1.0 + (temp - 25.0) * (0.05 +
(temp - 25.0) * (-1.81 * 1E-3 + (temp - 25.0) *
(-1.37 * 1E-4)))))
vcmax = (self.params.vcmaxna * (1.0 + (temp - 25.0) *
(0.0485 + (temp - 25.0) * (-6.93 * 1E-4 + (temp - 25.0) *
(-3.9 * 1E-5)))))
elif float_gt(temp, 0.0):
jmax = self.params.jmaxna * 0.0305 * temp
vcmax = self.params.vcmaxna * 0.0238 * temp
else:
jmax = 0.0
vcmax = 0.0
return jmax, vcmax
开发者ID:douglask3,项目名称:GDAY,代码行数:30,代码来源:bewdy.py
示例2: partition_plant_litter_n
def partition_plant_litter_n(self, nsurf, nsoil):
""" Partition litter N from the plant (surface) and roots into metabolic
and structural pools
Parameters:
-----------
nsurf : float
N input from surface pool
nsoil : float
N input from soil pool
"""
# constant structural input n:c as per century
if not self.control.strfloat:
# dead plant litter -> structural pool
# n flux -> surface structural pool
self.fluxes.n_surf_struct_litter = (self.fluxes.surf_struct_litter /
self.params.structcn)
# n flux -> soil structural pool
self.fluxes.n_soil_struct_litter = (self.fluxes.soil_struct_litter /
self.params.structcn)
# if not enough N for structural, all available N goes to structural
if float_gt( self.fluxes.n_surf_struct_litter, nsurf):
self.fluxes.n_surf_struct_litter = nsurf
if float_gt(self.fluxes.n_soil_struct_litter, nsoil):
self.fluxes.n_soil_struct_litter = nsoil
# structural input n:c is a fraction of metabolic
else:
c_surf_struct_litter = (self.fluxes.surf_struct_litter *
self.params.structrat +
self.fluxes.surf_metab_litter)
if float_eq(c_surf_struct_litter, 0.0):
self.fluxes.n_surf_struct_litter = 0.0
else:
self.fluxes.n_surf_struct_litter = (nsurf *
self.fluxes.surf_struct_litter *
self.params.structrat /
c_surf_struct_litter)
c_soil_struct_litter = (self.fluxes.soil_struct_litter *
self.params.structrat +
self.fluxes.soil_metab_litter)
if float_eq(c_soil_struct_litter, 0.0):
self.fluxes.n_soil_struct_litter = 0.
else:
self.fluxes.n_soil_struct_litter = (nsurf *
self.fluxes.soil_struct_litter *
self.params.structrat /
c_soil_struct_litter)
# remaining N goes to metabolic pools
self.fluxes.n_surf_metab_litter = (nsurf -
self.fluxes.n_surf_struct_litter)
self.fluxes.n_soil_metab_litter = (nsoil -
self.fluxes.n_soil_struct_litter)
开发者ID:npp97,项目名称:GDAY,代码行数:60,代码来源:soil_cn_model.py
示例3: soil_temp_factor
def soil_temp_factor(self, project_day):
"""Soil-temperature activity factor (A9).
Parameters:
-----------
project_day : int
current simulation day (index)
Returns:
--------
tfac : float
soil temperature factor [degC]
"""
tsoil = self.met_data["tsoil"][project_day]
if float_gt(tsoil, 0.0):
tfac = 0.0326 + 0.00351 * tsoil ** 1.652 - (tsoil / 41.748) ** 7.19
if float_lt(tfac, 0.0):
tfac = 0.0
else:
# negative number cannot be raised to a fractional power
# number would need to be complex
tfac = 0.0
return tfac
开发者ID:jedrake,项目名称:GDAY,代码行数:26,代码来源:soil_cn_model.py
示例4: epsilon
def epsilon(self, asat, par, daylen, alpha):
""" Canopy scale LUE using method from Sands 1995, 1996.
Sands derived daily canopy LUE from Asat by modelling the light response
of photosysnthesis as a non-rectangular hyperbola with a curvature
(theta) and a quantum efficiency (alpha).
Assumptions of the approach are:
- horizontally uniform canopy
- PAR varies sinusoidally during daylight hours
- extinction coefficient is constant all day
- Asat and incident radiation decline through the canopy following
Beer's Law.
- leaf transmission is assumed to be zero.
* Numerical integration of "g" is simplified to 6 intervals.
Parameters:
----------
asat : float
Light-saturated photosynthetic rate at the top of the canopy
par : float
photosyntetically active radiation (umol m-2 d-1)
daylen : float
length of day (hrs).
theta : float
curvature of photosynthetic light response curve
alpha : float
quantum yield of photosynthesis (mol mol-1)
Returns:
-------
lue : float
integrated light use efficiency over the canopy (umol C umol-1 PAR)
References:
-----------
See assumptions above...
* Sands, P. J. (1995) Australian Journal of Plant Physiology,
22, 601-14.
"""
delta = 0.16666666667 # subintervals scaler, i.e. 6 intervals
h = daylen * const.SECS_IN_HOUR # number of seconds of daylight
if float_gt(asat, 0.0):
# normalised daily irradiance
q = pi * self.params.kext * alpha * par / (2.0 * h * asat)
integral_g = 0.0
for i in xrange(1, 13, 2):
sinx = sin(pi * i / 24.0)
arg1 = sinx
arg2 = 1.0 + q * sinx
arg3 = sqrt((1.0 + q * sinx) ** 2.0 - 4.0 * self.params.theta * q * sinx)
integral_g += arg1 / (arg2 + arg3) * delta
lue = alpha * integral_g * pi
else:
lue = 0.0
return lue
开发者ID:kelvinn,项目名称:GDAY,代码行数:60,代码来源:mate.py
示例5: calc_infiltration
def calc_infiltration(self, rain):
""" Estimate "effective" rain, or infiltration I guess.
Simple assumption that infiltration relates to leaf area
and therefore canopy storage capacity (wetloss). Interception is
likely to be ("more") erroneous if a canopy is subject to frequent daily
rainfall I would suggest.
Parameters:
-------
rain : float
rainfall [mm d-1]
"""
if float_gt(rain, 0.0):
self.fluxes.interception = self.state.lai * self.params.wetloss
self.fluxes.interception = clip(self.fluxes.interception,
min=self.fluxes.interception,
max=rain)
self.fluxes.erain = (rain * self.params.rfmult -
self.fluxes.interception)
else:
self.fluxes.interception = 0.0
self.fluxes.erain = 0.0
开发者ID:jgomezdans,项目名称:GDAY,代码行数:26,代码来源:water_balance_maestra.py
示例6: calc_transpiration
def calc_transpiration(self):
""" units mm/day """
if float_gt(self.fluxes.wue, 0.0):
self.fluxes.transpiration = self.fluxes.gpp_gCm2 / self.fluxes.wue
else:
self.fluxes.transpiration = 0.0
开发者ID:jgomezdans,项目名称:GDAY,代码行数:7,代码来源:water_balance+(Martin+De+Kauwe's+conflicted+copy+2012-07-20).py
示例7: calc_soil_evaporation
def calc_soil_evaporation(self, tavg, net_rad, press, daylen, sw_rad):
""" Use Penman eqn to calculate top soil evaporation flux at the
potential rate.
Soil evaporation is dependent upon soil wetness and plant cover. The net
radiation term is scaled for the canopy cover passed to this func and
the impact of soil wetness is accounted for in the wtfac term. As the
soil dries the evaporation component reduces significantly.
Key assumptions from Ritchie...
* When plant provides shade for the soil surface, evaporation will not
be the same as bare soil evaporation. Wind speed, net radiation and VPD
will all belowered in proportion to the canopy density. Following
Ritchie role ofwind, VPD are assumed to be negligible and are therefore
ignored.
These assumptions are based on work with crops and whether this holds
for tree shading where the height from the soil to the base of the
crown is larger is questionable.
units = (mm/day)
References:
-----------
* Ritchie, 1972, Water Resources Research, 8, 1204-1213.
Parameters:
-----------
tavg : float
average daytime temp [degC]
net_rad : float
net radiation [mj m-2 day-1]
press : float
average daytime pressure [kPa]
Returns:
--------
soil_evap : float
soil evaporation [mm d-1]
"""
P = Penman()
soil_evap = P.calc_evaporation(net_rad, tavg, press)
# Surface radiation is reduced by overstory LAI cover. This empirical
# fit comes from Ritchie (1972) and is formed by a fit between the LAI
# of 5 crops types and the fraction of observed net radiation at the
# surface. Whilst the LAI does cover a large range, nominal 0–6, there
# are only 12 measurements and only three from LAI > 3. So this might
# not hold as well for a forest canopy?
# Ritchie 1972, Water Resources Research, 8, 1204-1213.
if float_gt(self.state.lai, 0.0):
soil_evap *= exp(-0.398 * self.state.lai)
# reduce soil evaporation if top soil is dry
soil_evap *= self.state.wtfac_topsoil
tconv = 60.0 * 60.0 * daylen # seconds to day
return soil_evap * tconv
开发者ID:kelvinn,项目名称:GDAY,代码行数:60,代码来源:water_balance.py
示例8: soil_temp_factor
def soil_temp_factor(self, project_day):
"""Soil-temperature activity factor (A9). Fit to Parton's fig 2a
Parameters:
-----------
project_day : int
current simulation day (index)
Returns:
--------
tfac : float
soil temperature factor [degC]
"""
tsoil = self.met_data['tsoil'][project_day]
if float_gt(tsoil, 0.0):
self.fluxes.tfac_soil_decomp = (0.0326 + 0.00351 * tsoil**1.652 -
(tsoil / 41.748)**7.19)
if float_lt(self.fluxes.tfac_soil_decomp, 0.0):
self.fluxes.tfac_soil_decomp = 0.0
else:
# negative number cannot be raised to a fractional power
# number would need to be complex
self.fluxes.tfac_soil_decomp = 0.0
return self.fluxes.tfac_soil_decomp
开发者ID:npp97,项目名称:GDAY,代码行数:27,代码来源:soil_cn_model.py
示例9: nc_limit
def nc_limit(self, cpool, npool, ncmin, ncmax):
""" Release N to 'Inorgn' pool or fix N from 'Inorgn', in order to keep
the N:C ratio of a litter pool within the range 'ncmin' to 'ncmax'.
Parameters:
-----------
cpool : float
various C pool (state)
npool : float
various N pool (state)
ncmin : float
maximum N:C ratio
ncmax : float
minimum N:C ratio
Returns:
--------
fix/rel : float
amount of N to be added/released from the inorganic pool
"""
nmax = cpool * ncmax
nmin = cpool * ncmin
if float_gt(npool, nmax): #release
rel = npool - nmax
self.fluxes.nlittrelease += rel
return -rel
elif float_lt(npool, nmin): #fix
fix = nmin - npool
self.fluxes.nlittrelease -= fix
return fix
else:
return 0.0
开发者ID:npp97,项目名称:GDAY,代码行数:34,代码来源:soil_cn_model.py
示例10: decay_in_dry_soils
def decay_in_dry_soils(self, decay_rate, decay_rate_dry):
"""Decay rates (e.g. leaf litterfall) can increase in dry soil, adjust
decay param
Parameters:
-----------
decay_rate : float
default model parameter decay rate [tonnes C/ha/day]
decay_rate_dry : float
default model parameter dry deacy rate [tonnes C/ha/day]
Returns:
--------
decay_rate : float
adjusted deacy rate if the soil is dry [tonnes C/ha/day]
"""
# turn into fraction...
smc_root = self.state.pawater_root / self.params.wcapac_root
new_decay_rate = (decay_rate_dry - (decay_rate_dry - decay_rate) *
(smc_root - self.params.watdecaydry) /
(self.params.watdecaywet - self.params.watdecaydry))
if float_lt(new_decay_rate, decay_rate):
new_decay_rate = decay_rate
if float_gt(new_decay_rate, decay_rate_dry):
new_decay_rate = decay_rate_dry
return new_decay_rate
开发者ID:jedrake,项目名称:GDAY,代码行数:31,代码来源:litter_production.py
示例11: inputs_from_structrual_pool
def inputs_from_structrual_pool(self, nsurf, nsoil):
"""structural pool input fluxes
Parameters:
-----------
nsurf : float
N input from surface pool
nsoil : float
N input from soil pool
"""
# constant structural input n:c as per century
if not self.control.strfloat:
# dead plant -> structural
# surface
self.fluxes.nresid[0] = self.fluxes.cresid[0] / self.params.structcn
# soil
self.fluxes.nresid[1] = self.fluxes.cresid[1] / self.params.structcn
# if not enough N for structural, all available N goes to structural
if float_gt(self.fluxes.nresid[0], nsurf):
self.fluxes.nresid[0] = nsurf
if float_gt(self.fluxes.nresid[1], nsoil):
self.fluxes.nresid[1] = nsoil
else:
# structural input n:c is a fraction of metabolic
cwgtsu = (self.fluxes.cresid[0] * self.params.structrat +
self.fluxes.cresid[2])
if float_eq(cwgtsu, 0.0):
self.fluxes.nresid[0] = 0.0
else:
self.fluxes.nresid[0] = (nsurf * self.fluxes.cresid[0] *
self.params.structrat / cwgtsu)
cwgtsl = (self.fluxes.cresid[1] * self.params.structrat +
self.fluxes.cresid[3])
if float_eq(cwgtsl, 0.0):
self.fluxes.nresid[1] = 0.
else:
self.fluxes.nresid[1] = (nsurf * self.fluxes.cresid[1] *
self.params.structrat / cwgtsl)
开发者ID:walkeranthonyp,项目名称:GDAY,代码行数:43,代码来源:soil_cn_model.py
示例12: calculate_top_of_canopy_n
def calculate_top_of_canopy_n(self):
""" Calculate the canopy N at the top of the canopy (g N m-2), N0.
See notes and Chen et al 93, Oecologia, 93,63-69.
"""
if float_gt(self.state.lai, 0.0):
# calculation for canopy N content at the top of the canopy
N0 = self.state.ncontent * self.params.kext / (1.0 - exp(-self.params.kext * self.state.lai))
else:
N0 = 0.0
return N0
开发者ID:kelvinn,项目名称:GDAY,代码行数:11,代码来源:mate.py
示例13: clip
def clip(value, min=None, max=None):
""" clip value btw defined range """
if float_lt(value, min):
value = min
elif float_gt(value, max):
value = max
return value
开发者ID:jgomezdans,项目名称:GDAY,代码行数:7,代码来源:misc_funcs.py
示例14: adjust_cproduction
def adjust_cproduction(self, option):
""" select model?
It seems hybrid is the same as biomass, so check this and remove. I
have set it up so that a call to hybrid just calls biomass
Parameters:
-----------
option : integer
model option
"""
if option == 1 or option == 3:
self.monteith_rescap_model()
elif option == 2 and float_gt(self.params.fwpmax, self.params.fwpmin):
self.biomass_model()
elif option == 3 and float_gt(self.params.fwpmax, self.params.fwpmin):
self.hybrid_model() # same as calling biomass model!
else:
err_msg = "Unknown water bal model (try 1-3): %s\n" % option
raise RuntimeError, err_msg
开发者ID:jgomezdans,项目名称:GDAY,代码行数:21,代码来源:water_balance+(Martin+De+Kauwe's+conflicted+copy+2012-07-20).py
示例15: calc_evaporation
def calc_evaporation(self, vpd, wind, gs, net_rad, tavg, press, canht=None,
ga=None):
"""
Parameters:
-----------
vpd : float
vapour pressure def [kPa]
wind : float
average daytime wind speed [m s-1]
gs : float
stomatal conductance [m s-1]
net_rad : float
net radiation [mj m-2 s-1]
tavg : float
daytime average temperature [degC]
press : float
average daytime pressure [kPa]
Returns:
--------
et : float
evapotranspiration [mm d-1]
"""
# if not read from met file calculate atmospheric pressure from sea lev
if press == None:
press = self.calc_atmos_pressure()
lambdax = self.calc_latent_heat_of_vapourisation(tavg)
gamma = self.calc_pyschrometric_constant(lambdax, press)
slope = self.calc_slope_of_saturation_vapour_pressure_curve(tavg)
rho = self.calc_density_of_air(tavg)
if ga is None:
ga = self.canopy_boundary_layer_conductance(wind, canht)
if float_gt(gs, 0.0):
# decoupling coefficent, Jarvis and McNaughton, 1986
# when omega is close to zero, it is said to be well coupled and
# gs is the dominant controller of water loss (gs<ga).
e = slope / gamma # chg of latent heat relative to sensible heat of air
omega = (e + 1.0) / (e + 1.0 + (ga / gs))
arg1 = ((slope * net_rad ) + (rho * self.cp * vpd * ga))
arg2 = slope + gamma * (1.0 + (ga / gs))
et = (arg1 / arg2) / lambdax
else:
et = 0.0
omega = 0.0
return et, omega
开发者ID:kelvinn,项目名称:GDAY,代码行数:51,代码来源:water_balance.py
示例16: calc_evaporation
def calc_evaporation(self, vpd, wind, gs, net_rad, tavg, press):
"""
Parameters:
-----------
vpd : float
vapour pressure def [kPa]
wind : float
average daytime wind speed [m s-1]
gs : float
stomatal conductance [m s-1]
net_rad : float
net radiation [mj m-2 s-1]
tavg : float
daytime average temperature [degC]
press : float
average daytime pressure [kPa]
Returns:
--------
et : float
evapotranspiration [mm d-1]
"""
# if not read from met file calculate atmospheric pressure from sea lev
if press == None:
press = self.calc_atmos_pressure()
lambdax = self.calc_latent_heat_of_vapourisation(tavg)
gamma = self.calc_pyschrometric_constant(lambdax, press)
slope = self.calc_slope_of_saturation_vapour_pressure_curve(tavg)
rho = self.calc_density_of_air(tavg)
ga = self.calc_atmos_boundary_layer_conductance(wind)
# our model is a big leaf, so canopy conductance, gc = gs
gc = gs
if float_gt(gc, 0.0):
# decoupling coefficent, Jarvis and McNaughton, 1986
e = slope / gamma # chg of latent heat relative to sensible heat of air
omega = (e + 1.0) / (e + 1.0 + (ga / gc))
arg1 = ((slope * net_rad ) + (rho * self.cp * vpd * ga))
arg2 = slope + gamma * (1.0 + ga / gc)
et = (arg1 / arg2) / lambdax
else:
et = 0.0
omega = 0.0
return et
开发者ID:jgomezdans,项目名称:GDAY,代码行数:51,代码来源:water_balance+(Martin+De+Kauwe's+conflicted+copy+2012-07-20).py
示例17: epsilon
def epsilon(self, amax, par, daylen, alpha):
""" Canopy scale LUE using method from Sands 1995, 1996.
Numerical integration of g is simplified to 6 intervals. Leaf
transmission is assumed to be zero.
Parameters:
----------
amax : float
photosynthetic rate at the top of the canopy
par : float
incident photosyntetically active radiation
daylen : float
length of day in hours.
theta : float
curvature of photosynthetic light response curve
alpha : float
quantum yield of photosynthesis (mol mol-1)
Returns:
-------
lue : float
integrated light use efficiency over the canopy
References:
-----------
See assumptions above...
* Sands, P. J. (1995) Australian Journal of Plant Physiology,
22, 601-14.
* LUE stuff comes from Sands 1996
"""
delta = 0.16666666667 # subintervals scaler, i.e. 6 intervals
h = daylen * const.HRS_TO_SECS
theta = self.params.theta # local var
if float_gt(amax, 0.0):
q = pi * self.params.kext * alpha * par / (2.0 * h * amax)
integral = 0.0
for i in xrange(1, 13, 2):
sinx = sin(pi * i / 24.)
arg1 = sinx
arg2 = 1.0 + q * sinx
arg3 = sqrt((1.0 + q * sinx)**2.0 - 4.0 * theta * q * sinx)
integral += arg1 / (arg2 + arg3) * delta
lue = alpha * integral * pi
else:
lue = 0.0
return lue
开发者ID:jgomezdans,项目名称:GDAY,代码行数:50,代码来源:mate.py
示例18: calc_wue
def calc_wue(self, vpd, ca, amb_co2):
"""water use efficiency
Not sure of units conversions here, have to ask BM
Parameters:
-----------
vpd : float
average daily vpd [kPa]
ca : float
atmospheric co2, depending on flag set in param file this will be
ambient or elevated. [umol mol-1]
"""
if self.control.wue_model == 0:
# Gday original implementation
# (gC / kg H20)
if float_gt(vpd, 0.0):
# WUE Power law dependence on co2, Pepper et al 2005.
co2_ratio = (ca / amb_co2)
co2_adjustment = co2_ratio**self.params.co2_effect_on_wue
# wue inversely proportional to daily mean vpd
self.fluxes.wue = self.params.wue0 * co2_adjustment / vpd
else:
self.fluxes.wue = 0.0
elif self.control.wue_model == 1 and self.control.assim_model == 7:
conv = const.MOL_C_TO_GRAMS_C / const.MOL_WATER_TO_GRAMS_WATER
self.fluxes.wue = (conv * 1000.0 * (ca * const.UMOL_TO_MOL *
(1.0 - self.fluxes.cica_avg) /
(1.6 * vpd / 101.0)))
#if self.fluxes.wue > 20.0: self.fluxes.wue = 20.0 # FIX THIS!!!
# what is this? ask BM
elif self.control.wue_model == 2:
self.fluxes.wue = (self.params.wue0 * 0.27273 / vpd *
ca / amb_co2)
elif self.control.wue_model == 3 :
if float_eq(self.fluxes.transpiration, 0.0):
self.fluxes.wue = 0.0
else:
self.fluxes.wue = (self.fluxes.gpp_gCm2 /
self.fluxes.transpiration)
else:
raise AttributeError('Unknown WUE calculation option')
开发者ID:jgomezdans,项目名称:GDAY,代码行数:46,代码来源:water_balance+(Martin+De+Kauwe's+conflicted+copy+2012-07-20).py
示例19: epsilon
def epsilon(self, amax, par, daylen, alpha):
""" Canopy scale LUE using method from Sands 1995, 1996.
Parameters:
----------
amax : float
photosynthetic rate at the top of the canopy
par : float
incident photosyntetically active radiation
daylen : float
length of day in hours.
theta : float
curvature of photosynthetic light response curve
alpha : float
quantum yield of photosynthesis (mol mol-1)
Returns:
-------
lue : float
integrated light use efficiency over the canopy
References:
-----------
See assumptions above...
* Sands, P. J. (1995) Australian Journal of Plant Physiology, 22, 601-14.
"""
if float_gt(amax, 0.0):
q = (math.pi * self.params.kext * alpha * par /
(2.0 * daylen * const.HRS_TO_SECS * amax))
# check sands but shouldn't it be 2 * q * sin x on the top?
f = (lambda x: x / (1.0 + q * x + math.sqrt((1.0 + q * x)**2.0 -
4.0 * self.params.theta * q * x)))
g = [f(math.sin(math.pi * i / 24.)) for i in xrange(1, 13, 2)]
#Trapezoidal rule - seems more accurate
gg = 0.16666666667 * sum(g)
lue = alpha * gg * math.pi
else:
lue = 0.0
return lue
开发者ID:jgomezdans,项目名称:GDAY,代码行数:45,代码来源:x.py
示例20: day_length
def day_length(date, latitude):
""" Figure out number of sunlight hours, (hours day-1)
Routine from sdgvm. date is a python object, see datetime library for
more info
Parameters:
-----------
date : date format string
date object, yr/month/day
latitude : float
latitude [degrees]
Returns:
--------
dayl : float
daylength [hrs]
"""
conv = math.pi / 180.0
# day of year 1-365/366
doy = int(date.strftime('%j'))
# Total number of days in year
if calendar.isleap(date.year):
yr_days = 366.
else:
yr_days = 365.
solar_declin = -23.4 * math.cos(conv * yr_days * (doy + 10.0) / yr_days)
temx = -math.tan(latitude * conv) * math.tan(solar_declin * conv)
if float_lt(math.fabs(temx), 1.0):
has = math.acos(temx) / conv
dayl = 2.0 * has / 15.0
elif float_gt(temx, 0.0):
dayl = 0.0
else:
dayl = 24.0
return dayl
开发者ID:jgomezdans,项目名称:GDAY,代码行数:42,代码来源:misc_funcs.py
注:本文中的utilities.float_gt函数示例由纯净天空整理自Github/MSDocs等源码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。 |
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