本文整理汇总了Python中tests.shared.getEmptyDeck函数的典型用法代码示例。如果您正苦于以下问题:Python getEmptyDeck函数的具体用法?Python getEmptyDeck怎么用?Python getEmptyDeck使用的例子?那么恭喜您, 这里精选的函数代码示例或许可以为您提供帮助。
在下文中一共展示了getEmptyDeck函数的20个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于我们的系统推荐出更棒的Python代码示例。
示例1: setup_basic
def setup_basic():
global deck1, deck2, client, server
deck1 = getEmptyDeck()
# add a note to deck 1
f = deck1.newNote()
f["Front"] = u"foo"
f["Back"] = u"bar"
f.tags = [u"foo"]
deck1.addNote(f)
# answer it
deck1.reset()
deck1.sched.answerCard(deck1.sched.getCard(), 4)
# repeat for deck2
deck2 = getEmptyDeck(server=True)
f = deck2.newNote()
f["Front"] = u"bar"
f["Back"] = u"bar"
f.tags = [u"bar"]
deck2.addNote(f)
deck2.reset()
deck2.sched.answerCard(deck2.sched.getCard(), 4)
# start with same schema and sync time
deck1.scm = deck2.scm = 0
# and same mod time, so sync does nothing
t = intTime(1000)
deck1.save(mod=t)
deck2.save(mod=t)
server = LocalServer(deck2)
client = Syncer(deck1, server)
开发者ID:kieranclancy,项目名称:libanki,代码行数:29,代码来源:test_sync.py
示例2: test_counts
def test_counts():
d = getEmptyDeck()
# add a second group
assert d.groupId("new group") == 2
# for each card type
for type in range(3):
# and each of the groups
for gid in (1,2):
# create a new fact
f = d.newFact()
f['Front'] = u"one"
d.addFact(f)
c = f.cards()[0]
# set type/gid
c.type = type
c.queue = type
c.gid = gid
c.due = 0
c.flush()
d.reset()
# with the default settings, there's no count limit
assert d.sched.counts() == (2,2,2)
# check limit to one group
d.qconf['groups'] = [1]
d.reset()
assert d.sched.counts() == (1,1,1)
# we don't need to build the queue to get the counts
assert d.sched.allCounts() == (2,2,2)
assert d.sched.selCounts() == (1,1,1)
assert d.sched.allCounts() == (2,2,2)
开发者ID:ChYi,项目名称:libanki,代码行数:30,代码来源:test_sched.py
示例3: test_remove
def test_remove():
deck = getEmptyDeck()
# can't remove the default deck
assertException(AssertionError, lambda: deck.decks.rem(1))
# create a new deck, and add a note/card to it
g1 = deck.decks.id("g1")
f = deck.newNote()
f['Front'] = u"1"
f.model()['did'] = g1
deck.addNote(f)
c = f.cards()[0]
assert c.did == g1
# by default deleting the deck leaves the cards with an invalid did
assert deck.cardCount() == 1
deck.decks.rem(g1)
assert deck.cardCount() == 1
c.load()
assert c.did == g1
# but if we try to get it, we get the default
assert deck.decks.name(c.did) == "[no deck]"
# let's create another deck and explicitly set the card to it
g2 = deck.decks.id("g2")
c.did = g2; c.flush()
# this time we'll delete the card/note too
deck.decks.rem(g2, cardsToo=True)
assert deck.cardCount() == 0
assert deck.noteCount() == 0
开发者ID:greedychipmunk,项目名称:libanki,代码行数:27,代码来源:test_decks.py
示例4: test_delete
def test_delete():
deck = getEmptyDeck()
f = deck.newFact()
f['Front'] = u'1'
f['Back'] = u'2'
deck.addFact(f)
cid = f.cards()[0].id
deck.reset()
deck.sched.answerCard(deck.sched.getCard(), 2)
assert deck.db.scalar("select count() from revlog") == 1
deck.delCards([cid])
assert deck.cardCount() == 0
assert deck.factCount() == 0
assert deck.db.scalar("select count() from facts") == 0
assert deck.db.scalar("select count() from cards") == 0
assert deck.db.scalar("select count() from fsums") == 0
assert deck.db.scalar("select count() from revlog") == 0
assert deck.db.scalar("select count() from graves") == 0
# add the fact back
deck.addFact(f)
assert deck.cardCount() == 1
cid = f.cards()[0].id
# delete again, this time with syncing enabled
deck.syncName = "abc"
deck.lastSync = time.time()
deck.delCards([cid])
assert deck.cardCount() == 0
assert deck.factCount() == 0
assert deck.db.scalar("select count() from graves") != 0
开发者ID:bhutley,项目名称:libanki,代码行数:29,代码来源:test_cards.py
示例5: test_fieldChecksum
def test_fieldChecksum():
deck = getEmptyDeck()
f = deck.newFact()
f['Front'] = u"new"; f['Back'] = u"new2"
deck.addFact(f)
assert deck.db.scalar(
"select csum from fsums") == int("22af645d", 16)
# empty field should have no checksum
f['Front'] = u""
f.flush()
assert deck.db.scalar(
"select count() from fsums") == 0
# changing the val should change the checksum
f['Front'] = u"newx"
f.flush()
assert deck.db.scalar(
"select csum from fsums") == int("4b0e5a4c", 16)
# turning off unique and modifying the fact should delete the sum
m = f.model()
m.fields[0]['uniq'] = False
m.flush()
f.flush()
assert deck.db.scalar(
"select count() from fsums") == 0
# and turning on both should ensure two checksums generated
m.fields[0]['uniq'] = True
m.fields[1]['uniq'] = True
m.flush()
f.flush()
assert deck.db.scalar(
"select count() from fsums") == 2
开发者ID:bhutley,项目名称:libanki,代码行数:31,代码来源:test_deck.py
示例6: test_genrem
def test_genrem():
d = getEmptyDeck()
f = d.newNote()
f['Front'] = u'1'
f['Back'] = u''
d.addNote(f)
assert len(f.cards()) == 1
m = d.models.current()
mm = d.models
# adding a new template should automatically create cards
t = mm.newTemplate("rev")
t['qfmt'] = '{{Front}}'
t['afmt'] = ""
mm.addTemplate(m, t)
mm.save(m, templates=True)
assert len(f.cards()) == 2
# if the template is changed to remove cards, they'll be removed
t['qfmt'] = "{{Back}}"
mm.save(m, templates=True)
d.remCards(d.emptyCids())
assert len(f.cards()) == 1
# if we add to the note, a card should be automatically generated
f.load()
f['Back'] = "1"
f.flush()
assert len(f.cards()) == 2
开发者ID:ACEfanatic02,项目名称:libanki,代码行数:26,代码来源:test_cards.py
示例7: test_gendeck
def test_gendeck():
d = getEmptyDeck()
cloze = d.models.byName("Cloze")
d.models.setCurrent(cloze)
f = d.newNote()
f['Text'] = u'{{c1::one}}'
d.addNote(f)
assert d.cardCount() == 1
assert f.cards()[0].did == 1
# set the model to a new default deck
newId = d.decks.id("new")
cloze['did'] = newId
d.models.save(cloze)
# a newly generated card should share the first card's deck
f['Text'] += u'{{c2::two}}'
f.flush()
assert f.cards()[1].did == 1
# and same with multiple cards
f['Text'] += u'{{c3::three}}'
f.flush()
assert f.cards()[2].did == 1
# if one of the cards is in a different deck, it should revert to the
# model default
c = f.cards()[1]
c.did = newId
c.flush()
f['Text'] += u'{{c4::four}}'
f.flush()
assert f.cards()[3].did == newId
开发者ID:ACEfanatic02,项目名称:libanki,代码行数:29,代码来源:test_cards.py
示例8: test_ordcycle
def test_ordcycle():
d = getEmptyDeck()
# add two more templates and set second active
m = d.models.current()
mm = d.models
t = mm.newTemplate("Reverse")
t["qfmt"] = "{{Back}}"
t["afmt"] = "{{Front}}"
mm.addTemplate(m, t)
t = mm.newTemplate("f2")
t["qfmt"] = "{{Front}}"
t["afmt"] = "{{Back}}"
mm.addTemplate(m, t)
mm.save(m)
# create a new note; it should have 3 cards
f = d.newNote()
f["Front"] = "1"
f["Back"] = "1"
d.addNote(f)
assert d.cardCount() == 3
d.reset()
# ordinals should arrive in order
assert d.sched.getCard().ord == 0
assert d.sched.getCard().ord == 1
assert d.sched.getCard().ord == 2
开发者ID:harcharansidhu,项目名称:anki,代码行数:25,代码来源:test_sched.py
示例9: test_op
def test_op():
d = getEmptyDeck()
# should have no undo by default
assert not d.undoName()
# let's adjust a study option
d.save("studyopts")
d.conf['abc'] = 5
# it should be listed as undoable
assert d.undoName() == "studyopts"
# with about 5 minutes until it's clobbered
assert time.time() - d._lastSave < 1
# undoing should restore the old value
d.undo()
assert not d.undoName()
assert 'abc' not in d.conf
# an (auto)save will clear the undo
d.save("foo")
assert d.undoName() == "foo"
d.save()
assert not d.undoName()
# and a review will, too
d.save("add")
f = d.newNote()
f['Front'] = u"one"
d.addNote(f)
d.reset()
assert d.undoName() == "add"
c = d.sched.getCard()
d.sched.answerCard(c, 2)
assert d.undoName() == "Review"
开发者ID:aaronharsh,项目名称:libanki,代码行数:30,代码来源:test_undo.py
示例10: test_templates
def test_templates():
d = getEmptyDeck()
m = d.currentModel()
m.templates[1]['actv'] = True
m.flush()
f = d.newFact()
f['Front'] = u'1'
f['Back'] = u'2'
d.addFact(f)
assert d.cardCount() == 2
(c, c2) = f.cards()
# first card should have first ord
assert c.ord == 0
assert c2.ord == 1
# switch templates
m.moveTemplate(c.template(), 1)
c.load(); c2.load()
assert c.ord == 1
assert c2.ord == 0
# removing a template should delete its cards
m.delTemplate(m.templates[0])
assert d.cardCount() == 1
# and should have updated the other cards' ordinals
c = f.cards()[0]
assert c.ord == 0
stripHTML(c.q()) == "2"
开发者ID:ChYi,项目名称:libanki,代码行数:26,代码来源:test_models.py
示例11: test_genrem
def test_genrem():
d = getEmptyDeck()
f = d.newNote()
f['Front'] = u'1'
f['Back'] = u''
d.addNote(f)
assert len(f.cards()) == 1
m = d.models.current()
mm = d.models
# adding a new template should automatically create cards
t = mm.newTemplate("rev")
t['qfmt'] = '{{Front}}'
t['afmt'] = ""
mm.addTemplate(m, t)
mm.save(m, templates=True)
assert len(f.cards()) == 2
# if the template is changed to remove cards, they'll be removed
t['qfmt'] = "{{Back}}"
mm.save(m, templates=True)
assert len(f.cards()) == 1
# if we add to the note, a card should be automatically generated
f.load()
f['Back'] = "1"
f.flush()
assert len(f.cards()) == 2
# deleteion calls a hook to let the user abort the delete. let's abort it:
def abort(val, *args):
return False
addHook("remEmptyCards", abort)
f['Back'] = ""
f.flush()
assert len(f.cards()) == 2
开发者ID:aaronharsh,项目名称:libanki,代码行数:32,代码来源:test_cards.py
示例12: test_findReplace
def test_findReplace():
deck = getEmptyDeck()
f = deck.newFact()
f['Front'] = u'foo'
f['Back'] = u'bar'
deck.addFact(f)
f2 = deck.newFact()
f2['Front'] = u'baz'
f2['Back'] = u'foo'
deck.addFact(f2)
fids = [f.id, f2.id]
# should do nothing
assert deck.findReplace(fids, "abc", "123") == 0
# global replace
assert deck.findReplace(fids, "foo", "qux") == 2
f.load(); assert f['Front'] == "qux"
f2.load(); assert f2['Back'] == "qux"
# single field replace
assert deck.findReplace(fids, "qux", "foo", field="Front") == 1
f.load(); assert f['Front'] == "foo"
f2.load(); assert f2['Back'] == "qux"
# regex replace
assert deck.findReplace(fids, "B.r", "reg") == 0
f.load(); assert f['Back'] != "reg"
assert deck.findReplace(fids, "B.r", "reg", regex=True) == 1
f.load(); assert f['Back'] == "reg"
开发者ID:ChYi,项目名称:libanki,代码行数:26,代码来源:test_find.py
示例13: test_findDupes
def test_findDupes():
deck = getEmptyDeck()
f = deck.newNote()
f['Front'] = u'foo'
f['Back'] = u'bar'
deck.addNote(f)
f2 = deck.newNote()
f2['Front'] = u'baz'
f2['Back'] = u'bar'
deck.addNote(f2)
f3 = deck.newNote()
f3['Front'] = u'quux'
f3['Back'] = u'bar'
deck.addNote(f3)
f4 = deck.newNote()
f4['Front'] = u'quuux'
f4['Back'] = u'nope'
deck.addNote(f4)
r = deck.findDupes("Back")
assert r[0][0] == "bar"
assert len(r[0][1]) == 3
# valid search
r = deck.findDupes("Back", "bar")
assert r[0][0] == "bar"
assert len(r[0][1]) == 3
# excludes everything
r = deck.findDupes("Back", "invalid")
assert not r
# front isn't dupe
assert deck.findDupes("Front") == []
开发者ID:ACEfanatic02,项目名称:anki,代码行数:30,代码来源:test_find.py
示例14: test_basic
def test_basic():
deck = getEmptyDeck()
# we start with a standard deck
assert len(deck.decks.decks) == 1
# it should have an id of 1
assert deck.decks.name(1)
# create a new deck
parentId = deck.decks.id("new deck")
assert parentId
assert len(deck.decks.decks) == 2
# should get the same id
assert deck.decks.id("new deck") == parentId
# we start with the default deck selected
assert deck.decks.selected() == 1
assert deck.decks.active() == [1]
# we can select a different deck
deck.decks.select(parentId)
assert deck.decks.selected() == parentId
assert deck.decks.active() == [parentId]
# let's create a child
childId = deck.decks.id("new deck::child")
# it should have been added to the active list
assert deck.decks.selected() == parentId
assert deck.decks.active() == [parentId, childId]
# we can select the child individually too
deck.decks.select(childId)
assert deck.decks.selected() == childId
assert deck.decks.active() == [childId]
开发者ID:shantipants,项目名称:libanki,代码行数:28,代码来源:test_decks.py
示例15: test_overdue_lapse
def test_overdue_lapse():
d = getEmptyDeck()
# add a note
f = d.newNote()
f['Front'] = u"one"
d.addNote(f)
# simulate a review that was lapsed and is now due for its normal review
c = f.cards()[0]
c.type = 2
c.queue = 1
c.due = -1
c.odue = -1
c.factor = 2500
c.left = 2
c.ivl = 0
c.flush()
d.sched._clearOverdue = False
# checkpoint
d.save()
d.sched.reset()
assert d.sched.counts() == (0, 2, 0)
c = d.sched.getCard()
d.sched.answerCard(c, 3)
# it should be due tomorrow
assert c.due == d.sched.today + 1
# revert to before
d.rollback()
d.sched._clearOverdue = True
# with the default settings, the overdue card should be removed from the
# learning queue
d.sched.reset()
assert d.sched.counts() == (0, 0, 1)
开发者ID:jakeprobst,项目名称:libanki,代码行数:32,代码来源:test_sched.py
示例16: test_learn_collapsed
def test_learn_collapsed():
d = getEmptyDeck()
# add 2 notes
f = d.newNote()
f['Front'] = u"1"
f = d.addNote(f)
f = d.newNote()
f['Front'] = u"2"
f = d.addNote(f)
# set as a learn card and rebuild queues
d.db.execute("update cards set queue=0, type=0")
d.reset()
# should get '1' first
c = d.sched.getCard()
assert c.q().endswith("1")
# pass it so it's due in 10 minutes
d.sched.answerCard(c, 2)
# get the other card
c = d.sched.getCard()
assert c.q().endswith("2")
# fail it so it's due in 1 minute
d.sched.answerCard(c, 1)
# we shouldn't get the same card again
c = d.sched.getCard()
assert not c.q().endswith("2")
开发者ID:jakeprobst,项目名称:libanki,代码行数:25,代码来源:test_sched.py
示例17: test_anki2_updates
def test_anki2_updates():
# create a new empty deck
dst = getEmptyDeck()
tmp = getUpgradeDeckPath("update1.apkg")
imp = AnkiPackageImporter(dst, tmp)
imp.run()
assert imp.dupes == 0
assert imp.added == 1
assert imp.updated == 0
# importing again should be idempotent
imp = AnkiPackageImporter(dst, tmp)
imp.run()
assert imp.dupes == 1
assert imp.added == 0
assert imp.updated == 0
# importing a newer note should update
assert dst.noteCount() == 1
assert dst.db.scalar("select flds from notes").startswith("hello")
tmp = getUpgradeDeckPath("update2.apkg")
imp = AnkiPackageImporter(dst, tmp)
imp.run()
assert imp.dupes == 1
assert imp.added == 0
assert imp.updated == 1
assert dst.noteCount() == 1
assert dst.db.scalar("select flds from notes").startswith("goodbye")
开发者ID:BigDataNerd,项目名称:anki,代码行数:26,代码来源:test_importing.py
示例18: test_timing
def test_timing():
d = getEmptyDeck()
# add a few review cards, due today
for i in range(5):
f = d.newNote()
f['Front'] = "num"+str(i)
d.addNote(f)
c = f.cards()[0]
c.type = 2
c.queue = 2
c.due = 0
c.flush()
# fail the first one
d.reset()
c = d.sched.getCard()
# set a a fail delay of 1 second so we don't have to wait
d.sched._cardConf(c)['lapse']['delays'][0] = 1/60.0
d.sched.answerCard(c, 1)
# the next card should be another review
c = d.sched.getCard()
assert c.queue == 2
# but if we wait for a second, the failed card should come back
time.sleep(1)
c = d.sched.getCard()
assert c.queue == 1
开发者ID:grantcox,项目名称:libanki,代码行数:25,代码来源:test_sched.py
示例19: test_suspend
def test_suspend():
d = getEmptyDeck()
f = d.newNote()
f['Front'] = u"one"
d.addNote(f)
c = f.cards()[0]
# suspending
d.reset()
assert d.sched.getCard()
d.sched.suspendCards([c.id])
d.reset()
assert not d.sched.getCard()
# unsuspending
d.sched.unsuspendCards([c.id])
d.reset()
assert d.sched.getCard()
# should cope with rev cards being relearnt
c.due = 0; c.ivl = 100; c.type = 2; c.queue = 2; c.flush()
d.reset()
c = d.sched.getCard()
d.sched.answerCard(c, 1)
assert c.due >= time.time()
assert c.queue == 1
assert c.type == 2
d.sched.suspendCards([c.id])
d.sched.unsuspendCards([c.id])
c.load()
assert c.queue == 2
assert c.type == 2
assert c.due == 1
开发者ID:grantcox,项目名称:libanki,代码行数:30,代码来源:test_sched.py
示例20: test_newLimits
def test_newLimits():
d = getEmptyDeck()
# add some notes
g2 = d.decks.id("Default::foo")
for i in range(30):
f = d.newNote()
f['Front'] = str(i)
if i > 4:
f.did = g2
d.addNote(f)
# give the child deck a different configuration
c2 = d.decks.confId("new conf")
d.decks.setConf(d.decks.get(g2), c2)
d.reset()
# both confs have defaulted to a limit of 20
assert d.sched.newCount == 20
# first card we get comes from parent
c = d.sched.getCard()
assert c.did == 1
# limit the parent to 10 cards, meaning we get 10 in total
conf1 = d.decks.confForDid(1)
conf1['new']['perDay'] = 10
d.reset()
assert d.sched.newCount == 10
# if we limit child to 4, we should get 9
conf2 = d.decks.confForDid(g2)
conf2['new']['perDay'] = 4
d.reset()
assert d.sched.newCount == 9
开发者ID:grantcox,项目名称:libanki,代码行数:29,代码来源:test_sched.py
注:本文中的tests.shared.getEmptyDeck函数示例由纯净天空整理自Github/MSDocs等源码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。 |
请发表评论