本文整理汇总了Python中tensorflow.python.ops.math_ops.cumprod函数的典型用法代码示例。如果您正苦于以下问题:Python cumprod函数的具体用法?Python cumprod怎么用?Python cumprod使用的例子?那么恭喜您, 这里精选的函数代码示例或许可以为您提供帮助。
在下文中一共展示了cumprod函数的14个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于我们的系统推荐出更棒的Python代码示例。
示例1: testAxisType
def testAxisType(self):
for dtype in self.valid_dtypes:
x = np.arange(1, 6).reshape([5]).astype(dtype)
for axis_dtype in self.axis_dtypes():
with self.cached_session(), self.test_scope():
p = array_ops.placeholder(x.dtype)
axis = constant_op.constant(0, axis_dtype)
math_ops.cumprod(x, axis).eval(feed_dict={p: x})
开发者ID:Ajaycs99,项目名称:tensorflow,代码行数:8,代码来源:scan_ops_test.py
示例2: testAxisType
def testAxisType(self):
for dtype in self.valid_dtypes:
x = np.arange(1, 6).reshape([5]).astype(dtype)
for axis_dtype in [dtypes.int64, dtypes.int32]:
with self.cached_session(use_gpu=True):
axis = constant_op.constant(0, axis_dtype)
tf_out = math_ops.cumprod(x, axis).eval()
开发者ID:abhinav-upadhyay,项目名称:tensorflow,代码行数:7,代码来源:scan_ops_test.py
示例3: _compareGradient
def _compareGradient(self, shape, axis, exclusive, reverse):
x = np.arange(1, 9).reshape(shape).astype(np.float64)
with self.cached_session(use_gpu=True):
t = ops.convert_to_tensor(x)
result = math_ops.cumprod(t, axis, exclusive, reverse)
jacob_t, jacob_n = gradient_checker.compute_gradient(
t, shape, result, shape, x_init_value=x, delta=1)
self.assertAllClose(jacob_t, jacob_n, rtol=1e-8, atol=1e-8)
开发者ID:abhinav-upadhyay,项目名称:tensorflow,代码行数:8,代码来源:scan_ops_test.py
示例4: _compare
def _compare(self, x, axis, exclusive, reverse):
np_out = handle_options(np.cumprod, x, axis, exclusive, reverse)
with self.cached_session(), self.test_scope():
p = array_ops.placeholder(x.dtype)
prod = math_ops.cumprod(p, axis, exclusive, reverse)
tf_out = prod.eval(feed_dict={p: x})
self.assertAllClose(np_out, tf_out)
开发者ID:Ajaycs99,项目名称:tensorflow,代码行数:8,代码来源:scan_ops_test.py
示例5: _ProdGrad
def _ProdGrad(op, grad):
"""Gradient for Prod."""
# The gradient can be expressed by dividing the product by each entry of the
# input tensor, but this approach can't deal with zeros in the input.
# Here, we avoid this problem by composing the output as a product of two
# cumprod operations.
input_shape = array_ops.shape(op.inputs[0])
# Reshape reduction indices for the case where the parameter is a scalar
reduction_indices = array_ops.reshape(op.inputs[1], [-1])
# Expand grad to full input shape
output_shape_kept_dims = math_ops.reduced_shape(input_shape, op.inputs[1])
tile_scaling = _safe_shape_div(input_shape, output_shape_kept_dims)
grad = array_ops.reshape(grad, output_shape_kept_dims)
grad = array_ops.tile(grad, tile_scaling)
# Pack all reduced dimensions into a single one, so we can perform the
# cumprod ops. If the reduction dims list is empty, it defaults to float32,
# so we need to cast here. We put all the shape-related ops on CPU to avoid
# copying back and forth, and since listdiff is CPU only.
with ops.device("/cpu:0"):
rank = array_ops.rank(op.inputs[0])
reduction_indices = (reduction_indices + rank) % rank
reduced = math_ops.cast(reduction_indices, dtypes.int32)
idx = math_ops.range(0, rank)
other, _ = array_ops.setdiff1d(idx, reduced)
perm = array_ops.concat([reduced, other], 0)
reduced_num = math_ops.reduce_prod(array_ops.gather(input_shape, reduced))
other_num = math_ops.reduce_prod(array_ops.gather(input_shape, other))
permuted = array_ops.transpose(op.inputs[0], perm)
permuted_shape = array_ops.shape(permuted)
reshaped = array_ops.reshape(permuted, (reduced_num, other_num))
# Calculate product, leaving out the current entry
left = math_ops.cumprod(reshaped, axis=0, exclusive=True)
right = math_ops.cumprod(reshaped, axis=0, exclusive=True, reverse=True)
# For complex inputs, the gradient is in the conjugate direction.
y = array_ops.reshape(math_ops.conj(left) * math_ops.conj(right),
permuted_shape)
# Invert the transpose and reshape operations.
# Make sure to set the statically known shape information through a reshape.
out = grad * array_ops.transpose(y, array_ops.invert_permutation(perm))
return array_ops.reshape(out, input_shape), None
开发者ID:AnishShah,项目名称:tensorflow,代码行数:45,代码来源:math_grad.py
示例6: _CumprodGrad
def _CumprodGrad(op, grad):
x = op.inputs[0]
axis = op.inputs[1]
reverse = op.get_attr("reverse")
# TODO This fails when x contains 0 and should be fixed
prod = math_ops.cumprod(x, axis=axis, reverse=reverse)
out = math_ops.cumsum(prod * grad, axis=axis, reverse=(not reverse))
return [out / x, None]
开发者ID:LaGuardia,项目名称:tensorflow,代码行数:9,代码来源:math_grad.py
示例7: _ProdGrad
def _ProdGrad(op, grad):
"""Gradient for Prod."""
# The gradient can be expressed by dividing the product by each entry of the
# input tensor, but this approach can't deal with zeros in the input.
# Here, we avoid this problem by composing the output as a product of two
# cumprod operations.
input_shape = array_ops.shape(op.inputs[0])
# Expand grad to full input shape
output_shape_kept_dims = math_ops.reduced_shape(input_shape, op.inputs[1])
tile_scaling = _safe_shape_div(input_shape, output_shape_kept_dims)
grad = array_ops.reshape(grad, output_shape_kept_dims)
grad = array_ops.tile(grad, tile_scaling)
# Pack all reduced dimensions into a single one, so we can perform the
# cumprod ops. If the reduction dims list is empty, it defaults to float32,
# so we need to cast here.
reduced = math_ops.cast(op.inputs[1], dtypes.int32)
idx = math_ops.range(0, array_ops.rank(op.inputs[0]))
other, _ = array_ops.listdiff(idx, reduced)
perm = array_ops.concat(0, [reduced, other])
reduced_num = math_ops.reduce_prod(array_ops.gather(input_shape, reduced))
other_num = math_ops.reduce_prod(array_ops.gather(input_shape, other))
permuted = array_ops.transpose(op.inputs[0], perm)
permuted_shape = array_ops.shape(permuted)
reshaped = array_ops.reshape(permuted, (reduced_num, other_num))
# Calculate product, leaving out the current entry
left = math_ops.cumprod(reshaped, axis=0, exclusive=True)
right = math_ops.cumprod(reshaped, axis=0, exclusive=True, reverse=True)
y = array_ops.reshape(left * right, permuted_shape)
# Invert the transpose and reshape operations.
# Make sure to set the statically known shape information through a reshape.
out = grad * array_ops.transpose(y, array_ops.invert_permutation(perm))
return array_ops.reshape(out, input_shape), None
开发者ID:JamesFysh,项目名称:tensorflow,代码行数:37,代码来源:math_grad.py
示例8: test_safe_cumprod
def test_safe_cumprod(self):
# Create some random test input
test_input = np.random.uniform(size=(10, 20))
for axis in [0, 1]:
for exclusive in [True, False]:
with self.test_session():
# Compute cumprod with regular tf.cumprod
cumprod_output = math_ops.cumprod(
test_input, axis=axis, exclusive=exclusive).eval()
# Compute cumprod with safe_cumprod
safe_cumprod_output = wrapper.safe_cumprod(
test_input, axis=axis, exclusive=exclusive).eval()
for x, y in zip(cumprod_output.shape, safe_cumprod_output.shape):
self.assertEqual(x, y)
for x, y in zip(cumprod_output.flatten(),
safe_cumprod_output.flatten()):
# Use assertAlmostEqual for the actual values due to floating point
self.assertAlmostEqual(x, y, places=5)
开发者ID:AutumnQYN,项目名称:tensorflow,代码行数:19,代码来源:attention_wrapper_test.py
示例9: testInvalidAxis
def testInvalidAxis(self):
x = np.arange(0, 10).reshape([2, 5]).astype(np.float32)
input_tensor = ops.convert_to_tensor(x)
with self.session(use_gpu=True):
with self.assertRaisesWithPredicateMatch(
errors_impl.InvalidArgumentError,
lambda e: "Expected scan axis in the range [-2, 2)" in str(e)):
math_ops.cumprod(input_tensor, -3).eval()
with self.assertRaisesWithPredicateMatch(
errors_impl.InvalidArgumentError,
lambda e: "Expected scan axis in the range [-2, 2)" in str(e)):
math_ops.cumprod(input_tensor, 2).eval()
with self.assertRaisesWithPredicateMatch(
errors_impl.InvalidArgumentError,
lambda e: "axis must be a scalar" in str(e)):
math_ops.cumprod(input_tensor, [0]).eval()
开发者ID:abhinav-upadhyay,项目名称:tensorflow,代码行数:16,代码来源:scan_ops_test.py
示例10: _compare
def _compare(self, x, axis, exclusive, reverse):
np_out = handle_options(np.cumprod, x, axis, exclusive, reverse)
with self.cached_session(use_gpu=True):
tf_out = math_ops.cumprod(x, axis, exclusive, reverse).eval()
self.assertAllClose(np_out, tf_out)
开发者ID:abhinav-upadhyay,项目名称:tensorflow,代码行数:6,代码来源:scan_ops_test.py
示例11: loop_fn
def loop_fn(i):
a = array_ops.gather(x, i)
return math_ops.cumprod(
a, axis=axis, exclusive=exclusive, reverse=reverse)
开发者ID:aritratony,项目名称:tensorflow,代码行数:4,代码来源:math_test.py
示例12: monotonic_attention
def monotonic_attention(p_choose_i, previous_attention, mode):
"""Compute monotonic attention distribution from choosing probabilities.
Monotonic attention implies that the input sequence is processed in an
explicitly left-to-right manner when generating the output sequence. In
addition, once an input sequence element is attended to at a given output
timestep, elements occurring before it cannot be attended to at subsequent
output timesteps. This function generates attention distributions according
to these assumptions. For more information, see ``Online and Linear-Time
Attention by Enforcing Monotonic Alignments''.
Args:
p_choose_i: Probability of choosing input sequence/memory element i. Should
be of shape (batch_size, input_sequence_length), and should all be in the
range [0, 1].
previous_attention: The attention distribution from the previous output
timestep. Should be of shape (batch_size, input_sequence_length). For
the first output timestep, preevious_attention[n] should be [1, 0, 0, ...,
0] for all n in [0, ... batch_size - 1].
mode: How to compute the attention distribution. Must be one of
'recursive', 'parallel', or 'hard'.
* 'recursive' uses tf.scan to recursively compute the distribution.
This is slowest but is exact, general, and does not suffer from
numerical instabilities.
* 'parallel' uses parallelized cumulative-sum and cumulative-product
operations to compute a closed-form solution to the recurrence
relation defining the attention distribution. This makes it more
efficient than 'recursive', but it requires numerical checks which
make the distribution non-exact. This can be a problem in particular
when input_sequence_length is long and/or p_choose_i has entries very
close to 0 or 1.
* 'hard' requires that the probabilities in p_choose_i are all either 0
or 1, and subsequently uses a more efficient and exact solution.
Returns:
A tensor of shape (batch_size, input_sequence_length) representing the
attention distributions for each sequence in the batch.
Raises:
ValueError: mode is not one of 'recursive', 'parallel', 'hard'.
"""
# Force things to be tensors
p_choose_i = ops.convert_to_tensor(p_choose_i, name="p_choose_i")
previous_attention = ops.convert_to_tensor(
previous_attention, name="previous_attention")
if mode == "recursive":
# Use .shape[0].value when it's not None, or fall back on symbolic shape
batch_size = p_choose_i.shape[0].value or array_ops.shape(p_choose_i)[0]
# Compute [1, 1 - p_choose_i[0], 1 - p_choose_i[1], ..., 1 - p_choose_i[-2]]
shifted_1mp_choose_i = array_ops.concat(
[array_ops.ones((batch_size, 1)), 1 - p_choose_i[:, :-1]], 1)
# Compute attention distribution recursively as
# q[i] = (1 - p_choose_i[i])*q[i - 1] + previous_attention[i]
# attention[i] = p_choose_i[i]*q[i]
attention = p_choose_i*array_ops.transpose(functional_ops.scan(
# Need to use reshape to remind TF of the shape between loop iterations
lambda x, yz: array_ops.reshape(yz[0]*x + yz[1], (batch_size,)),
# Loop variables yz[0] and yz[1]
[array_ops.transpose(shifted_1mp_choose_i),
array_ops.transpose(previous_attention)],
# Initial value of x is just zeros
array_ops.zeros((batch_size,))))
elif mode == "parallel":
# safe_cumprod computes cumprod in logspace with numeric checks
cumprod_1mp_choose_i = safe_cumprod(1 - p_choose_i, axis=1, exclusive=True)
# Compute recurrence relation solution
attention = p_choose_i*cumprod_1mp_choose_i*math_ops.cumsum(
previous_attention /
# Clip cumprod_1mp to avoid divide-by-zero
clip_ops.clip_by_value(cumprod_1mp_choose_i, 1e-10, 1.), axis=1)
elif mode == "hard":
# Remove any probabilities before the index chosen last time step
p_choose_i *= math_ops.cumsum(previous_attention, axis=1)
# Now, use exclusive cumprod to remove probabilities after the first
# chosen index, like so:
# p_choose_i = [0, 0, 0, 1, 1, 0, 1, 1]
# cumprod(1 - p_choose_i, exclusive=True) = [1, 1, 1, 1, 0, 0, 0, 0]
# Product of above: [0, 0, 0, 1, 0, 0, 0, 0]
attention = p_choose_i*math_ops.cumprod(
1 - p_choose_i, axis=1, exclusive=True)
else:
raise ValueError("mode must be 'recursive', 'parallel', or 'hard'.")
return attention
开发者ID:AutumnQYN,项目名称:tensorflow,代码行数:83,代码来源:attention_wrapper.py
示例13: from_tensor
def from_tensor(tensor, lengths=None, padding=None, ragged_rank=1, name=None):
"""Converts a `Tensor` into a `RaggedTensor`.
The set of absent/default values may be specified using a vector of lengths
or a padding value (but not both). If `lengths` is specified, then the
output tensor will satisfy `output[row] = tensor[row][:lengths[row]]`.
If `padding` is specified, then any row *suffix* consisting entirely of
`padding` will be excluded from the returned `RaggedTensor`. If neither
`lengths` nor `padding` is specified, then the returned `RaggedTensor` will
have no absent/default values.
Examples:
```python
>>> dt = tf.constant([[5, 7, 0], [0, 3, 0], [6, 0, 0]])
>>> ragged.from_tensor(dt).eval().tolist()
[[5, 7, 0], [0, 3, 0], [6, 0, 0]]
>>> ragged.from_tensor(dt, lengths=[2, 0, 3]).eval().tolist()
[[5, 7], [], [6, 0, 0]]
>>> ragged.from_tensor(dt, padding=0).eval().tolist()
[[5, 7], [0, 3], [6]]
```
Args:
tensor: The `Tensor` to convert. Must have rank `ragged_rank + 1` or
higher.
lengths: An optional set of row lengths, specified using a 1-D integer
`Tensor` whose length is equal to `tensor.shape[0]` (the number of rows in
`tensor`). If specified, then `output[row]` will contain
`tensor[row][:lengths[row]]`. Negative lengths are treated as zero.
padding: An optional padding value. If specified, then any row suffix
consisting entirely of `padding` will be excluded from the returned
RaggedTensor. `padding` is a `Tensor` with the same dtype as `tensor`
and with `shape=tensor.shape[ragged_rank + 1:]`.
ragged_rank: Integer specifying the ragged rank for the returned
`RaggedTensor`. Must be greater than zero.
name: A name prefix for the returned tensors (optional).
Returns:
A `RaggedTensor` with the specified `ragged_rank`. The shape of the
returned ragged tensor is compatible with the shape of `tensor`.
Raises:
ValueError: If both `lengths` and `padding` are specified.
"""
if lengths is not None and padding is not None:
raise ValueError('Specify lengths or padding, but not both')
if not isinstance(ragged_rank, int):
raise TypeError('ragged_rank expected int, got %r' % ragged_rank)
if ragged_rank <= 0:
raise ValueError('ragged_rank must be greater than 0; got %s' % ragged_rank)
with ops.name_scope(name, 'RaggedFromTensor', [tensor, lengths, padding]):
tensor = ops.convert_to_tensor(tensor, name='tensor')
tensor.shape.with_rank_at_least(ragged_rank + 1)
input_shape = array_ops.shape(tensor, out_type=dtypes.int64)
ncols = input_shape[1]
# Handle ragged_rank>1 via recursion:
# If the output should have multiple ragged dimensions, then first
# flatten the tensor to eliminate all but the last ragged dimension,
# and recursively convert that flattened tensor. Then add on the splits
# for the dimensions that we flattened out.
if ragged_rank > 1:
# Flatten `tensor` to eliminate all but the last ragged dimension.
new_shape = array_ops.concat(
[constant_op.constant([-1], dtypes.int64), input_shape[ragged_rank:]],
axis=0)
flattened = array_ops.reshape(tensor, new_shape)
# Recursively convert the flattened tensor.
values = from_tensor(flattened, lengths, padding)
# The total number of elements in each dimension. E.g., if
# input_shape=[3, 4, 5, 6], then dim[2] has 3*4*5 elements in total.
dim_size = math_ops.cumprod(input_shape)
# Construct splits tensors for the dimensions that were flattened.
new_splits = [
math_ops.range(0, dim_size[dim - 1] + 1) * input_shape[dim]
for dim in range(1, ragged_rank)
]
return ragged_factory_ops.from_nested_row_splits(values, new_splits)
# If padding was specified, then use it to find row lengths.
if padding is not None:
padding = ops.convert_to_tensor(
padding, name='padding', dtype=tensor.dtype)
padding.shape.assert_is_compatible_with(tensor.shape[2:])
# Find places where the padding is equal to the tensor. (This will
# broadcast `padding` across the outermost 2 dimensions of `tensor`,
# so `has_default_value.shape = tensor.shape`.)
has_default_value = math_ops.equal(padding, tensor)
# If the padding isn't a scalar, then require that all values in the
# padding match each item in the tensor. After this block of code,
# `has_default.shape = tensor.shape[:2]`. (Unfortunately, we can't just
# use reduce_all for both cases, becaue when you pass an empty `axis`
# list to reduce_all, it reduces all axes; but we want it to reduce no
# axes -- i.e., to be a no-op.)
tensor_rank = array_ops.rank(tensor)
reduce_axis = math_ops.range(2, tensor_rank)
has_default = control_flow_ops.cond(
#.........这里部分代码省略.........
开发者ID:abhinav-upadhyay,项目名称:tensorflow,代码行数:101,代码来源:ragged_conversion_ops.py
示例14: boolean_mask
#.........这里部分代码省略.........
elif mask.shape.ndims == 0:
raise ValueError('mask cannot be scalar.')
# If mask is ragged, then recurse with a non-ragged mask.
if ragged_tensor.is_ragged(mask):
if not ragged_tensor.is_ragged(data):
data = ragged_tensor.RaggedTensor.from_tensor(
data, ragged_rank=mask.ragged_rank,
row_splits_dtype=mask.row_splits.dtype)
# Check that mask.nested_row_splits is a prefix of
# data.nested_row_splits.
splits_list = [
mask.nested_row_splits, data.nested_row_splits[:mask.ragged_rank]
]
with ops.control_dependencies(
ragged_util.assert_splits_match(splits_list)):
# Strip off ragged `splits` until `mask` is non-ragged. Keep the splits
# that we strip off in `splits`, so we can add them back on after
# we recursively mask the non-ragged data.
splits = []
while ragged_tensor.is_ragged(mask):
if mask.shape.ndims > 2:
splits.append(mask.row_splits)
else:
# Count the number of True mask values in each row to find the
# lengths of the filtered rows; then convert to splits.
int_mask = ragged_functional_ops.map_flat_values(
math_ops.cast, mask, dtype=row_splits_dtype)
masked_row_lengths = ragged_math_ops.reduce_sum(int_mask, axis=1)
splits.append(ragged_util.lengths_to_splits(masked_row_lengths))
mask = mask.values
data = data.values
# Recursively apply the nested non-ragged mask to the nested data.
masked_values = boolean_mask(data, mask, keepdims)
# Add the ragged `splits` back to the result.
if keepdims:
masked_values = ragged_tensor.RaggedTensor.from_nested_row_splits(
masked_values, splits, validate=False)
return masked_values
# If mask is non-ragged and has rank 1, and data is ragged, then build a
# ragged tensor with the indicated rows.
elif ragged_tensor.is_ragged(data) and mask.shape.ndims == 1:
# Get the masked splits: first get the length of each row, then filter
# out the rows that we are deleting, and convert that filtered set of
# masks back to a splits tensor.
lengths = data.row_lengths()
masked_lengths = array_ops.boolean_mask(lengths, mask)
masked_splits = ragged_util.lengths_to_splits(masked_lengths)
# Get the masked values: first get row ids corresponding to each
# value, then use tf.gather to build a boolean mask that's false for
# values that come from rows that we are deleting, and use that mask to
# construct the masked values tensor.
segment_ids = segment_id_ops.row_splits_to_segment_ids(data.row_splits)
segment_mask = array_ops.gather(mask, segment_ids)
masked_values = boolean_mask(data.values, segment_mask, keepdims=False)
return ragged_tensor.RaggedTensor.from_row_splits(masked_values,
masked_splits,
validate=False)
# If mask is non-ragged and has rank>1, then convert it to be ragged,
# with a ragged rank matching data.
if ragged_tensor.is_ragged(data):
mask = ragged_tensor.RaggedTensor.from_tensor(
mask, ragged_rank=min(data.ragged_rank, mask.shape.ndims - 1),
row_splits_dtype=data.row_splits.dtype)
return boolean_mask(data, mask, keepdims)
# Otherwise, data and mask are both `Tensor`s.
else:
# Apply `boolean_mask` to get the masked values.
masked_values = array_ops.boolean_mask(data, mask)
if mask.shape.ndims >= 2 and keepdims:
# Add the innermost ragged dimension. For each innermost cell, get the
# number of values it contains. Then flatten that to get a list of
# cell lengths, and convert it to splits. Finally, combine the splits
# and values to get the innermost ragged tensor.
masked_lengths = math_ops.count_nonzero(mask, axis=-1,
dtype=row_splits_dtype)
flattened_masked_lengths = array_ops.reshape(masked_lengths, [-1])
masked_values = ragged_tensor.RaggedTensor.from_row_lengths(
masked_values, flattened_masked_lengths, validate=False)
# Wrap remaining ragged dimensions.
if mask.shape.ndims > 2 and keepdims:
mask_shape = array_ops.shape(mask, out_type=row_splits_dtype)
split_size = math_ops.cumprod(mask_shape) + 1
for dim in range(mask.shape.ndims - 3, -1, -1):
elt_size = mask_shape[dim + 1]
masked_splits = math_ops.range(split_size[dim]) * elt_size
masked_values = ragged_tensor.RaggedTensor.from_row_splits(
masked_values, masked_splits, validate=False)
return masked_values
开发者ID:aritratony,项目名称:tensorflow,代码行数:101,代码来源:ragged_array_ops.py
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