本文整理汇总了Python中sympy.logic.boolalg.distribute_and_over_or函数的典型用法代码示例。如果您正苦于以下问题:Python distribute_and_over_or函数的具体用法?Python distribute_and_over_or怎么用?Python distribute_and_over_or使用的例子?那么恭喜您, 这里精选的函数代码示例或许可以为您提供帮助。
在下文中一共展示了distribute_and_over_or函数的5个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于我们的系统推荐出更棒的Python代码示例。
示例1: eval
def eval(cls, *args):
# Check for situations where we can evaluate the Piecewise object.
# 1) Hit an unevaluable cond (e.g. x<1) -> keep object
# 2) Hit a true condition -> return that expr
# 3) Remove false conditions, if no conditions left -> raise ValueError
all_conds_evaled = True # Do all conds eval to a bool?
piecewise_again = False # Should we pass args to Piecewise again?
non_false_ecpairs = []
or1 = Or(*[cond for (_, cond) in args if cond != true])
for expr, cond in args:
# Check here if expr is a Piecewise and collapse if one of
# the conds in expr matches cond. This allows the collapsing
# of Piecewise((Piecewise(x,x<0),x<0)) to Piecewise((x,x<0)).
# This is important when using piecewise_fold to simplify
# multiple Piecewise instances having the same conds.
# Eventually, this code should be able to collapse Piecewise's
# having different intervals, but this will probably require
# using the new assumptions.
if isinstance(expr, Piecewise):
or2 = Or(*[c for (_, c) in expr.args if c != true])
for e, c in expr.args:
# Don't collapse if cond is "True" as this leads to
# incorrect simplifications with nested Piecewises.
if c == cond and (or1 == or2 or cond != true):
expr = e
piecewise_again = True
cond_eval = cls.__eval_cond(cond)
if cond_eval is None:
all_conds_evaled = False
elif cond_eval:
if all_conds_evaled:
return expr
if len(non_false_ecpairs) != 0:
if non_false_ecpairs[-1].cond == cond:
continue
elif non_false_ecpairs[-1].expr == expr:
newcond = Or(cond, non_false_ecpairs[-1].cond)
if isinstance(newcond, (And, Or)):
newcond = distribute_and_over_or(newcond)
non_false_ecpairs[-1] = ExprCondPair(expr, newcond)
continue
non_false_ecpairs.append(ExprCondPair(expr, cond))
if len(non_false_ecpairs) != len(args) or piecewise_again:
return cls(*non_false_ecpairs)
return None
开发者ID:B-Rich,项目名称:sympy,代码行数:46,代码来源:piecewise.py
示例2: test_distribute
def test_distribute():
A, B, C = symbols('ABC')
assert distribute_and_over_or(Or(And(A, B), C)) == And(Or(A, C), Or(B, C))
开发者ID:KevinGoodsell,项目名称:sympy,代码行数:3,代码来源:test_boolalg.py
示例3: test_distribute
def test_distribute():
assert distribute_and_over_or(Or(And(A, B), C)) == And(Or(A, C), Or(B, C))
assert distribute_or_over_and(And(A, Or(B, C))) == Or(And(A, B), And(A, C))
开发者ID:Lenqth,项目名称:sympy,代码行数:3,代码来源:test_boolalg.py
示例4: eval
#.........这里部分代码省略.........
c = c.xreplace(reps)
args.append((e, _canonical(c)))
for expr, cond in args:
# Check here if expr is a Piecewise and collapse if one of
# the conds in expr matches cond. This allows the collapsing
# of Piecewise((Piecewise((x,x<0)),x<0)) to Piecewise((x,x<0)).
# This is important when using piecewise_fold to simplify
# multiple Piecewise instances having the same conds.
# Eventually, this code should be able to collapse Piecewise's
# having different intervals, but this will probably require
# using the new assumptions.
if isinstance(expr, Piecewise):
unmatching = []
for i, (e, c) in enumerate(expr.args):
if c in current_cond:
# this would already have triggered
continue
if c == cond:
if c != True:
# nothing past this condition will ever
# trigger and only those args before this
# that didn't match a previous condition
# could possibly trigger
if unmatching:
expr = Piecewise(*(
unmatching + [(e, c)]))
else:
expr = e
break
else:
unmatching.append((e, c))
# check for condition repeats
got = False
# -- if an And contains a condition that was
# already encountered, then the And will be
# False: if the previous condition was False
# then the And will be False and if the previous
# condition is True then then we wouldn't get to
# this point. In either case, we can skip this condition.
for i in ([cond] +
(list(cond.args) if isinstance(cond, And) else
[])):
if i in current_cond:
got = True
break
if got:
continue
# -- if not(c) is already in current_cond then c is
# a redundant condition in an And. This does not
# apply to Or, however: (e1, c), (e2, Or(~c, d))
# is not (e1, c), (e2, d) because if c and d are
# both False this would give no results when the
# true answer should be (e2, True)
if isinstance(cond, And):
nonredundant = []
for c in cond.args:
if (isinstance(c, Relational) and
(~c).canonical in current_cond):
continue
nonredundant.append(c)
cond = cond.func(*nonredundant)
elif isinstance(cond, Relational):
if (~cond).canonical in current_cond:
cond = S.true
current_cond.add(cond)
# collect successive e,c pairs when exprs or cond match
if newargs:
if newargs[-1].expr == expr:
orcond = Or(cond, newargs[-1].cond)
if isinstance(orcond, (And, Or)):
orcond = distribute_and_over_or(orcond)
newargs[-1] = ExprCondPair(expr, orcond)
continue
elif newargs[-1].cond == cond:
orexpr = Or(expr, newargs[-1].expr)
if isinstance(orexpr, (And, Or)):
orexpr = distribute_and_over_or(orexpr)
newargs[-1] == ExprCondPair(orexpr, cond)
continue
newargs.append(ExprCondPair(expr, cond))
# some conditions may have been redundant
missing = len(newargs) != len(_args)
# some conditions may have changed
same = all(a == b for a, b in zip(newargs, _args))
# if either change happened we return the expr with the
# updated args
if not newargs:
raise ValueError(filldedent('''
There are no conditions (or none that
are not trivially false) to define an
expression.'''))
if missing or not same:
return cls(*newargs)
开发者ID:Lenqth,项目名称:sympy,代码行数:101,代码来源:piecewise.py
示例5: test_distribute
def test_distribute():
A, B, C = map(Boolean, symbols('A,B,C'))
assert distribute_and_over_or(Or(And(A, B), C)) == And(Or(A, C), Or(B, C))
开发者ID:jenshnielsen,项目名称:sympy,代码行数:4,代码来源:test_boolalg.py
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