本文整理汇总了Python中networkx.min_cost_flow函数的典型用法代码示例。如果您正苦于以下问题:Python min_cost_flow函数的具体用法?Python min_cost_flow怎么用?Python min_cost_flow使用的例子?那么恭喜您, 这里精选的函数代码示例或许可以为您提供帮助。
在下文中一共展示了min_cost_flow函数的11个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于我们的系统推荐出更棒的Python代码示例。
示例1: test_digon
def test_digon(self):
"""Check if digons are handled properly. Taken from ticket
#618 by arv."""
nodes = [(1, {}),
(2, {'demand': -4}),
(3, {'demand': 4}),
]
edges = [(1, 2, {'capacity': 3, 'weight': 600000}),
(2, 1, {'capacity': 2, 'weight': 0}),
(2, 3, {'capacity': 5, 'weight': 714285}),
(3, 2, {'capacity': 2, 'weight': 0}),
]
G = nx.DiGraph(edges)
G.add_nodes_from(nodes)
flowCost, H = nx.network_simplex(G)
soln = {1: {2: 0},
2: {1: 0, 3: 4},
3: {2: 0}}
assert_equal(flowCost, 2857140)
assert_equal(nx.min_cost_flow_cost(G), 2857140)
assert_equal(H, soln)
assert_equal(nx.min_cost_flow(G), soln)
assert_equal(nx.cost_of_flow(G, H), 2857140)
flowCost, H = nx.capacity_scaling(G)
assert_equal(flowCost, 2857140)
assert_equal(H, soln)
assert_equal(nx.cost_of_flow(G, H), 2857140)
开发者ID:ProgVal,项目名称:networkx,代码行数:28,代码来源:test_mincost.py
示例2: test_digraph1
def test_digraph1(self):
# From Bradley, S. P., Hax, A. C. and Magnanti, T. L. Applied
# Mathematical Programming. Addison-Wesley, 1977.
G = nx.DiGraph()
G.add_node(1, demand=-20)
G.add_node(4, demand=5)
G.add_node(5, demand=15)
G.add_edges_from([(1, 2, {'capacity': 15, 'weight': 4}),
(1, 3, {'capacity': 8, 'weight': 4}),
(2, 3, {'weight': 2}),
(2, 4, {'capacity': 4, 'weight': 2}),
(2, 5, {'capacity': 10, 'weight': 6}),
(3, 4, {'capacity': 15, 'weight': 1}),
(3, 5, {'capacity': 5, 'weight': 3}),
(4, 5, {'weight': 2}),
(5, 3, {'capacity': 4, 'weight': 1})])
flowCost, H = nx.network_simplex(G)
soln = {1: {2: 12, 3: 8},
2: {3: 8, 4: 4, 5: 0},
3: {4: 11, 5: 5},
4: {5: 10},
5: {3: 0}}
assert_equal(flowCost, 150)
assert_equal(nx.min_cost_flow_cost(G), 150)
assert_equal(H, soln)
assert_equal(nx.min_cost_flow(G), soln)
assert_equal(nx.cost_of_flow(G, H), 150)
flowCost, H = nx.capacity_scaling(G)
assert_equal(flowCost, 150)
assert_equal(H, soln)
assert_equal(nx.cost_of_flow(G, H), 150)
开发者ID:ProgVal,项目名称:networkx,代码行数:32,代码来源:test_mincost.py
示例3: test_zero_capacity_edges
def test_zero_capacity_edges(self):
"""Address issue raised in ticket #617 by arv."""
G = nx.DiGraph()
G.add_edges_from([(1, 2, {'capacity': 1, 'weight': 1}),
(1, 5, {'capacity': 1, 'weight': 1}),
(2, 3, {'capacity': 0, 'weight': 1}),
(2, 5, {'capacity': 1, 'weight': 1}),
(5, 3, {'capacity': 2, 'weight': 1}),
(5, 4, {'capacity': 0, 'weight': 1}),
(3, 4, {'capacity': 2, 'weight': 1})])
G.nodes[1]['demand'] = -1
G.nodes[2]['demand'] = -1
G.nodes[4]['demand'] = 2
flowCost, H = nx.network_simplex(G)
soln = {1: {2: 0, 5: 1},
2: {3: 0, 5: 1},
3: {4: 2},
4: {},
5: {3: 2, 4: 0}}
assert_equal(flowCost, 6)
assert_equal(nx.min_cost_flow_cost(G), 6)
assert_equal(H, soln)
assert_equal(nx.min_cost_flow(G), soln)
assert_equal(nx.cost_of_flow(G, H), 6)
flowCost, H = nx.capacity_scaling(G)
assert_equal(flowCost, 6)
assert_equal(H, soln)
assert_equal(nx.cost_of_flow(G, H), 6)
开发者ID:ProgVal,项目名称:networkx,代码行数:30,代码来源:test_mincost.py
示例4: constrained_kmeans
def constrained_kmeans(data, demand, maxiter=None, fixedprec=1e9):
data = np.array(data)
min_ = np.min(data, axis=0)
max_ = np.max(data, axis=0)
c = min_ + np.random.random((len(demand), data.shape[1])) * (max_ - min_)
m = np.array([-1] * len(data), dtype=np.int)
itercnt = 0
while True:
itercnt += 1
# memberships
g = nx.DiGraph()
g.add_nodes_from(xrange(0, data.shape[0]), demand=-1) # points
for i in xrange(0, len(c)):
g.add_node(len(data) + i, demand=demand[i])
# Calculating cost...
cost = np.array([np.linalg.norm(
np.tile(data.T, len(c)).T - np.tile(c, len(data)).reshape(len(c) * len(data), c.shape[1]), axis=1)])
# Preparing data_to_c_edges...
data_to_c_edges = np.concatenate((np.tile([xrange(0, data.shape[0])], len(c)).T,
np.tile(np.array([xrange(data.shape[0], data.shape[0] + c.shape[0])]).T,
len(data)).reshape(len(c) * len(data), 1), cost.T * fixedprec),
axis=1).astype(np.uint64)
# Adding to graph
g.add_weighted_edges_from(data_to_c_edges)
a = len(data) + len(c)
g.add_node(a, demand=len(data) - np.sum(demand))
c_to_a_edges = np.concatenate((np.array([xrange(len(data), len(data) + len(c))]).T, np.tile([[a]], len(c)).T),
axis=1)
g.add_edges_from(c_to_a_edges)
# Calculating min cost flow...
f = nx.min_cost_flow(g)
# assign
m_new = np.ones(len(data), dtype=np.int) * -1
for i in xrange(len(data)):
p = sorted(f[i].iteritems(), key=lambda x: x[1])[-1][0]
m_new[i] = p - len(data)
# stop condition
if np.all(m_new == m):
# Stop
return c, m, f
m = m_new
# compute new centers
for i in xrange(len(c)):
c[i, :] = np.mean(data[m == i, :], axis=0)
if maxiter is not None and itercnt >= maxiter:
# Max iterations reached
return c, m, f
开发者ID:polito-eda,项目名称:ghost,代码行数:59,代码来源:_constrained_kmeans.py
示例5: assign
def assign(photos, pois):
"""Assign photos to POIs with minimum cost"""
#REF: en.wikipedia.org/wiki/Minimum-cost_flow_problem
#assert(len(photos) == len(pois))
dists = np.zeros((len(photos), len(pois)), dtype=np.float64)
for i, d in enumerate(photos):
for j, p in enumerate(pois):
dists[i, j] = round(math.sqrt( (d[0] - p[0])**2 + (d[1] - p[1])**2 ))
#print(dists)
G = nx.DiGraph()
# complete bipartite graph: photo -> POI
# infinity capacity
for i in range(len(photos)):
for j in range(len(pois)):
u = 'd' + str(i)
v = 'p' + str(j)
G.add_edge(u, v, weight=dists[i, j])
# source -> photo
# capacity = 1
for i in range(len(photos)):
u = 's'
v = 'd' + str(i)
G.add_edge(u, v, capacity=1, weight=0)
# POI -> sink
# infinity capacity
for j in range(len(pois)):
u = 'p' + str(j)
v = 't'
G.add_edge(u, v, weight=0)
# demand for source and sink
G.add_node('s', demand=-len(photos))
G.add_node('t', demand=len(photos))
#print(G.nodes())
#print(G.edges())
flowDict = nx.min_cost_flow(G)
assignment = dict()
for e in G.edges():
u = e[0]
v = e[1]
if u != 's' and v != 't' and flowDict[u][v] > 0:
#print(e, flowDict[u][v])
assignment[u] = v
return assignment
开发者ID:BigHankSmallHank,项目名称:digbeta,代码行数:52,代码来源:poi_photo_assign.py
示例6: test_transshipment
def test_transshipment(self):
G = nx.DiGraph()
G.add_node('a', demand=1)
G.add_node('b', demand=-2)
G.add_node('c', demand=-2)
G.add_node('d', demand=3)
G.add_node('e', demand=-4)
G.add_node('f', demand=-4)
G.add_node('g', demand=3)
G.add_node('h', demand=2)
G.add_node('r', demand=3)
G.add_edge('a', 'c', weight=3)
G.add_edge('r', 'a', weight=2)
G.add_edge('b', 'a', weight=9)
G.add_edge('r', 'c', weight=0)
G.add_edge('b', 'r', weight=-6)
G.add_edge('c', 'd', weight=5)
G.add_edge('e', 'r', weight=4)
G.add_edge('e', 'f', weight=3)
G.add_edge('h', 'b', weight=4)
G.add_edge('f', 'd', weight=7)
G.add_edge('f', 'h', weight=12)
G.add_edge('g', 'd', weight=12)
G.add_edge('f', 'g', weight=-1)
G.add_edge('h', 'g', weight=-10)
flowCost, H = nx.network_simplex(G)
soln = {'a': {'c': 0},
'b': {'a': 0, 'r': 2},
'c': {'d': 3},
'd': {},
'e': {'r': 3, 'f': 1},
'f': {'d': 0, 'g': 3, 'h': 2},
'g': {'d': 0},
'h': {'b': 0, 'g': 0},
'r': {'a': 1, 'c': 1}}
assert_equal(flowCost, 41)
assert_equal(nx.min_cost_flow_cost(G), 41)
assert_equal(H, soln)
assert_equal(nx.min_cost_flow(G), soln)
assert_equal(nx.cost_of_flow(G, H), 41)
flowCost, H = nx.capacity_scaling(G)
assert_equal(flowCost, 41)
assert_equal(nx.cost_of_flow(G, H), 41)
assert_equal(H, soln)
开发者ID:ProgVal,项目名称:networkx,代码行数:45,代码来源:test_mincost.py
示例7: test_simple_digraph
def test_simple_digraph(self):
G = nx.DiGraph()
G.add_node('a', demand = -5)
G.add_node('d', demand = 5)
G.add_edge('a', 'b', weight = 3, capacity = 4)
G.add_edge('a', 'c', weight = 6, capacity = 10)
G.add_edge('b', 'd', weight = 1, capacity = 9)
G.add_edge('c', 'd', weight = 2, capacity = 5)
flowCost, H = nx.network_simplex(G)
soln = {'a': {'b': 4, 'c': 1},
'b': {'d': 4},
'c': {'d': 1},
'd': {}}
assert_equal(flowCost, 24)
assert_equal(nx.min_cost_flow_cost(G), 24)
assert_equal(H, soln)
assert_equal(nx.min_cost_flow(G), soln)
assert_equal(nx.cost_of_flow(G, H), 24)
开发者ID:mshelton,项目名称:networkx,代码行数:18,代码来源:test_mincost.py
示例8: int
total += int(exits) - int(entries)
for n in G.nodes():
if "demand" not in G.node[n]:
G.remove_node(n)
turnstile_stations = [record.strip().split(',')[2] for record in noondata]
gtfs_stations = G.nodes()
#print set(turnstile_stations) - set(gtfs_stations)
extra_nodes = set(gtfs_stations) - set(turnstile_stations)
nx.draw_spring(G, with_labels=True, node_color='w', node_size=350, font_size=7)
#plt.show()
flow = nx.min_cost_flow(G)
inflowstation=[]
inflow=[]
for x in G.nodes():
total = 0
inflowstation.append(x)
for p in G.predecessors(x):
total = total+ flow[p][x]
inflow.append(total)
rows = zip(inflowstation,inflow)
length= range(0,len(inflowstation))
开发者ID:eimanahmed,项目名称:Subway-Flow,代码行数:31,代码来源:Inflows.py
示例9: func
y = [ func(xx) for xx in x ]
plt.figure()
plt.plot(x,y)
plt.show()
def FLOWCOST( flow, cost ) :
res = [ cc( flow.get( e, 0. ) ) for e, cc in cost.iteritems() ] # big difference!
#res = [ cost.get( e, line(0.) )( flow[e] ) for e in flow ]
return sum( res )
def FEAS( flow, capacity, network ) :
for e in network.edges() :
if flow.get(e, 0. ) > capacity.get(e, np.Inf ) : return False
return True
flow = MinConvexCostFlow( g, u, supply, cf, epsilon=.001 )
print ( flow, FLOWCOST( flow, cf ), FEAS( flow, u, g ) )
flowstar = { 'b' : 10., 'd' : 10. }
print ( flowstar, FLOWCOST( flowstar, cf ), FEAS( flowstar, u, g ) )
digraph = mincostflow_nx( g, u, supply, c )
compare = nx.min_cost_flow( digraph )
开发者ID:kyletreleaven,项目名称:roadgeometry-matching,代码行数:25,代码来源:cvxcostflow.py
示例10: costs
# Let's now solve for the min-cost flow of the example we had in class. We have already added capacities and demands to our network. We finally need to introduce edge costs (weights).
# In[10]:
G.edge['s']['u']['weight'] = 1
G.edge['s']['v']['weight'] = 1
G.edge['u']['v']['weight'] = 1
G.edge['u']['t']['weight'] = 1
G.edge['v']['t']['weight'] = 2
# Now we can just call the min-cost flow function. Note that we could have used this to solve the flow-with-demands problem, just by setting all the costs (weights) to 0.
# In[11]:
minimum_cost_flow = nx.min_cost_flow(G)
print_flow(minimum_cost_flow)
# This is the same as the maximum flow found in class. For this example, the maximum flow is unique.
# ## Exercises
#
# 1. Construct the bipartite graph from the example application in the slides and find a matching using max flow.
#
# 2. Write a function to compute a conformal decomposition of a flow with demands, and run it on the flows found in the "Min-Cost Flow" section above.
# ### Solution 1
#
# For the first problem, we form the network by hand then solve max flow using new source and sink vertices, imposing a capacity of 1 on all edges.
开发者ID:Ablat,项目名称:coursework,代码行数:30,代码来源:network-flows.py
示例11: constrcut_flow_graph
def constrcut_flow_graph(reach_graph,sorted_bbox,flow_graph=None,scores=None):
def to_left_node(index):
return 2*index+1
def to_right_node(index):
return 2*index+2
def scale_to_int(score):
MAX_VALUE = 10000
return int(score*MAX_VALUE)
def compute_box_center(box):
center_y = (box[3]+box[1])/2
center_x = (box[2]+box[0])/2
return center_x,center_y
def get_data_cost(score):
return scale_to_int(score)
def get_smoothness_cost(box1, box2):
alpha=0.0
h1=box1[3]-box1[1]+1
h2=box2[3]-box2[1]+1
x1, y1=compute_box_center(box1)
x2, y2=compute_box_center(box2)
d=((x1-x2)**2+(y1-y2)**2)**0.5/min(h1,h2)
s=float(abs(h1-h2))/min(h1, h2)
return scale_to_int(alpha*d+(1-alpha)*s)
def get_entry_cost(index,reach_graph,scores):
reach_node_costs = [scores[left] for left, right in reach_graph.edges() if right == index]
sorted_costs = sorted(reach_node_costs)
if len(sorted_costs) > 0:
cost = scale_to_int(-sorted_costs[-1])
else:
cost = 0
return cost
def get_exit_cost(index,reach_graph,scores):
reach_node_costs = [scores[right] for left, right in reach_graph.edges() if left == index]
sorted_costs = sorted(reach_node_costs)
if len(sorted_costs) > 0:
cost = scale_to_int(-sorted_costs[-1])
else:
cost = 0
return cost
def overlaps(box1,box2):
h1=box1[3]-box1[1]+1
h2=box2[3]-box2[1]+1
overlaps=min(box2[3], box1[3])-max(box1[1], box2[1])
overlaps=overlaps if overlaps>0 else 0
return float(overlaps)/h2
length = len(sorted_bbox)
scores = [-1 for i in range(length)]
if flow_graph == None:
#box
print 'construct graph'
flow_graph = nx.DiGraph()
ENTRY_NODE = -1
flow_graph.add_node(ENTRY_NODE,demand = -1)
EXIT_NODE = -2
flow_graph.add_node(EXIT_NODE,demand = 1)
# data cost
for index in range(length):
left_node = to_left_node(index)
right_node = to_right_node(index)
flow_graph.add_node(left_node)
flow_graph.add_node(right_node)
data_cost = get_data_cost(scores[index])
flow_graph.add_edge(left_node,right_node,weight=data_cost,capacity = 1)
# smoothness cost
for left,right in reach_graph.edges():
left_node = to_right_node(left)
right_node = to_left_node(right)
smoothness_cost = get_smoothness_cost(sorted_bbox[left],sorted_bbox[right])
flow_graph.add_edge(left_node,right_node,weight=smoothness_cost,capacity = 1)
# entry cost
for index in range(length):
entry_cost = get_entry_cost(index,reach_graph,scores)
left_node = to_left_node(index)
flow_graph.add_edge(ENTRY_NODE,left_node,weight=entry_cost,capacity = 1)
# exit cost
for index in range(length):
exit_cost = get_exit_cost(index,reach_graph,scores)
right_node = to_right_node(index)
flow_graph.add_edge(right_node,EXIT_NODE,weight=exit_cost,capacity = 1)
box_inds=[]
flowDict = nx.min_cost_flow(flow_graph)
flowCost = nx.min_cost_flow_cost(flow_graph)
for index in range(length):
left_node=to_left_node(index)
right_node=to_right_node(index)
try:
find = [node for node, value in flowDict[left_node].iteritems() if value == 1]
except:
find = []
if len(find)>0:
#.........这里部分代码省略.........
开发者ID:BestSonny,项目名称:text-flow,代码行数:101,代码来源:text_flow.py
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