本文整理汇总了Python中mezzanine.utils.sites.has_site_permission函数的典型用法代码示例。如果您正苦于以下问题:Python has_site_permission函数的具体用法?Python has_site_permission怎么用?Python has_site_permission使用的例子?那么恭喜您, 这里精选的函数代码示例或许可以为您提供帮助。
在下文中一共展示了has_site_permission函数的6个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于我们的系统推荐出更棒的Python代码示例。
示例1: _can_edit_content
def _can_edit_content(self, request, obj):
if isinstance(obj, Content):
owners = obj.get_root().node.versiontracker_set.get().owners
any_owner_in_current_site = any(current_site_id() == o.site_id for o in owners)
return has_site_permission(request.user) and any_owner_in_current_site
else:
return True
开发者ID:sigmundv,项目名称:django-widgy,代码行数:7,代码来源:site.py
示例2: editable_loader
def editable_loader(context):
"""
Set up the required JS/CSS for the in-line editing toolbar and controls.
"""
user = context["request"].user
context["has_site_permission"] = has_site_permission(user)
if settings.INLINE_EDITING_ENABLED and context["has_site_permission"]:
t = get_template("includes/editable_toolbar.html")
context["REDIRECT_FIELD_NAME"] = REDIRECT_FIELD_NAME
context["toolbar"] = t.render(Context(context))
context["richtext_media"] = RichTextField().formfield().widget.media
return context
开发者ID:dfalk,项目名称:mezzanine,代码行数:12,代码来源:mezzanine_tags.py
示例3: is_editable
def is_editable(obj, request):
"""
Returns ``True`` if the object is editable for the request. First
check for a custom ``editable`` handler on the object, otherwise
use the logged in user and check change permissions for the
object's model.
"""
if hasattr(obj, "is_editable"):
return obj.is_editable(request)
else:
perm = obj._meta.app_label + "." + obj._meta.get_change_permission()
return (request.user.is_authenticated() and
has_site_permission(request.user) and
request.user.has_perm(perm))
开发者ID:AdnanHodzic,项目名称:mezzanine,代码行数:14,代码来源:views.py
示例4: editable_loader
def editable_loader(context):
"""
Set up the required JS/CSS for the in-line editing toolbar and controls.
"""
user = context["request"].user
template_vars = {"has_site_permission": has_site_permission(user), "request": context["request"]}
if settings.INLINE_EDITING_ENABLED and template_vars["has_site_permission"]:
t = get_template("includes/editable_toolbar.html")
template_vars["REDIRECT_FIELD_NAME"] = REDIRECT_FIELD_NAME
template_vars["editable_obj"] = context.get("editable_obj", context.get("page", None))
template_vars["accounts_logout_url"] = context.get("accounts_logout_url", None)
template_vars["toolbar"] = t.render(Context(template_vars))
template_vars["richtext_media"] = RichTextField().formfield().widget.media
return template_vars
开发者ID:sjdines,项目名称:mezzanine,代码行数:14,代码来源:mezzanine_tags.py
示例5: is_editable
def is_editable(obj, request):
"""
Returns ``True`` if the object is editable for the request. First
check for a custom ``editable`` handler on the object, otherwise
use the logged in user and check change permissions for the
object's model.
"""
if hasattr(obj, "is_editable"):
return obj.is_editable(request)
else:
codename = get_permission_codename("change", obj._meta)
perm = "%s.%s" % (obj._meta.app_label, codename)
return (is_authenticated(request.user) and
has_site_permission(request.user) and
request.user.has_perm(perm))
开发者ID:christianwgd,项目名称:mezzanine,代码行数:15,代码来源:views.py
示例6: edit
def edit(request):
"""
Process the inline editing form.
"""
model = apps.get_model(request.POST["app"], request.POST["model"])
obj = model.objects.get(id=request.POST["id"])
form = get_edit_form(obj, request.POST["fields"], data=request.POST, files=request.FILES)
if not (is_editable(obj, request) and has_site_permission(request.user)):
response = _("Permission denied")
elif form.is_valid():
form.save()
model_admin = ModelAdmin(model, admin.site)
message = model_admin.construct_change_message(request, form, None)
model_admin.log_change(request, obj, message)
response = ""
else:
response = list(form.errors.values())[0][0]
return HttpResponse(response)
开发者ID:rhizomedotorg,项目名称:mezzanine,代码行数:18,代码来源:views.py
注:本文中的mezzanine.utils.sites.has_site_permission函数示例由纯净天空整理自Github/MSDocs等源码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。 |
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