本文整理汇总了C++中power函数的典型用法代码示例。如果您正苦于以下问题:C++ power函数的具体用法?C++ power怎么用?C++ power使用的例子?那么恭喜您, 这里精选的函数代码示例或许可以为您提供帮助。
在下文中一共展示了power函数的20个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于我们的系统推荐出更棒的C++代码示例。
示例1: makeMSP_v3
int makeMSP_v3(MSP* msp, attr_tree_node* node){
int** matrix = msp -> matrix;
char** label = msp -> label;
int cols = msp -> cols;
int rows = msp -> rows;
attr_tree_node* queue[100] = {0};
int* vectors [100] = {0};
int write_i = -1;
int read_i = -1;
int* v = calloc(cols, sizeof(int));
v[0] = 1;
queue[++write_i] = node;
vectors[write_i] = v;
int count = 1;
int index = 0;
while( read_i < write_i ){
attr_tree_node* node = queue[++read_i];
int* v = vectors[read_i];
if( node -> node_type == ATTR_NODE_OR ){
int i = 0;
for( i; i < 2; i++){
queue[++write_i] = (node -> subnode)[i];
vectors[write_i] = v;
}
}
else if( node -> node_type == ATTR_NODE_AND ){
int* l_v = calloc(cols, sizeof(int));
int* r_v = calloc(cols, sizeof(int));
memcpy(l_v, v, cols*sizeof(int));
l_v[count] = 1;
{
int i = 0;
for(i; i < cols; i++)
r_v[i] = v[i] - l_v[i];
}
count++;
queue[++write_i] = (node -> subnode)[0];
vectors[write_i] = l_v;
queue[++write_i] = (node -> subnode)[1];
vectors[write_i] = r_v;
}
else if( node -> node_type == ATTR_NODE_THRESHOLD ){
int i = 0;
for( i; i < node->num_subnodes; i++ ){
int* l_v = calloc(cols, sizeof(int));
memcpy(l_v, v, cols*sizeof(int));
int j = 0;
for( j; j < node->threshold_k - 1; j++){
l_v[count+j] = power(i+1, j+1);
//printf("power:%d\n", power(i+1, j+1));
}
queue[++write_i] = (node -> subnode)[i];
vectors[write_i] = l_v;
//free(l_v);
}
count = count + (node->threshold_k) - 1;
}
else if( node -> node_type == ATTR_NODE_LEAF){
memcpy( matrix[index], v, cols*sizeof(int) );
label[index] = node->attribute;
index++;
}
}
}
开发者ID:pigeon119,项目名称:ABE,代码行数:75,代码来源:LSSS.c
示例2: str_from_delimited_time_duration
inline
time_duration
str_from_delimited_time_duration(const std::basic_string<char_type>& s)
{
unsigned short min=0, sec =0;
int hour =0;
bool is_neg = (s.at(0) == '-');
lslboost::int64_t fs=0;
int pos = 0;
typedef typename std::basic_string<char_type>::traits_type traits_type;
typedef lslboost::char_separator<char_type, traits_type> char_separator_type;
typedef lslboost::tokenizer<char_separator_type,
typename std::basic_string<char_type>::const_iterator,
std::basic_string<char_type> > tokenizer;
typedef typename lslboost::tokenizer<char_separator_type,
typename std::basic_string<char_type>::const_iterator,
typename std::basic_string<char_type> >::iterator tokenizer_iterator;
char_type sep_chars[5] = {'-',':',',','.'};
char_separator_type sep(sep_chars);
tokenizer tok(s,sep);
for(tokenizer_iterator beg=tok.begin(); beg!=tok.end(); ++beg) {
switch(pos) {
case 0: {
hour = lslboost::lexical_cast<int>(*beg);
break;
}
case 1: {
min = lslboost::lexical_cast<unsigned short>(*beg);
break;
}
case 2: {
sec = lslboost::lexical_cast<unsigned short>(*beg);
break;
};
case 3: {
int digits = static_cast<int>(beg->length());
//Works around a bug in MSVC 6 library that does not support
//operator>> thus meaning lexical_cast will fail to compile.
#if (defined(BOOST_MSVC) && (_MSC_VER < 1300))
// msvc wouldn't compile 'time_duration::num_fractional_digits()'
// (required template argument list) as a workaround a temp
// time_duration object was used
time_duration td(hour,min,sec,fs);
int precision = td.num_fractional_digits();
// _atoi64 is an MS specific function
if(digits >= precision) {
// drop excess digits
fs = _atoi64(beg->substr(0, precision).c_str());
}
else {
fs = _atoi64(beg->c_str());
}
#else
int precision = time_duration::num_fractional_digits();
if(digits >= precision) {
// drop excess digits
fs = lslboost::lexical_cast<lslboost::int64_t>(beg->substr(0, precision));
}
else {
fs = lslboost::lexical_cast<lslboost::int64_t>(*beg);
}
#endif
if(digits < precision) {
// trailing zeros get dropped from the string,
// "1:01:01.1" would yield .000001 instead of .100000
// the power() compensates for the missing decimal places
fs *= power(10, precision - digits);
}
break;
}
default:
break;
}//switch
pos++;
}
if(is_neg) {
return -time_duration(hour, min, sec, fs);
}
else {
return time_duration(hour, min, sec, fs);
}
}
开发者ID:cboulay,项目名称:labstreaminglayer,代码行数:85,代码来源:time_parsing.hpp
示例3: pack
mp_integer bv_arithmetict::pack() const
{
if(value>=0) return value;
return value+power(2, spec.width);
}
开发者ID:ashokkelur,项目名称:CBMC-With-DSP-C,代码行数:5,代码来源:bv_arithmetic.cpp
示例4: main
void main()
{
int x=5,y=2;
printf("%d\n",power(x,y));
printf("%d\n",poweropti(5,4));
}
开发者ID:vineetdhanawat,项目名称:crack-the-interview,代码行数:6,代码来源:power.c
示例5: wLoadBitmap
// returns a pointer to the loaded bitmap
// only supports 24-bit (and 32-bit?) images
wBitmap* wLoadBitmap(char *filename)
{
FILE *bmpFile;
wBitmap *bmp;
int i;
int fileLineSize, memLineSize, fileScanLines, memScanLines, dataSize;
int pad, generic;
BYTE *line;
bmp = (wBitmap*)malloc(sizeof(wBitmap));
memset(bmp, 0, sizeof(wBitmap));
bmp->name = filename;
bmpFile = fopen(filename, "rb");
if (bmpFile)
{
printf("Loading bitmap %s\n", filename);
fread(&bmp->Header, sizeof(bmp->Header), 1, bmpFile);
fread(&bmp->Info, sizeof(bmp->Info), 1, bmpFile);
// only supports 24-bit+ color bitmaps
if (bmp->Info.biBitCount < 24)
{
printf("cannot load %s: bitmap is less than 24-bit color\n", filename);
free(bmp);
return NULL;
}
if (bmp->Info.biCompression)
{
printf("cannot load %s: bitmap is compressed\n", filename);
free(bmp);
return NULL;
}
fileLineSize = bmp->Info.biWidth*bmp->Info.biBitCount / 8;
pad = 4 - fileLineSize % 4;
if (pad == 4)
pad = 0;
fileScanLines = bmp->Info.biHeight;
// check to make sure that image is 2^x * 2^y
// image in memory can be 2^x * 2^y even if disk file isn't, but there will be blank pixels
for (i = 1; i <= MAX_EXP; i++)
{
generic = (int)power(2, i);
if (generic >= bmp->Info.biWidth)
{
bmp->Info.biWidth = generic;
break;
}
}
if (i > MAX_EXP)
{
printf("cannot load %s: bitmap is too large\n", filename);
free(bmp);
return NULL;
}
for (i = 1; i <= MAX_EXP; i++)
{
generic = power(2, i);
if (generic >= bmp->Info.biHeight)
{
bmp->Info.biHeight = generic;
break;
}
}
if (i > MAX_EXP)
{
printf("cannot load %s: bitmap is too large\n", filename);
free(bmp);
return NULL;
}
memLineSize = bmp->Info.biWidth*bmp->Info.biBitCount / 8;
memScanLines = bmp->Info.biHeight;
dataSize = memLineSize*memScanLines;
bmp->pixels = (BYTE*)malloc(dataSize);
memset(bmp->pixels, 0, dataSize);
// end 2^n check
/* printf("image is %i by %i", fileLineSize*8/bmp->Info.biBitCount, fileScanLines);
if ( fileLineSize != memLineSize || fileScanLines != memScanLines )
printf(", expanded to %i by %i", memLineSize*8/bmp->Info.biBitCount, memScanLines);
printf("\n");
*/
// bmps are stored last line first
fseek(bmpFile, bmp->Header.bfOffBits, 0);
line = bmp->pixels + (fileScanLines - 1)*memLineSize;
for (i = 0; i < fileScanLines; i++)
{
fread(line, fileLineSize, 1, bmpFile);
// lines are padded to be 32-bit divisible
if (pad)
fread(&generic, pad, 1, bmpFile);
line -= memLineSize;
}
//.........这里部分代码省略.........
开发者ID:luchoscar,项目名称:Scene_Engine,代码行数:101,代码来源:TextureManager.cpp
示例6: makeGeometry
BaseIF* makeGeometry(Box& a_domain,
RealVect& a_origin,
Real& a_dx)
{
RealVect center;
RealVect radii;
bool insideRegular;
// parse input file
ParmParse pp;
Vector<int> n_cell(SpaceDim);
pp.getarr("n_cell",n_cell,0,SpaceDim);
CH_assert(n_cell.size() == SpaceDim);
IntVect lo = IntVect::Zero;
IntVect hi;
for (int ivec = 0; ivec < SpaceDim; ivec++)
{
if (n_cell[ivec] <= 0)
{
pout() << "Bogus number of cells input = " << n_cell[ivec];
exit(1);
}
hi[ivec] = n_cell[ivec] - 1;
}
a_domain.setSmall(lo);
a_domain.setBig(hi);
Vector<Real> prob_lo(SpaceDim,1.0);
Real prob_hi;
pp.getarr("prob_lo",prob_lo,0,SpaceDim);
pp.get("prob_hi",prob_hi);
a_dx = (prob_hi-prob_lo[0])/n_cell[0];
for (int idir = 0; idir < SpaceDim; idir++)
{
a_origin[idir] = prob_lo[idir];
}
// ParmParse doesn't get RealVects, so work-around with Vector<Real>
Vector<Real> vectorCenter;
pp.getarr("center",vectorCenter,0,SpaceDim);
for (int idir = 0; idir < SpaceDim; idir++)
{
center[idir] = vectorCenter[idir];
}
Vector<Real> vectorRadii;
pp.getarr("radii",vectorRadii,0,SpaceDim);
for (int idir = 0; idir < SpaceDim; idir++)
{
radii[idir] = vectorRadii[idir];
}
int halfTurns;
pp.get("halfturns",halfTurns);
// Parm Parse doesn't get bools, so work-around with int
int intInsideRegular;
pp.get("insideRegular",intInsideRegular);
if (intInsideRegular != 0) insideRegular = true;
if (intInsideRegular == 0) insideRegular = false;
IntVect zero=IntVect::Zero;
bool inside = true;
EllipsoidIF ellipsoid(radii,center,inside);
Real coef = halfTurns / 2.0;
IntVect power(D_DECL(1,0,0));
Vector<PolyTerm> term;
term.resize(1);
term[0].coef = coef;
term[0].powers = power;
PolynomialIF rotate(term,inside);
LatheIF implicit(ellipsoid,rotate,center,insideRegular);
RealVect vectDx = RealVect::Unit;
vectDx *= a_dx;
GeometryShop workshop(implicit,0,vectDx);
// This generates the new EBIS
EBIndexSpace* ebisPtr = Chombo_EBIS::instance();
ebisPtr->define(a_domain,a_origin,a_dx,workshop);
return implicit.newImplicitFunction();
}
开发者ID:rsnemmen,项目名称:Chombo,代码行数:100,代码来源:mobiusTorus.cpp
示例7: Li2_series
static ex Li2_series(const ex &x, const relational &rel, int order, unsigned options)
{
const ex x_pt = x.subs(rel, subs_options::no_pattern);
if (x_pt.info(info_flags::numeric)) {
// First special case: x==0 (derivatives have poles)
if (x_pt.is_zero()) {
// method:
// The problem is that in d/dx Li2(x==0) == -log(1-x)/x we cannot
// simply substitute x==0. The limit, however, exists: it is 1.
// We also know all higher derivatives' limits:
// (d/dx)^n Li2(x) == n!/n^2.
// So the primitive series expansion is
// Li2(x==0) == x + x^2/4 + x^3/9 + ...
// and so on.
// We first construct such a primitive series expansion manually in
// a dummy symbol s and then insert the argument's series expansion
// for s. Reexpanding the resulting series returns the desired
// result.
const symbol s;
ex ser;
// manually construct the primitive expansion
for (int i=1; i<order; ++i)
ser += pow(s,i) / pow(numeric(i), *_num2_p);
// substitute the argument's series expansion
ser = ser.subs(s==x.series(rel, order), subs_options::no_pattern);
// maybe that was terminating, so add a proper order term
epvector nseq { expair(Order(_ex1), order) };
ser += pseries(rel, std::move(nseq));
// reexpanding it will collapse the series again
return ser.series(rel, order);
// NB: Of course, this still does not allow us to compute anything
// like sin(Li2(x)).series(x==0,2), since then this code here is
// not reached and the derivative of sin(Li2(x)) doesn't allow the
// substitution x==0. Probably limits *are* needed for the general
// cases. In case L'Hospital's rule is implemented for limits and
// basic::series() takes care of this, this whole block is probably
// obsolete!
}
// second special case: x==1 (branch point)
if (x_pt.is_equal(_ex1)) {
// method:
// construct series manually in a dummy symbol s
const symbol s;
ex ser = zeta(_ex2);
// manually construct the primitive expansion
for (int i=1; i<order; ++i)
ser += pow(1-s,i) * (numeric(1,i)*(I*Pi+log(s-1)) - numeric(1,i*i));
// substitute the argument's series expansion
ser = ser.subs(s==x.series(rel, order), subs_options::no_pattern);
// maybe that was terminating, so add a proper order term
epvector nseq { expair(Order(_ex1), order) };
ser += pseries(rel, std::move(nseq));
// reexpanding it will collapse the series again
return ser.series(rel, order);
}
// third special case: x real, >=1 (branch cut)
if (!(options & series_options::suppress_branchcut) &&
ex_to<numeric>(x_pt).is_real() && ex_to<numeric>(x_pt)>1) {
// method:
// This is the branch cut: assemble the primitive series manually
// and then add the corresponding complex step function.
const symbol &s = ex_to<symbol>(rel.lhs());
const ex point = rel.rhs();
const symbol foo;
epvector seq;
// zeroth order term:
seq.push_back(expair(Li2(x_pt), _ex0));
// compute the intermediate terms:
ex replarg = series(Li2(x), s==foo, order);
for (size_t i=1; i<replarg.nops()-1; ++i)
seq.push_back(expair((replarg.op(i)/power(s-foo,i)).series(foo==point,1,options).op(0).subs(foo==s, subs_options::no_pattern),i));
// append an order term:
seq.push_back(expair(Order(_ex1), replarg.nops()-1));
return pseries(rel, std::move(seq));
}
}
// all other cases should be safe, by now:
throw do_taylor(); // caught by function::series()
}
开发者ID:feelpp,项目名称:feelpp,代码行数:79,代码来源:inifcns.cpp
示例8: power
unsigned long long int power(unsigned long long int a,unsigned long long int b) { if(b==0) return 1; unsigned long long int x=power(a,b/2);
return (((x*x)%mod)*((b&1)?a:1))%mod;}
开发者ID:dmncdr,项目名称:Algo_code,代码行数:2,代码来源:TPALIN.c
示例9: deriveBranch
//TODO remove pModel
CEvaluationNode* CDerive::deriveBranch(const CEvaluationNode* node, const CCopasiObject * pObject,
std::vector<const CEvaluationNode*>& env,
//std::vector<const CCopasiObject*>& objenv,
const CEvaluationTree* pTree,
bool simplify)
{
CEvaluationNode * newNode = NULL;
const CEvaluationNodeOperator * pENO = dynamic_cast<const CEvaluationNodeOperator*>(node);
if (pENO)
{
if (!pENO->getLeft() || !pENO->getRight()) return NULL;
CEvaluationNode * pLeftDeriv = deriveBranch(pENO->getLeft(), pObject, env, pTree, simplify);
if (!pLeftDeriv) return NULL;
CEvaluationNode * pRightDeriv = deriveBranch(pENO->getRight(), pObject, env, pTree, simplify);
if (!pRightDeriv) {delete pLeftDeriv; return NULL;}
// we now know that derivations of the left and right branch exist
switch ((CEvaluationNodeOperator::SubType) CEvaluationNode::subType(pENO->getType()))
{
case CEvaluationNodeOperator::MULTIPLY:
{
CEvaluationNode * pLeftCopy = copyBranch_var2obj(pENO->getLeft(), env);
CEvaluationNode * pRightCopy = copyBranch_var2obj(pENO->getRight(), env);
CEvaluationNode * tmpNode1 = multiply(pRightCopy, pLeftDeriv, simplify);
CEvaluationNode * tmpNode2 = multiply(pRightDeriv, pLeftCopy, simplify);
return add(tmpNode1, tmpNode2, simplify);
}
break;
case CEvaluationNodeOperator::DIVIDE:
{
CEvaluationNode * pLeftCopy = copyBranch_var2obj(pENO->getLeft(), env);
CEvaluationNode * pRightCopy = copyBranch_var2obj(pENO->getRight(), env);
//numerator
CEvaluationNode * tmpNode1 = multiply(pRightCopy, pLeftDeriv, simplify);
CEvaluationNode * tmpNode2 = multiply(pRightDeriv, pLeftCopy, simplify);
CEvaluationNode * minusNode = subtract(tmpNode1, tmpNode2, simplify);
minusNode->compile(NULL);
//denominator
CEvaluationNode * powerNode = power(copyBranch_var2obj(pENO->getRight(), env),
new CEvaluationNodeNumber(CEvaluationNodeNumber::INTEGER, "2"),
simplify);
return divide(minusNode, powerNode, simplify);
}
break;
case CEvaluationNodeOperator::PLUS:
return add(pLeftDeriv, pRightDeriv, simplify);
break;
case CEvaluationNodeOperator::MINUS:
return subtract(pLeftDeriv, pRightDeriv, simplify);
break;
case CEvaluationNodeOperator::POWER:
{
// b-1
CEvaluationNode * tmpNode = subtract(copyBranch_var2obj(pENO->getRight(), env),
new CEvaluationNodeNumber(CEvaluationNodeNumber::INTEGER, "1"),
simplify);
// a^(b-1)
CEvaluationNode * powerNode = power(copyBranch_var2obj(pENO->getLeft(), env), tmpNode, simplify);
// b*a'
tmpNode = multiply(copyBranch_var2obj(pENO->getRight(), env),
pLeftDeriv, simplify);
// ln a
CEvaluationNodeFunction * funcNode = new CEvaluationNodeFunction(CEvaluationNodeFunction::LOG, "ln");
funcNode->addChild(copyBranch_var2obj(pENO->getLeft(), env)); // add a
// a * b' * ln a
CEvaluationNode * tmpNode2 = multiply(copyBranch_var2obj(pENO->getLeft(), env),
multiply(pRightDeriv, funcNode, simplify),
simplify);
// b*a + a*b * ln a
CEvaluationNode * plusNode = add(tmpNode, tmpNode2, simplify);
// a^(b-1)*(b*a + a*b * ln a)
return multiply(powerNode, plusNode, simplify);
}
//.........这里部分代码省略.........
开发者ID:jonasfoe,项目名称:COPASI,代码行数:101,代码来源:CDerive.cpp
示例10: load_bmp
int load_bmp(char *file, struct image **res_image)
{
FILE *fp;
struct bitmap_file_header hdr;
struct bitmap_info_header infohdr;
struct image *img;
int num_pixels;
int j, pad;
if (!res_image) {
printf("**res_image pointer to pointer is not initialized!!!\n");
errno = -EAGAIN;
return -EAGAIN;
}
img = (struct image *) malloc(sizeof(*img));
if (!img)
return errno;
*res_image = img;
/* open the file */
if ((fp = fopen(file,"r")) == NULL)
return errno;
/* Read bitmap header */
if (fread(&hdr, sizeof(hdr), 1, fp) != 1)
goto error;
/* Check format */
if (hdr.id[0] != 'B' || hdr.id[1] != 'M') {
printf("%s is not a bitmap file in windows-format.\n", file);
errno = -EAGAIN;
goto error;
}
/* Read bitmap info header */
if (fread(&infohdr, sizeof(infohdr), 1, fp) != 1)
goto error;
if (infohdr.color_planes != 1 || infohdr.bits_per_pixel != 24 ||
infohdr.compression != 0 || infohdr.num_colors != 0 ||
infohdr.important_colors != 0) {
printf("The bmp image is not in a supported format!\n");
printf("The supported format requires: colorplanes == 0, 24 bits per "
"pixel, no compression, num-colors == 0 and important-colors == 0\n");
printf("But we got: colorplanes %u bits per pixel %u compression %u "
"num-colors %u important-colors %u\n", infohdr.color_planes,
infohdr.bits_per_pixel, infohdr.compression, infohdr.num_colors,
infohdr.important_colors);
errno = -EAGAIN;
goto error;
}
if (infohdr.num_colors == 0)
/* This means, the number of colors in the color-pallette is 2**bits_per_pixel */
infohdr.num_colors = power(2, infohdr.bits_per_pixel);
img->width = infohdr.width;
img->height = infohdr.height;
img->hor_res = infohdr.hor_res;
img->ver_res = infohdr.ver_res;
/* Now, move the pointer to the pixel-array */
if (fseek(fp, infohdr.hdrsize - sizeof(infohdr), SEEK_CUR))
goto error;
num_pixels = img->width * img->height;
img->pixels = (struct pixel *) malloc(sizeof(struct pixel)*num_pixels);
if (!img->pixels)
goto error;
pad = (4 - (img->width * 3) % 4) % 4;
for (j = 0; j < img->height; j++) {
if (fread(&img->pixels[j*img->width], 3, img->width, fp) != img->width)
goto error;
if (fseek(fp, pad, SEEK_CUR))
goto error;
}
fclose(fp);
return 0;
error:
fclose(fp);
return errno;
}
开发者ID:HappyRave,项目名称:SystInfo1,代码行数:90,代码来源:bitmapio.c
示例11: power_mpz
void power_mpz(elem &result, elem a, mpz_ptr n) const
{
int n1 = static_cast<int>(mpz_fdiv_ui(n, p1));
power(result,a,n1);
}
开发者ID:mikestillman,项目名称:practice2,代码行数:5,代码来源:aring-zzp.hpp
示例12: setUp
void Tester_68k::testSbcd() {
u16 opcode;
//MOVE.L #$12345689, D1
//MOVE.L #$f745ff78, D2
//MOVE #$4, CCR
//SBCD D2, D1
setUp();
opcode = 0x8100 | (1 << 9) | 2;
addWord(opcode);
addWord(0xffff);
power();
setCCR(0x4);
setRegD(1, 0x12345689);
setRegD(2, 0xf745ff78);
process();
check("SBCD D2, D1");
//MOVE.L #$12345605, D1
//MOVE.L #$f745ff05, D2
//MOVE #$4, CCR
//SBCD D2, D1
setUp();
opcode = 0x8100 | (1 << 9) | 2;
addWord(opcode);
addWord(0xffff);
power();
setCCR(0x4);
setRegD(1, 0x123456ff);
setRegD(2, 0xf745ffff);
process();
check("SBCD D2, D1 zero");
//MOVE.L #$12345634, D1
//MOVE.L #$f745ff45, D2
//MOVE #$10, CCR
//SBCD D2, D1
setUp();
opcode = 0x8100 | (1 << 9) | 2;
addWord(opcode);
addWord(0xffff);
power();
setCCR(0x10);
setRegD(1, 0x12345634);
setRegD(2, 0xf745ff45);
process();
check("SBCD D2, D1 neg");
//MOVE.L #$12345634, D1
//MOVE.L #$f745ff45, D2
//MOVE #$10, CCR
//SBCD D2, D1
setUp();
opcode = 0x8100 | (1 << 9) | 2;
addWord(opcode);
addWord(0xffff);
power();
setCCR(0x10);
setRegD(1, 0x123456a9);
setRegD(2, 0xf745ffff);
process();
check("SBCD D2, D1 overflow");
//MOVE.L #$3001, A1
//MOVE.L #$4001, A2
//MOVE.B #$a2, $3000
//MOVE.B #$19, $4000
//MOVE #$10, CCR
//SBCD -(A2), -(A1)
//MOVE.B $3000, D1
//MOVE.B $4000, D2
setUp();
opcode = 0x8100 | (1 << 9) | (1 << 3) | 2;
addWord(opcode);
addWord(0xffff);
power();
memoryblock.write(0x3000, 0xa2);
memoryblock.write(0x4000, 0x19);
setCCR(0x10);
setRegA(1, 0x3001);
setRegA(2, 0x4001);
process();
check("SBCD -(A2), -(A1)");
}
开发者ID:ctessler,项目名称:fork68k,代码行数:84,代码来源:sbcd.cpp
示例13: get_head_num
ui get_head_num(ull n, ui d)
{
return n / power(10, d - 2);
}
开发者ID:weezybusy,项目名称:cs50-solutions,代码行数:4,代码来源:credit.c
示例14: absval
void
absval(void)
{
int h;
save();
p1 = pop();
if (istensor(p1)) {
absval_tensor();
restore();
return;
}
if (isnum(p1)) {
push(p1);
if (isnegativenumber(p1))
negate();
restore();
return;
}
if (iscomplexnumber(p1)) {
push(p1);
push(p1);
conjugate();
multiply();
push_rational(1, 2);
power();
restore();
return;
}
// abs(1/a) evaluates to 1/abs(a)
if (car(p1) == symbol(POWER) && isnegativeterm(caddr(p1))) {
push(p1);
reciprocate();
absval();
reciprocate();
restore();
return;
}
// abs(a*b) evaluates to abs(a)*abs(b)
if (car(p1) == symbol(MULTIPLY)) {
h = tos;
p1 = cdr(p1);
while (iscons(p1)) {
push(car(p1));
absval();
p1 = cdr(p1);
}
multiply_all(tos - h);
restore();
return;
}
if (isnegativeterm(p1) || (car(p1) == symbol(ADD) && isnegativeterm(cadr(p1)))) {
push(p1);
negate();
p1 = pop();
}
push_symbol(ABS);
push(p1);
list(2);
restore();
}
开发者ID:AnderainLovelace,项目名称:ForumlaZ-WH,代码行数:70,代码来源:abs.cpp
示例15: calculate
double calculate(int numInputTokens, char **inputString){
int i;
double result = 0.0;
char *s;
struct DynArr *stack;
double num;
//set up the stack
stack = createDynArr(20);
// start at 1 to skip the name of the calculator calc
for(i=1;i < numInputTokens;i++)
{
s = inputString[i];
// Hint: General algorithm:
// (1) Check if the string s is in the list of operators.
// (1a) If it is, perform corresponding operations.
// (1b) Otherwise, check if s is a number.
// (1b - I) If s is not a number, produce an error.
// (1b - II) If s is a number, push it onto the stack
if(strcmp(s, "+") == 0){
add(stack);
printf("Adding\n");
}
else if(strcmp(s,"-") == 0){
subtract(stack);
printf("Subtracting\n");
}
else if(strcmp(s, "/") == 0){
divide(stack);
printf("Dividing\n");
}
else if(strcmp(s, "x") == 0){
multiply(stack);
printf("Multiplying\n");
}
else if(strcmp(s,"^") == 0){
power(stack);
printf("Power\n");
}
else if(strcmp(s, "^2") == 0){
squared(stack);
printf("Squaring\n");
}
else if(strcmp(s, "^3") == 0){
cubed(stack);
printf("Cubing\n");
}
else if(strcmp(s, "abs") == 0){
absoluteValue(stack);
printf("Absolute value\n");
}
else if(strcmp(s, "sqrt") == 0){
squareRoot(stack);
printf("Square root\n");
}
else if(strcmp(s, "exp") == 0){
exponential(stack);
printf("Exponential\n");
}
else if(strcmp(s, "ln") == 0){
naturalLog(stack);
printf("Natural Log\n");
}
else if(strcmp(s, "log") == 0){
logBase10(stack);
printf("Log\n");
}
else{
// FIXME: You need to develop the code here (when s is not an operator)
// Remember to deal with special values ("pi" and "e")
//check if not a number
if (isNumber(s, &num) == 0){
if (strcmp(s, "pi") == 0){
num = 3.14159265;
}
else if (strcmp(s, "e") == 0){
num = 2.7182818;
}
else{ //wrong
printf("%s is not valid (number or operator) \n", s);
break;
}
}
pushDynArr(stack, num);
}
} //end for
/* FIXME: You will write this part of the function (2 steps below)
* (1) Check if everything looks OK and produce an error if needed.
* (2) Store the final value in result and print it out.
*/
if (sizeDynArr(stack) != 1) {
printf("Incorrect count of numbers is detected! Calculations CANNOT be preformed. ");
return 0;
}
else {
result = topDynArr(stack);
}
//.........这里部分代码省略.........
开发者ID:TatyanaV,项目名称:Data-Structures-C-,代码行数:101,代码来源:calc.c
示例16: yybesselj
void
yybesselj(void)
{
double d;
int n;
N = pop();
X = pop();
push(N);
n = pop_integer();
// numerical result
if (isdouble(X) && n != (int) 0x80000000) {
//d = jn(n, X->u.d);
push_double(d);
return;
}
// bessej(0,0) = 1
if (iszero(X) && iszero(N)) {
push_integer(1);
return;
}
// besselj(0,n) = 0
if (iszero(X) && n != (int) 0x80000000) {
push_integer(0);
return;
}
// half arguments
if (N->k == NUM && MEQUAL(N->u.q.b, 2)) {
// n = 1/2
if (MEQUAL(N->u.q.a, 1)) {
push_integer(2);
push_symbol(PI);
divide();
push(X);
divide();
push_rational(1, 2);
power();
push(X);
sine();
multiply();
return;
}
// n = -1/2
if (MEQUAL(N->u.q.a, -1)) {
push_integer(2);
push_symbol(PI);
divide();
push(X);
divide();
push_rational(1, 2);
power();
push(X);
cosine();
multiply();
return;
}
// besselj(x,n) = (2/x) (n-sgn(n)) besselj(x,n-sgn(n)) - besselj(x,n-2*sgn(n))
push_integer(MSIGN(N->u.q.a));
SGN = pop();
push_integer(2);
push(X);
divide();
push(N);
push(SGN);
subtract();
multiply();
push(X);
push(N);
push(SGN);
subtract();
besselj();
multiply();
push(X);
push(N);
push_integer(2);
push(SGN);
multiply();
subtract();
besselj();
subtract();
return;
}
//.........这里部分代码省略.........
开发者ID:AnderainLovelace,项目名称:Taumath,代码行数:101,代码来源:besselj.c
示例17: get_num_branches
bool get_num_branches(contains_app& x, expr* fml, rational& nb) override {
unsigned sz = m_bv.get_bv_size(x.x());
nb = power(rational(2), sz);
return true;
}
开发者ID:NikolajBjorner,项目名称:z3,代码行数:5,代码来源:qe_bv_plugin.cpp
示例18: main
/* Am folosit Fibonacci generalizat */
int main(int args, char** argv) {
int n, m, k, i, j;
long long **a, *initial;
FILE *fr, *fw;
fr = fopen("date.in", "r");
fw = fopen("date.out", "w");
fscanf(fr, "%d", &n);
fscanf(fr, "%d", &m);
fscanf(fr, "%d", &k);
a = (long long**)calloc((k + 1), sizeof(long long*));
for(i = 0; i <= k; i++) {
a[i] = (long long *)calloc((k + 1), sizeof(long long));
}
initial = (long long *)calloc((k + 1), sizeof(long long));
/* Pe vectorul termenilor initiali se pun puteri ale lui 2 */
for(i = 0; i <= k; i++) {
initial[i] = pow(2, i);
}
/* In matrice se pune 1 pe diagonala de deasupra celei principale (pentru a
se avansa cu cate un termen la fiecare inmultire si a se lua in considerare
doar ultimi k) si 1 pe ultima linie (al k + 1 termen se calculeaza ca suma
celor k + 1 termeni de la pasul anterior) */
for(i = 0; i < k + 1; i++) {
for(j = 0; j < k + 1; j++) {
if(j == i + 1) {
a[i][j] = 1;
}
if(i == k) {
a[i][j] = 1;
}
}
}
/* Se ridica a la n - k in vederea calculului celui de-al n-lea termen */
a = logPowMatrix(a, n - k, k);
/* Se inmulteste vectorul intial cu matricea a */
long long result = 0;
for(i = 0; i <= k; i++) {
result += ((a[k][i] * initial[i]) % MOD);
}
/* Rezultatul se ridica la puterea numarul de coloane pt numarul total de
cadre */
result = power(result, m);
fprintf(fw, "%lli", result);
/* Se elibereaza memoria */
for(i = 0; i <= k; i++) {
free(a[i]);
}
free(a);
free(initial);
fclose(fr);
fclose(fw);
return 0;
}
开发者ID:dariusjam,项目名称:Tema-1-PA,代码行数:71,代码来源:p2.c
示例19: main
int main(void)
{
printf("2 ^ 4 = %.2f\n", power(2, 4));
return 0;
}
开发者ID:algking,项目名称:algorithms-in-c,代码行数:5,代码来源:main.c
示例20: power
double power(double x, long n)
{
if(n == 0) return 1;
if(n < 0) return power ( 1 / x, -n);
return x * power(x, n - 1);
}
开发者ID:orcchg,项目名称:StudyProjects,代码行数:6,代码来源:main.cpp
注:本文中的power函数示例由纯净天空整理自Github/MSDocs等源码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。 |
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