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C++ MALLOCARRAY函数代码示例

原作者: [db:作者] 来自: [db:来源] 收藏 邀请

本文整理汇总了C++中MALLOCARRAY函数的典型用法代码示例。如果您正苦于以下问题:C++ MALLOCARRAY函数的具体用法?C++ MALLOCARRAY怎么用?C++ MALLOCARRAY使用的例子?那么恭喜您, 这里精选的函数代码示例或许可以为您提供帮助。



在下文中一共展示了MALLOCARRAY函数的20个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于我们的系统推荐出更棒的C++代码示例。

示例1: srf_img_init

static void
srf_img_init(struct srf_img * const imgP,
             uint16_t         const width,
             uint16_t         const height) {

    struct srf_img_header * const headerP = &imgP->header;
    struct srf_img_alpha *  const alphaP  = &imgP->alpha;
    struct srf_img_data *   const dataP   = &imgP->data;

    headerP->_ints[0]   = 0;
    headerP->_ints[1]   = 16;
    headerP->_ints[2]   = 0;
    headerP->height     = height;
    headerP->width      = width;
    headerP->_bytes[0]  = 16;
    headerP->_bytes[1]  = 8;
    headerP->line_len   = width * 2;
    headerP->zeros      = 0;

    alphaP->type     = 11;
    alphaP->data_len = height * width;
    MALLOCARRAY(alphaP->data, alphaP->data_len);

    if (!alphaP->data)
        pm_error("Could not allocate buffer for %u bytes of alpha",
                 alphaP->data_len);

    dataP->type     = 1;
    dataP->data_len = height * width * 2;
    MALLOCARRAY(dataP->data, dataP->data_len / 2);

    if (!dataP->data)
        pm_error("Could not allocation buffer for %u units of data",
                 dataP->data_len);
}
开发者ID:chneukirchen,项目名称:netpbm-mirror,代码行数:35,代码来源:srf.c


示例2: openFiles

static void
openFiles(struct CmdlineInfo const cmdline,
          unsigned int *     const fileCtP,
          struct pam **      const imgPamP,
          const char ***     const namesP) {

    unsigned int fileCt;
    struct pam * imgPam;
    const char ** names;

    fileCt = cmdline.nFiles > 0 ? cmdline.nFiles : 1;

    MALLOCARRAY(imgPam, fileCt);
    MALLOCARRAY(names, fileCt);

    if (!imgPam || !names)
        pm_error("out of memory");

    if (cmdline.nFiles > 0) {
        unsigned int i;

        for (i = 0; i < cmdline.nFiles; ++i) {
            imgPam[i].file = pm_openr(cmdline.inFileName[i]);
            names[i] = strdup(cmdline.inFileName[i]);
        }
    } else {
        imgPam[0].file = stdin;
        names[0] = strdup("stdin");
    }

    *fileCtP = fileCt;
    *imgPamP = imgPam;
    *namesP  = names;
}
开发者ID:chneukirchen,项目名称:netpbm-mirror,代码行数:34,代码来源:pnmmontage.c


示例3: findpack

static void 
findpack(struct pam * const imgs,
         unsigned int const imgCt,
         Coord **     const coordsP,
         unsigned int const quality,
         unsigned int const qfactor) {

    Coord * coords;  /* malloc'ed array */
    unsigned int minarea;
    unsigned int i;
    unsigned int rdiv;
    unsigned int cdiv;
    Rectangle * current;  /* malloc'ed array */
    unsigned int z;
    Coord c;

    MALLOCARRAY(coords, imgCt);
  
    if (!coords)
        pm_error("Out of memory allocating %u-element coords array", imgCt);

    z = UINT_MAX;  /* initial value */
    c.x = 0; c.y = 0;  /* initial value */

    if (quality > 1) {
        unsigned int realMinarea;
        for (realMinarea = i = 0; i < imgCt; ++i)
            realMinarea += imgs[i].height * imgs[i].width;
        minarea = realMinarea * qfactor / 100;
    } else
        minarea = UINT_MAX - 1;

    /* It's relatively easy to show that, if all the images
     * are multiples of a particular size, then a best
     * packing will always align the images on a grid of
     * that size.
     *
     * This speeds computation immensely.
     */
    for (rdiv = imgs[0].height, i = 1; i < imgCt; ++i)
        rdiv = gcf(imgs[i].height, rdiv);

    for (cdiv = imgs[0].width, i = 1; i < imgCt; ++i)
        cdiv = gcf(imgs[i].width, cdiv);

    MALLOCARRAY(current, imgCt);

    for (i = 0; i < imgCt; ++i) {
        current[i].size.x = imgs[i].width;
        current[i].size.y = imgs[i].height;
    }
    recursefindpack(current, c, coords, minarea, &z, 0, imgCt, cdiv, rdiv,
                    quality, qfactor);

    free(current);

    *coordsP = coords;
}
开发者ID:chneukirchen,项目名称:netpbm-mirror,代码行数:58,代码来源:pnmmontage.c


示例4: newRGBMapData

static void
newRGBMapData(RGBMap *     const rgbP,
              unsigned int const size) {

    rgbP->used = 0;
    rgbP->size = size;
    rgbP->compressed = FALSE;
    MALLOCARRAY(rgbP->red, size);
    MALLOCARRAY(rgbP->grn, size);
    MALLOCARRAY(rgbP->blu, size);

    if (rgbP->red == NULL || rgbP->grn == NULL || rgbP->blu == NULL)
        pm_error("Out of memory allocating %u pixels", size);
}
开发者ID:Eleanor66613,项目名称:CS131,代码行数:14,代码来源:image.c


示例5: findpack

static void 
findpack(struct pam *imgs, int n, coord *coords)
{
  int minarea;
  int i;
  int rdiv;
  int cdiv;
  int minx = -1;
  int miny = -1;
  coord *current;
  coord *set;
  int z = INT_MAX;
  coord c = { 0, 0 };

  if (quality > 1)
  {
    for (minarea = i = 0; i < n; ++i)
      minarea += imgs[i].height * imgs[i].width,
      minx = imax(minx, imgs[i].width),
      miny = imax(miny, imgs[i].height);

    minarea = minarea * qfactor / 100;
  }
  else
  {
    minarea = INT_MAX - 1;
  }

  /* It's relatively easy to show that, if all the images
   * are multiples of a particular size, then a best
   * packing will always align the images on a grid of
   * that size.
   *
   * This speeds computation immensely.
   */
  for (rdiv = imgs[0].height, i = 1; i < n; ++i)
    rdiv = gcd(imgs[i].height, rdiv);

  for (cdiv = imgs[0].width, i = 1; i < n; ++i)
    cdiv = gcd(imgs[i].width, cdiv);

  MALLOCARRAY(current, n);
  MALLOCARRAY(set, n);
  for (i = 0; i < n; ++i)
    set[i].x = imgs[i].width,
    set[i].y = imgs[i].height;
  recursefindpack(current, c, set, coords, minarea, &z, 0, n, cdiv, rdiv);
}
开发者ID:cjd8363,项目名称:Global-Illum,代码行数:48,代码来源:pnmmontage.c


示例6: ppmd_read_font

void
ppmd_read_font(FILE *                        const ifP,
               const struct ppmd_font **     const fontPP) {

    unsigned int relativeCodePoint;
    struct ppmd_glyph * glyphTable;
    struct ppmd_font * fontP;

    MALLOCVAR(fontP);
    if (fontP == NULL)
        pm_error("Insufficient memory for font header");

    readFontHeader(ifP, &fontP->header);

    MALLOCARRAY(glyphTable, fontP->header.characterCount);
    if (glyphTable == NULL)
        pm_error("Insufficient memory to store %u characters",
                 fontP->header.characterCount);

    for (relativeCodePoint = 0;
         relativeCodePoint < fontP->header.characterCount;
         ++relativeCodePoint) {

        readCharacter(ifP, &glyphTable[relativeCodePoint]);
    }
    fontP->glyphTable = glyphTable;
    *fontPP = fontP;
}
开发者ID:Eleanor66613,项目名称:CS131,代码行数:28,代码来源:ppmdfont.c


示例7: analyzeDistribution

static void
analyzeDistribution(struct pam *          const inpamP,
                    bool                  const verbose,
                    const unsigned int ** const histogramP,
                    struct range *        const rangeP) {
/*----------------------------------------------------------------------------
   Find the distribution of the sample values -- minimum, maximum, and
   how many of each value -- in input image *inpamP, whose file is
   positioned to the raster.

   Return the minimum and maximum as *rangeP and the frequency
   distribution as *histogramP, an array such that histogram[i] is the
   number of pixels that have sample value i.

   Assume the file is positioned to the raster upon entry and leave
   it positioned at the same place.
-----------------------------------------------------------------------------*/
    unsigned int row;
    tuple * inrow;
    tuplen * inrown;
    unsigned int * histogram;  /* malloced array */
    unsigned int i;

    pm_filepos rasterPos;      /* Position in input file of the raster */

    pm_tell2(inpamP->file, &rasterPos, sizeof(rasterPos));

    inrow = pnm_allocpamrow(inpamP);
    inrown = pnm_allocpamrown(inpamP);
    MALLOCARRAY(histogram, inpamP->maxval+1);
    if (histogram == NULL)
        pm_error("Unable to allocate space for %lu-entry histogram",
                 inpamP->maxval+1);

    /* Initialize histogram -- zero occurrences of everything */
    for (i = 0; i <= inpamP->maxval; ++i)
        histogram[i] = 0;

    initRange(rangeP);

    for (row = 0; row < inpamP->height; ++row) {
        unsigned int col;
        pnm_readpamrow(inpamP, inrow);
        pnm_normalizeRow(inpamP, inrow, NULL, inrown);
        for (col = 0; col < inpamP->width; ++col) {
            ++histogram[inrow[col][0]];
            addToRange(rangeP, inrown[col][0]);
        }
    }
    *histogramP = histogram;

    pnm_freepamrow(inrow);
    pnm_freepamrown(inrown);

    pm_seek2(inpamP->file, &rasterPos, sizeof(rasterPos));

    if (verbose)
        pm_message("Pixel values range from %f to %f",
                   rangeP->min, rangeP->max);
}
开发者ID:chneukirchen,项目名称:netpbm-mirror,代码行数:60,代码来源:pamthreshold.c


示例8: pamd_fill_create

struct fillobj *
pamd_fill_create(void) {

    fillobj * fillObjP;
    struct fillState * stateP;

    MALLOCVAR(fillObjP);
    if (fillObjP == NULL)
        pm_error("out of memory allocating a fillhandle");

    MALLOCVAR(stateP);
    if (stateP == NULL)
        pm_error("out of memory allocating a fillhandle");

    stateP->n = 0;
    stateP->size = SOME;
    MALLOCARRAY(stateP->coords, stateP->size);
    if (stateP->coords == NULL)
        pm_error("out of memory allocating a fillhandle");
    stateP->curedge = 0;

    fillObjP->stateP = stateP;
    
    /* Turn off line clipping. */
    /* UGGH! We must eliminate this global variable */
    oldclip = pamd_setlineclip(0);
    
    return fillObjP;
}
开发者ID:chneukirchen,项目名称:netpbm-mirror,代码行数:29,代码来源:libpamd.c


示例9: newRGBImage

Image *
newRGBImage(unsigned int const width,
            unsigned int const height,
            unsigned int const depth) {
    
    unsigned int const pixlen = depth > 0 ? (depth + 7) / 8 : 1;
        /* Special case for "zero" depth image, which is sometimes
           interpreted as "one color"
        */
    unsigned int const numcolors = depthToColors(depth);

    Image * imageP;
    
    MALLOCVAR_NOFAIL(imageP);
    imageP->type   = IRGB;
    newRGBMapData(&imageP->rgb, numcolors);
    imageP->width  = width;
    imageP->height = height;
    imageP->depth  = depth;
    imageP->pixlen = pixlen;

    if (UINT_MAX / width / height < pixlen)
        pm_error("Image dimensions %u x %u x %u are too big to compute.",
                 width, height, pixlen);
    MALLOCARRAY(imageP->data, width * height * pixlen);
    if (imageP->data == NULL)
        pm_error("Unable to allocate %u x %u x %u raster array",
                 width, height, pixlen);

    return imageP;
}
开发者ID:Eleanor66613,项目名称:CS131,代码行数:31,代码来源:image.c


示例10: newBitImage

Image *
newBitImage(unsigned int const width,
            unsigned int const height) {

    unsigned int const linelen = (width + 7) / 8;

    Image * imageP;

    MALLOCVAR_NOFAIL(imageP);

    imageP->type = IBITMAP;
    newRGBMapData(&imageP->rgb, 2);
    imageP->rgb.red[0] = imageP->rgb.grn[0] = imageP->rgb.blu[0] = 65535;
    imageP->rgb.red[1] = imageP->rgb.grn[1] = imageP->rgb.blu[1] = 0;
    imageP->rgb.used = 2;
    imageP->width = width;
    imageP->height = height;
    imageP->depth = 1;

    if (UINT_MAX / linelen < height)
        pm_error("Image dimensions too big to compute: %u x %u",
                 linelen, height);
    MALLOCARRAY(imageP->data, linelen * height);

    if (imageP->data == NULL)
        pm_error("Out of memory allocating array of %u x %u", linelen, height);

    return imageP;
}
开发者ID:Eleanor66613,项目名称:CS131,代码行数:29,代码来源:image.c


示例11: newTrueImage

Image *
newTrueImage(unsigned int const width,
             unsigned int const height) {

    unsigned int const pixlen = 3;
    
    Image * imageP;

    MALLOCVAR_NOFAIL(imageP);
    imageP->type     = ITRUE;
    imageP->rgb.used = 0;
    imageP->rgb.size = 0;
    imageP->width    = width;
    imageP->height   = height;
    imageP->depth    = 24;
    imageP->pixlen   = 3;

    if (UINT_MAX / width / height < pixlen)
        pm_error("Image dimensions %u x %u x %u are too big to compute.",
                 width, height, pixlen);
    MALLOCARRAY(imageP->data, width * height * pixlen);
    if (imageP->data == NULL)
        pm_error("Unable to allocate %u x %u x %u raster array",
                 width, height, pixlen);

    return imageP;
}
开发者ID:Eleanor66613,项目名称:CS131,代码行数:27,代码来源:image.c


示例12: createLongOptsArray

static struct optionx *
createLongOptsArray(struct optionDesc * const optionDescArray,
                    unsigned int        const numOptions) {

    struct optionx * longopts; 

    MALLOCARRAY(longopts, numOptions+1);
    if (longopts != NULL) {
        unsigned int i;

        for (i = 0; i < numOptions; ++i) {
            longopts[i].name = optionDescArray[i].name;
            /* If the option takes a value, we say it is optional even
               though it never is.  That's because if we say it is
               mandatory, getopt_long_only() pretends it doesn't even
               recognize the option if the user doesn't give a value.
               We prefer to generate a meaningful error message when
               the user omits a required option value.
            */
            longopts[i].has_arg = 
                optionDescArray[i].type == OPTTYPE_FLAG ? 
                no_argument : optional_argument;
            longopts[i].flag = NULL;
            longopts[i].val = i;
        }
        longopts[numOptions].name = 0;
        longopts[numOptions].has_arg = 0;
        longopts[numOptions].flag = 0;
        longopts[numOptions].val = 0;
    }
    return longopts;
}
开发者ID:BehnamEmamian,项目名称:openholdembot,代码行数:32,代码来源:cmdline_parser.c


示例13: ppm_writeppmrowraw

static void
ppm_writeppmrowraw(FILE *        const fileP,
                   const pixel * const pixelrow,
                   unsigned int  const cols,
                   pixval        const maxval ) {

    unsigned int const bytesPerSample = maxval < 256 ? 1 : 2;
    unsigned int const bytesPerRow    = cols * 3 * bytesPerSample;

    unsigned char * rowBuffer;
    ssize_t rc;

    MALLOCARRAY(rowBuffer, bytesPerRow);

    if (rowBuffer == NULL)
        pm_error("Unable to allocate memory for row buffer "
                 "for %u columns", cols);

    if (maxval < 256)
        format1bpsRow(pixelrow, cols, rowBuffer);
    else
        format2bpsRow(pixelrow, cols, rowBuffer);

    rc = fwrite(rowBuffer, 1, bytesPerRow, fileP);

    if (rc < 0)
        pm_error("Error writing row.  fwrite() errno=%d (%s)",
                 errno, strerror(errno));
    else if (rc != bytesPerRow)
        pm_error("Error writing row.  Short write of %u bytes "
                 "instead of %u", rc, bytesPerRow);

    free(rowBuffer);
}
开发者ID:Eleanor66613,项目名称:CS131,代码行数:34,代码来源:libppm2.c


示例14: xmlrpc_authcookie_set

void
xmlrpc_authcookie_set(xmlrpc_env *const envP,
                      const char *const username,
                      const char *const password) {

    char *unencoded;
    xmlrpc_mem_block *token;

    XMLRPC_ASSERT_ENV_OK(envP);
    XMLRPC_ASSERT_PTR_OK(username);
    XMLRPC_ASSERT_PTR_OK(password);

    /* Create unencoded string/hash. */

    MALLOCARRAY(unencoded, (strlen(username) + strlen(password) + 1 + 1));
    sprintf(unencoded, "%s:%s", username, password);

    /* Create encoded string. */
    token = xmlrpc_base64_encode_without_newlines(
            envP, (unsigned char *) unencoded, strlen(unencoded));
    if (!envP->fault_occurred) {
        /* Set HTTP_COOKIE_AUTH to the character representation of the
           encoded string.
        */
#if HAVE_SETENV
        setenv("HTTP_COOKIE_AUTH",
               XMLRPC_MEMBLOCK_CONTENTS(char, token),
               1);
#endif
        xmlrpc_mem_block_free(token);
    }
开发者ID:arssivka,项目名称:naomech,代码行数:31,代码来源:xmlrpc_authcookie.c


示例15: at_bitmap_init

at_bitmap_type
at_bitmap_init(unsigned char * area,
               unsigned short width,
               unsigned short height,
               unsigned int planes) {

    at_bitmap_type bitmap;
    
    if (area)
        bitmap.bitmap = area;
    else {
        if (width * height == 0)
            bitmap.bitmap = NULL;
        else {
            MALLOCARRAY(bitmap.bitmap, width * height * planes);
            if (bitmap.bitmap == NULL)
                pm_error("Unable to allocate %u x %u x %u bitmap array",
                         width, height, planes);
            bzero(bitmap.bitmap,
                  width * height * planes * sizeof(unsigned char));
        }
    }
    
    bitmap.width  = width;
    bitmap.height = height;
    bitmap.np     =  planes;

    return bitmap;  
}
开发者ID:Eleanor66613,项目名称:CS131,代码行数:29,代码来源:bitmap.c


示例16: abel

/* ----------------------------------------------------------------------------
** procedure for making the Abel integration for deconvolution of the image
**        y    <-> array with values for deconvolution and results
**        N    <-  width of the array
**        adl  <-  array with pre-calculated weighting factors
*/
static void 
abel ( float *y, int N, double *adl)
{
    register int n;
    double *rho, *rhop;       /* results and new index                       */
    float  *yp;               /* new indizes for the y-array                 */

    MALLOCARRAY(rho, N);
    if( !rho )
        pm_error( "out of memory" );
    rhop = rho;
    yp  = y;

    for (n=0 ; n<N ; n++)
    {
        *(rhop++) = ((*yp++) - Sum(n,rho,N,adl))/(adl[n*N+n]);
/*    *(rhop++) = ((*yp++) - Sum(n,rho,N))/(dr(n,n+0.5,N));  old version */
        if ( *rhop < 0.0 ) *rhop = 0.0;         /*  error correction !       */
/*   if (n > 2) rhop[n-1] = (rho[n-2]+rho[n-1]+rho[n])/3.0;  stabilization*/
    }
    for (n=0 ; n<N ; n++)
        {
            if (( n>=1 )&&( n<N-1 ))
	       (*y++) = ((rho[n-1]*0.5+rho[n]+rho[n+1]*0.5)/2.0);/*1D median filter*/
            else (*y++) = rho[n];
        }
    free(rho);
}
开发者ID:Eleanor66613,项目名称:CS131,代码行数:34,代码来源:pgmabel.c


示例17: extractArguments

static void
extractArguments(struct cmdlineParserCtl * const cpP,
                 unsigned int              const argc,
                 const char **             const argv) {
    
    cpP->numArguments = argc - getopt_argstart();
    MALLOCARRAY(cpP->argumentArray, cpP->numArguments);

    if (cpP->argumentArray == NULL) {
        fprintf(stderr, "Unable to allocate memory for argument array "
                "(%u arguments)\n", cpP->numArguments);
        abort();
    } else {
        unsigned int i;

        for (i = 0; i < cpP->numArguments; ++i) {
            cpP->argumentArray[i] = strdup(argv[getopt_argstart() + i]);
            if (cpP->argumentArray[i] == NULL) {
                fprintf(stderr, "Unable to allocate memory for Argument %u\n",
                        i);
                abort();
            }
        }
    }
}
开发者ID:BehnamEmamian,项目名称:openholdembot,代码行数:25,代码来源:cmdline_parser.c


示例18: createHist

static void
createHist(bool             const colorWanted[3],
           unsigned int     const histWidth,
           unsigned int * (* const histP)[3]) {
/*----------------------------------------------------------------------------
   Allocate the histogram arrays and set each slot count to zero.
-----------------------------------------------------------------------------*/
    unsigned int color;

    for (color = 0; color < 3; ++color) {
        if (colorWanted[color]) {
            unsigned int * hist;
            unsigned int i;
            MALLOCARRAY(hist, histWidth);
            if (hist == NULL)
                pm_error("Not enough memory for histogram arrays (%u bytes)",
                         histWidth * (unsigned)sizeof(hist[0]) * 3);

            for (i = 0; i < histWidth; ++i)
                hist[i] = 0;
            (*histP)[color] = hist;
        } else
            (*histP)[color] = NULL;
    }
}
开发者ID:chneukirchen,项目名称:netpbm-mirror,代码行数:25,代码来源:pnmhistmap.c


示例19: parseCommandLine

static void
parseCommandLine(int argc, char ** argv,
                 struct cmdlineInfo * const cmdlineP) {
/*----------------------------------------------------------------------------
  Convert program invocation arguments (argc,argv) into a format the 
  program can use easily, struct cmdlineInfo.  Validate arguments along
  the way and exit program with message if invalid.

  Note that some string information we return as *cmdlineP is in the storage 
  argv[] points to.
-----------------------------------------------------------------------------*/
    optEntry * option_def;
        /* Instructions to OptParseOptions3 on how to parse our options.
         */
    optStruct3 opt;

    unsigned int maxvalSpec;
    unsigned int option_def_index;

    MALLOCARRAY(option_def, 100);

    option_def_index = 0;   /* incremented by OPTENTRY */
    OPTENT3(0,   "maxval",    OPT_UINT, &cmdlineP->maxval, &maxvalSpec,    0);

    opt.opt_table = option_def;
    opt.short_allowed = false;  /* We have no short (old-fashioned) options */
    opt.allowNegNum = false;  /* We have no parms that are negative numbers */

    optParseOptions3(&argc, argv, opt, sizeof(opt), 0);
        /* Uses and sets argc, argv, and some of *cmdlineP and others. */

    if (!maxvalSpec)
        cmdlineP->maxval = PPM_MAXMAXVAL;
    else {
        if (cmdlineP->maxval > PPM_OVERALLMAXVAL)
            pm_error("The value you specified for -maxval (%u) is too big.  "
                     "Max allowed is %u", cmdlineP->maxval, PPM_OVERALLMAXVAL);
        
        if (cmdlineP->maxval < 1)
            pm_error("You cannot specify 0 for -maxval");
    }    

    if (argc-1 < 3)
        pm_error("Need 3 arguments: color, width, height.");
    else if (argc-1 > 3)
        pm_error("Only 3 arguments allowed: color, width, height.  "
                 "You specified %d", argc-1);
    else {
        cmdlineP->color = ppm_parsecolor(argv[1], cmdlineP->maxval);
        cmdlineP->cols = atoi(argv[2]);
        cmdlineP->rows = atoi(argv[3]);
        if (cmdlineP->cols <= 0)
            pm_error("width argument must be a positive number.  You "
                     "specified '%s'", argv[2]);
        if (cmdlineP->rows <= 0)
            pm_error("height argument must be a positive number.  You "
                     "specified '%s'", argv[3]);
    }
}
开发者ID:jhbsz,项目名称:DIR-850L_A1,代码行数:59,代码来源:ppmmake.c


示例20: load

static void
load(const struct pam * const pamP,
     unsigned int       const hstep,
     sample ***         const pixelsP,
     unsigned int *     const hsamplesP) {
/*----------------------------------------------------------------------------
  read file into memory, returning array of rows
-----------------------------------------------------------------------------*/
    unsigned int const hsamples = 1 + (pamP->width - 1) / hstep;
        /* use only this many cols */

    unsigned int row;
    tuple *  tuplerow;
    sample ** pixels;

    tuplerow = pnm_allocpamrow(pamP);
    
    MALLOCARRAY(pixels, pamP->height);
    if (pixels == NULL)
        pm_error("Unable to allocate array of %u pixel rows",
                 pamP->height);

    if (pixels == NULL)
        pm_error("Unable to allocate array of %u rows", pamP->height);

    for (row = 0; row < pamP->height; ++row) {
        unsigned int i;
        unsigned int col;

        pnm_readpamrow(pamP, tuplerow);

        MALLOCARRAY(pixels[row], hsamples);
        if (pixels[row] == NULL)
            pm_error("Unable to allocate %u-sample array for Row %u",
                     hsamples, row);

        /* save every hstep'th column */
        for (i = col = 0; i < hsamples; ++i, col += hstep)
            pixels[row][i] = tuplerow[col][0];
    }

    pnm_freepamrow(tuplerow);

    *hsamplesP = hsamples;
    *pixelsP   = pixels;
}
开发者ID:jhbsz,项目名称:DIR-850L_A1,代码行数:46,代码来源:pamtilt.c



注:本文中的MALLOCARRAY函数示例由纯净天空整理自Github/MSDocs等源码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。


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C++ MALLOCATE函数代码示例发布时间:2022-05-30
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C++ MALLOC函数代码示例发布时间:2022-05-30
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