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在程序设计中,为了用户的体验,最后把程序出现的黄页错误归结到统一的页面上
下面是我在程序代码中的错误页面设计: 它由页面ErrorPage.aspx实现. HTML代码如下: <html xmlns="http://www.w3.org/1999/xhtml" > <head runat="server"> <title>网站错误页面</title> <link href="ASPNET2.0BaseCss.css" type="text/css" rel="stylesheet"> </head> <body> <form id="form1" runat="server"> <table cellSpacing="0" cellPadding="0" width="75%" align="center" border="0"> <TR> <TD bgColor="#d8e4f8" colSpan="2" height="4"></TD> </TR> <tr> <td vAlign="top" width="153" bgColor="#eff7f4"><asp:image id="RegisterImage" Runat="server" Width="153"></asp:image></td> <TD align="center" bgColor="#ebebff"> <TABLE cellSpacing="4" cellPadding="0" width="580"> <TR vAlign="top" height="*"> <TD colSpan="2" height="148"> <TABLE cellSpacing="0" cellPadding="4" width="100%" border="0"> <tr> <td><a><b>错误页:</b></a> <a><font color="red"><%=Request ["ErrorUrl"]%></font></a></td> </tr> <TR> <TD> <HR noShade SIZE="1"> </TD> </TR> <TR> <td class="Normal" valign="top"> <a><b>错误信息:</b></a> <br> <a><font color="red"><%=Request ["ErrorMsg"]%></font></a> </td> </TR> <tr> <td height="220"></td> </tr> <tr> <td vAlign="middle" align="center" height="80"><asp:button id="BackBtn" runat="server" Width="100" CssClass="ButtonCss" Text="返回" OnClick="BackBtn_Click"></asp:button></td> </tr> <tr> <td colspan="2" width="100%"> <hr size="1"> </td> </tr> </TABLE> </TD> </TR> </TABLE> </TD> </tr> </table> </form> </body> </html> 当应用程序发生错误时,跳转到该页,并在该页面上提示错误信息.用户单击返回按钮返回到发生错误的页面.在后置代码中这样写到: using System; using System.Data; using System.Configuration; using System.Collections; using System.Web; using System.Web.Security; using System.Web.UI; using System.Web.UI.WebControls; using System.Web.UI.WebControls.WebParts; using System.Web.UI.HtmlControls; public partial class DesktopModules_ErrorPage : System.Web.UI.Page { protected void Page_Load(object sender, EventArgs e) { if(!IsPostBack) { //保存发生错误页面的地址,在这里如果Request.UrlReferrer.ToString()报错,就换成Convert.ToString(Request.UrlReferrer) ViewState["BackURL"] = Request.UrlReferrer.ToString(); } } protected void BackBtn_Click(object sender,System.EventArgs e) { //返回发生错误的页面 Response.Redirect(ViewState["BackURL"].ToString()); } } |
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