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map数据结构key-value的数据结构,又叫字典或关联数组
var map1 map[keytype]valuetype var a map[string]string var a map[string]int var a map[int]string var a map[string]map[string]string 备注:声明是不会分配内存的,初始化需要make 样例一: func testMap() { var a map[string]string a = make(map[string]string, 10) a["abc"] = "efg" a["abc"] = "efg" a["abc1"] = "efg" fmt.Println(a) } 样例二: func testMap() { a := make(map[string]string, 10) a["abc"] = "efg" a["abc"] = "efg" a["abc1"] = "efg" fmt.Println(a) } 样例三: func testMap() { var a map[string]string = map[string]string{ "key": "value", } a["abc"] = "efg" a["abc"] = "efg" a["abc1"] = "efg" fmt.Println(a) }
var a map[string]string = map[string]string{"hello": "world"} a = make(map[string]string, 10) 插入和更新:a[“hello”] = “world” 查找:Val, ok := a[“hello”] 遍历: for k, v := range a { fmt.Println(k,v) } 删除:delete(a, “hello”) 长度:len(a) func trans(a map[string]map[string]string) { for k, v := range a { fmt.Println(k) for k1, v1 := range v { fmt.Println("\t", k1, v1) } } } func testMap4() { a := make(map[string]map[string]string, 100) a["key1"] = make(map[string]string) a["key1"]["key2"] = "abc" a["key1"]["key3"] = "abc" a["key1"]["key4"] = "abc" a["key1"]["key5"] = "abc" a["key2"] = make(map[string]string) a["key2"]["key2"] = "abc" a["key2"]["key3"] = "abc" trans(a) delete(a, "key1") fmt.Println() trans(a) fmt.Println(len(a)) }
func testMap2() { a := make(map[string]map[string]string, 100) a["key1"] = make(map[string]string) a["key1"]["key2"] = "abc" a["key1"]["key3"] = "abc" a["key1"]["key4"] = "abc" a["key1"]["key5"] = "abc" fmt.Println(a) }
func testMapSlice() { s := make([]map[string]int, 10) for i := 0; i < len(s); i++ { s[i] = make(map[string]int, 100) } s[0]["abc"] = 100 s[0]["qwe"] = 100 s[5]["abc"] = 100 fmt.Println(s) } 备注:上面第一次make是切片的长度,第二次make是map的容量
a. 先获取所有key,把key进行排序 b. 按照排序好的key,进行遍历 func testMapSort() { var a map[int]int a = make(map[int]int, 5) a[8] = 10 a[3] = 10 a[2] = 10 a[1] = 10 a[18] = 10 var keys []int for k, _ := range a { keys = append(keys, k) //fmt.Println(k, v) } sort.Ints(keys) for _, v := range keys { fmt.Println(v, a[v]) } }
初始化另外一个map,把key、value互换即可 func test() { var a map[string]int var b map[int]string a = make(map[string]int, 5) b = make(map[int]string, 5) a["abc"] = 101 a["efg"] = 10 fmt.Println(a) for k, v := range a { b[v] = k } fmt.Println(b) }
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