1  int code = int.Parse(this.TextBox1.Text);//图片编码
 2         string value = this.FileUpload1.PostedFile.FileName.ToString();//图片路径
 3         string type = value.Substring(value.LastIndexOf(".") + 1);
 4         FileStream fs = File.OpenRead(value);
 5         byte[] content = new byte[fs.Length];
 6         fs.Read(content, 0, content.Length);
 7         fs.Close();
 8 
 9         string sqlconfrom = System.Web.Configuration.WebConfigurationManager.ConnectionStrings["sqlConnectionStrings"].ToString();
10         SqlConnection con = new SqlConnection(sqlconfrom);
11         string sql = " insert into Image_Table values ( '1',@content,@code ) ";
12 
13         SqlCommand cmd = new SqlCommand(sql, con);
14         cmd.Parameters.Add(new SqlParameter("@content", SqlDbType.Image));
15         cmd.Parameters["@content"].Value = content;
16 
17         cmd.Parameters.Add(new SqlParameter("@code", SqlDbType.Int));
18         cmd.Parameters["@code"].Value = code;
19         con.Open();
20         int result = cmd.ExecuteNonQuery();
21         if (result > 0)
22         {
23             Response.Write("插入成功！");
24         }
25         con.Close();