SQL 保留两位小数的各种方法
1.求和后,保留两位
sum(cast(cc.OrderDateCount as decimal(10, 2)))
2.平均值,保留小数
CONVERT(decimal(10,2),avg(case when cc.ReceiveDateSum=0 then cc.ReceiveDateCount else
cc.ReceiveDateCount/cc.ReceiveDateSum end))
C# 保留两位小数的各种方法
1.用NumberFormatInfo类来解决:
System.Globalization.NumberFormatInfo provider = new System.Globalization.NumberFormatInfo();
provider.NumberDecimalDigits =intDecLength; //要設定的小數位數
double strCashAmt=Convert.ToDouble(this.txtCashAmt.Text); //先把控件內的值轉成double
this.txtCashAmt.Text = strCashAmt.ToString("N",provider); //再利用ToString函數格式化小數位數
2、用toString方法.:
public string getRate(double hcount, double task)
{
string rValue;
string temp = "";
if (task == 0)
{
task = 1;
}
double db = (hcount / task) * 100;
if (hcount >= task)
{
rValue = "100%";
}
else
{
rValue = db.ToString("#0.#0") + "%";
}
return rValue;
}
string str1 = String.Format("{0:N1}",56789); //result: 56,789.0 ({0:N1}金额一位小数)
string str2 = String.Format("{0:N2}",56789); //result: 56,789.00({0:N2}金额两位小数)
string str3 = String.Format ("{0:N3}",56789); //result: 56,789.000 ({0:N3}金额三位小数)
string str8 = String.Format("{0:F1}",56789); //result: 56789.0 ({0:F1}一位小数)
string str9 = String.Format("{0:F2}",56789); //result: 56789.00({0:F2}两位小数)
string str11 =(56789 / 100.0).ToString("#.##"); //result: 567.89 (除以小数)
string str12 =(56789 / 100).ToString("#.##"); //result: 56 (除以整数)
3.保留N位四舍五入
Math.Round(0.55555,2) //数学函数方法
4,保留N位四舍五入
double dbdata = 0.55555; string str1 = dbdata.ToString("f2");//fN 保留N位,四舍五入
5.保留N位四舍五入
string result = String.Format("{0:N2}", 0.55555);//2位
string result = String.Format("{0:N3}", 0.55555);//3位
6. 保留N位四舍五入
double s=0.55555;
result=s.ToString("#0.00");//点后面几个0就保留几位
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