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Find the contiguous subarray within an array (containing at least one number) which has the largest sum. 1 public static int MaximumSubarray(int[] A) 2 { 3 int n = A.Length; 4 int max = A[0], max_neg = A[0], sum = 0; 5 bool flag = false; // for all the elements are negative integers 6 for (int i = 0; i < n; i++) 7 { 8 //if found one is not negative, toggle flag. And keep tracking the max negative number 9 if (A[i] >= 0) 10 flag = true; 11 else if (A[i] > max_neg) 12 max_neg = A[i]; 13 14 sum += A[i]; 15 if (sum < 0) 16 sum = 0; 17 else if (sum > max) 18 max = sum; 19 } 20 21 return flag ? max : max_neg; 22 } 代码分析: O(n)的解法, 要注意所有element都是negative的case。 |
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