[Swift]LeetCode925.长按键入|LongPressedName

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Your friend is typing his name into a keyboard. Sometimes, when typing a character c, the key might get long pressed, and the character will be typed 1 or more times.

You examine the typed characters of the keyboard. Return True if it is possible that it was your friends name, with some characters (possibly none) being long pressed.

Example 1:

Input: name = true
Explanation: 'a' and 'e' in 'alex' were long pressed.

Example 2:

Input: name = false
Explanation: 'e' must have been pressed twice, but it wasn't in the typed output.

Example 3:

Input: name = true

Example 4:

Input: name = true
Explanation: It's not necessary to long press any character.

Note:

name.length <= 1000
typed.length <= 1000
The characters of name and typed are lowercase letters.

你的朋友正在使用键盘输入他的名字 name。偶尔，在键入字符 c 时，按键可能会被长按，而字符可能被输入 1 次或多次。

你将会检查键盘输入的字符 typed。如果它对应的可能是你的朋友的名字（其中一些字符可能被长按），那么就返回 True。

示例 1：

输入：name = "alex", typed = "aaleex"
输出：true
解释：'alex' 中的 'a' 和 'e' 被长按。

示例 2：

输入：name = "saeed", typed = "ssaaedd"
输出：false
解释：'e' 一定需要被键入两次，但在 typed 的输出中不是这样。

示例 3：

输入：name = "leelee", typed = "lleeelee"
输出：true

示例 4：

输入：name = "laiden", typed = "laiden"
输出：true
解释：长按名字中的字符并不是必要的。

提示：

name.length <= 1000
typed.length <= 1000
name 和 typed 的字符都是小写字母。

8ms

 1 class Solution {
 2     func isLongPressedName(_ name: String, _ typed: String) -> Bool {
 3         guard name.count != 0 else {
 4             return true
 5         }
 6         let chars1 = Array(name)
 7         let chars2 = Array(typed)
 8         var index = 0
 9         for i in 0..<chars2.count {
10             if index == chars1.count {  // Best Idea
11                 if chars2[i] != chars2[i - 1] {
12                     return false
13                 }
14                 continue
15             }
16             
17             if chars1[index] == chars2[i] {
18                 index += 1
19             } else if i != 0 && chars2[i] == chars2[i - 1] {
20                 continue
21             } else {
22                 return false
23             }
24         }
25         return index == chars1.count
26     }
27 }

12ms

 1 class Solution {
 2   func count(_ str: String) -> [(Character, Int)] {
 3     var result = [(Character,Int)]()
 4     
 5     var pos = str.startIndex
 6     while pos < str.endIndex {
 7       var next = str.index(after:pos)
 8       var c = 1
 9       while next < str.endIndex && str[pos] == str[next] {
10         next = str.index(after:next)
11         c += 1
12       }
13       result.append((str[pos], c))
14       pos = next
15     }
16     
17     
18     return result
19   }
20   
21   
22   func isLongPressedName(_ name: String, _ typed: String) -> Bool {
23     let nameC = count(name)
24     let typedC = count(typed)
25     
26     if nameC.count != typedC.count {
27       return false
28     }
29     
30     for var i in 0..<nameC.count {
31       if nameC[i].0 != typedC[i].0 {
32         return false
33       }
34       if nameC[i].1 > typedC[i].1 {
35         return false
36       }
37     }
38     
39     return true
40   }
41 }

16ms

 1 class Solution {
 2     func isLongPressedName(_ name: String, _ typed: String) -> Bool {
 3         guard name.count != 0 else {
 4             return true
 5         }
 6         let chars1 = Array(name)
 7         let chars2 = Array(typed)
 8         var index = 0
 9         for i in 0..<chars2.count {
10             if index == chars1.count { // Best Idea
11                 if chars2[i] != chars2[i - 1] {
12                     return false
13                 }
14                 continue
15             }
16 
17             if chars1[index] == chars2[i] {
18                     index += 1
19             } else if i != 0 && chars2[i] == chars2[i - 1] {
20                 continue
21             } else {
22                 return false
23             }
24         }
25         return index == chars1.count
26     }
27 }

36ms

 1 class Solution {
 2     func isLongPressedName(_ name: String, _ typed: String) -> Bool {
 3         guard name.count != 0 else {
 4             return true
 5         }
 6         var index1 = 0
 7         var index2 = 0
 8         var char1 = Array(name)
 9         var char2 = Array(typed)
10         while index1 < name.count && index2 < typed.count {
11             if char1[index1] == char2[index2] {
12                 index1 += 1
13                 index2 += 1
14             } else if index2 != 0 && char2[index2] == char2[index2 - 1] {
15                     index2 += 1
16             } else {
17                 return false
18             }
19         }
20         return index1 == char1.count
21     }
22 }

36ms

 1 class Solution {
 2     func isLongPressedName(_ name: String, _ typed: String) -> Bool {
 3         var p:Int = 0
 4         for num in 0..<typed.count
 5         {
 6             var typeIndex = typed.index(typed.startIndex,offsetBy: num)
 7             var nameIndex = name.index(name.startIndex,offsetBy: p)
 8             if p < name.count && typed[typeIndex] == name[nameIndex]
 9             {
10                 p += 1
11             }
12             else
13             {
14                 if num > 0 && typed[typeIndex] == typed[typed.index(typed.startIndex,offsetBy:num - 1)]
15                 {
16                     continue
17                 }
18                 else
19                 {
20                     return false
21                 }
22             }
23         }
24         return p == name.count
25     }
26 }

44ms

 1 class Solution {
 2     func isLongPressedName(_ name: String, _ typed: String) -> Bool {
 3         guard name.count != 0 else {
 4             return true
 5         }
 6         
 7         var index1 = 0
 8         var index2 = 0
 9         var char1 = Array(name)
10         var char2 = Array(typed)
11         while index1 < name.count && index2 < typed.count {
12             if char1[index1] == char2[index2] {
13                 index1 += 1
14                 index2 += 1
15             } else {
16                 if index2 != 0 && char2[index2] == char2[index2 - 1] {
17                     index2 += 1
18                 } else {
19                     return false
20                 }
21             }
22         }
23         guard index1 == name.count else {
24             return false
25         }
26         
27         while index2 < typed.count {
28             if index2 != 0 && char2[index2] == char2[index2 - 1] {
29                 index2 += 1
30                 continue
31             } else {
32                 break
33             }
34         }
35         return index2 == typed.count
36     }
37 }

52ms

 1 class Solution {
 2     func isLongPressedName(_ name: String, _ typed: String) -> Bool {
 3         guard name.count != 0 else {
 4             return true
 5         }
 6         
 7         var index1 = 0
 8         var index2 = 0
 9         var char1 = Array(name)
10         var char2 = Array(typed)
11         while index1 < name.count && index2 < typed.count {
12             if char1[index1] == char2[index2] {
13                 index1 += 1
14                 index2 += 1
15             } else if index2 != 0 && char2[index2] == char2[index2 - 1] {
16                 index2 += 1
17             } else {
18                 return false
19             }
20         }
21         guard index1 == name.count else {
22             return false
23         }
24         
25         while index2 < typed.count {
26             if index2 != 0 && char2[index2] == char2[index2 - 1] {
27                 index2 += 1
28                 continue
29             } else {
30                 break
31             }
32         }
33         return index2 == typed.count
34     }
35 }