[Swift]LeetCode320.通用简写$GeneralizedAbbreviation

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Write a function to generate the generalized abbreviations of a word.

Example:

Given word = "word", return the following list (order does not matter):

["word", "1ord", "w1rd", "wo1d", "wor1", "2rd", "w2d", "wo2", "1o1d", "1or1", "w1r1", "1o2", "2r1", "3d", "w3", "4"]

编写一个函数来生成一个单词的广义缩写。

例子：

给定word = "word",返回以下列表（顺序不重要）：

["word", "1ord", "w1rd", "wo1d", "wor1", "2rd", "w2d", "wo2", "1o1d", "1or1", "w1r1", "1o2", "2r1", "3d", "w3", "4"]

Solution:

 1 class Solution {
 2     func generateAbbreviations(_ word:String) -> [String] {
 3         var res:[String] = [String]()
 4         var str:String = String()
 5         if !word.isEmpty
 6         {
 7             str = String(word.count)
 8         }
 9         res.append(str)
10         for i in 0..<word.count
11         {
12             let arr:[String] = generateAbbreviations(word.subString(i + 1))
13             for a in arr
14             {
15                 var left:String = String()
16                 if i > 0
17                 {
18                     left = String(i)
19                 }
20                 res.append(left + word.subString(i, 1) + a )
21             }
22         }
23         return res        
24     }
25 }
26 
27 extension String {
28     // 截取字符串：从index到结束处
29     // - Parameter index: 开始索引
30     // - Returns: 子字符串
31     func subString(_ index: Int) -> String {
32         let theIndex = self.index(self.endIndex, offsetBy: index - self.count)
33         return String(self[theIndex..<endIndex])
34     }
35     
36     // 截取字符串：指定索引和字符数
37     // - begin: 开始截取处索引
38     // - count: 截取的字符数量
39     func subString(_ begin:Int,_ count:Int) -> String {
40         let start = self.index(self.startIndex, offsetBy: max(0, begin))
41         let end = self.index(self.startIndex, offsetBy:  min(self.count, begin + count))
42         return String(self[start..<end]) 
43     }
44 }

点击：Playground测试

1 var sol = Solution()
2 print(sol.generateAbbreviations("word"))
3 //Print ["4", "w3", "wo2", "wor1", "word", "wo1d", "w1r1", "w1rd", "w2d", "1o2", "1or1", "1ord", "1o1d", "2r1", "2rd", "3d"]