客服电话
APP下载
迪恩网络APP
随时随地掌握行业动态
官方微信
扫描二维码
关注迪恩网络微信公众号
|
★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★ Given a 2D board and a word, find if the word exists in the grid. The word can be constructed from letters of sequentially adjacent cell, where "adjacent" cells are those horizontally or vertically neighboring. The same letter cell may not be used more than once. Example: board = [ ['A','B','C','E'], ['S','F','C','S'], ['A','D','E','E'] ] Given word = "ABCCED", return true. Given word = "SEE", return true. Given word = "ABCB", return false. 给定一个二维网格和一个单词，找出该单词是否存在于网格中。 单词必须按照字母顺序，通过相邻的单元格内的字母构成，其中“相邻”单元格是那些水平相邻或垂直相邻的单元格。同一个单元格内的字母不允许被重复使用。 示例: board = [ ['A','B','C','E'], ['S','F','C','S'], ['A','D','E','E'] ] 给定 word = "ABCCED", 返回 true. 给定 word = "SEE", 返回 true. 给定 word = "ABCB", 返回 false. 100ms 1 class Solution { 2 3 func searchSolution(_ board: inout [[Character]], 4 _ letter: inout [Character], 5 _ visited: inout [[Bool]], 6 _ x: Int, 7 _ y: Int, 8 _ index: Int) -> Bool { 9 10 if board[x][y] == letter[index] { 11 12 visited[x][y] = true 13 14 if (index + 1) >= letter.count { 15 return true 16 } 17 18 if x > 0 { 19 if visited[x-1][y] == false && searchSolution(&board, &letter, &visited, x - 1, y, index + 1) { 20 return true 21 } 22 } 23 if x < (board.count - 1) { 24 if visited[x+1][y] == false && searchSolution(&board, &letter, &visited, x + 1, y, index + 1) { 25 return true 26 } 27 } 28 if y > 0 { 29 if visited[x][y-1] == false && searchSolution(&board, &letter, &visited, x, y - 1, index + 1) { 30 return true 31 } 32 } 33 if y < (board[0].count - 1) { 34 if visited[x][y+1] == false && searchSolution(&board, &letter, &visited, x, y + 1, index + 1) { 35 return true 36 } 37 } 38 39 visited[x][y] = false 40 41 } 42 43 return false 44 } 45 46 func exist(_ board: [[Character]], _ word: String) -> Bool { 47 48 var letters = Array(word) 49 var board = board 50 51 if board.count <= 0 { return false } 52 if board[0].count <= 0 { return false } 53 54 var visited = [[Bool]](repeating: [Bool](repeating: false, count: board[0].count), count: board.count) 55 56 for x in 0..<board.count { 57 for y in 0..<board[0].count { 58 59 if searchSolution(&board, &letters, &visited, x, y, 0) { 60 return true 61 } 62 } 63 } 64 65 return false 66 } 67 } 128ms 1 class Solution { 2 func exist(_ board: [[Character]], _ word: String) -> Bool { 3 4 if board.count == 0 { 5 return false 6 } 7 let m = board.count 8 let n = board[0].count 9 var board = board 10 var wordChars = Array(word) 11 for i in 0..<m { 12 for j in 0..<n { 13 if helper(&board, i, j, &wordChars, 0) { 14 return true 15 } 16 } 17 } 18 return false 19 20 } 21 22 func helper(_ board: inout [[Character]], _ i: Int, _ j: Int, _ wordChars: inout [Character], _ cur: Int) -> Bool { 23 let m = board.count 24 let n = board[0].count 25 if (i < 0 || i >= m || j < 0 || j >= n || board[i][j] == "0" || board[i][j] != wordChars[cur]) { 26 return false 27 } 28 if cur == wordChars.count - 1 { 29 return true 30 } 31 let temp = board[i][j] 32 board[i][j] = "0" 33 let res = helper(&board, i-1, j, &wordChars, cur+1) || 34 helper(&board, i+1, j, &wordChars, cur+1) || 35 helper(&board, i, j-1, &wordChars, cur+1) || 36 helper(&board, i, j+1, &wordChars, cur+1) 37 board[i][j] = temp 38 return res 39 } 40 } 168ms 1 class Solution { 2 func exist(_ board: [[Character]], _ word: String) -> Bool { 3 4 let char = word[word.index(word.startIndex, offsetBy: 0)] 5 6 for row in 0..<board.count { 7 for col in 0..<board[0].count { 8 if board[row][col] == char && search(board, word, row, col, 1) { 9 return true 10 } 11 } 12 } 13 14 return false 15 } 16 17 func search(_ board: [[Character]], _ word: String, _ row: Int, _ col: Int, _ index: Int) -> Bool { 18 if index >= word.count { return true } 19 20 var board = board 21 board[row][col] = "-" 22 23 let char = word[word.index(word.startIndex, offsetBy: index)] 24 25 if (row+1) < board.count && board[row+1][col] == char && search(board, word, row+1, col, index+1) { 26 return true 27 } 28 29 else if row > 0 && board[row-1][col] == char && search(board, word, row-1, col, index+1) { 30 return true 31 } 32 33 else if (col+1) < board[row].count && board[row][col+1] == char && search(board, word, row, col+1, index+1) { 34 return true 35 } 36 37 else if col > 0 && board[row][col-1] == char && search(board, word, row, col-1, index+1) { 38 return true 39 } 40 41 return false 42 } 43 } 172ms 1 class Solution { 2 func exist(_ board: [[Character]], _ word: String) -> Bool { 3 var board = board 4 var word = Array(word) 5 for y in stride(from:0,to:board.count,by:1) { 6 for x in stride(from:0,to:board[0].count,by:1) { 7 if dfs(&board,y,x,word,0) { 8 return true 9 } 10 } 11 } 12 return false 13 } 14 15 func dfs(_ board:inout[[Character]], _ y:Int,_ x:Int,_ word:Array<Character>,_ wordPos:Int) -> Bool { 16 if wordPos == word.count { 17 return true 18 } else if y < 0 || y >= board.count || x < 0 || x >= board[0].count || board[y][x] != word[wordPos]{ 19 return false 20 } 21 let temp = board[y][x] 22 board[y][x] = "#" 23 let res = dfs(&board,y + 1,x,word,wordPos + 1) || 24 dfs(&board,y - 1,x,word,wordPos + 1) || 25 dfs(&board,y,x + 1,word,wordPos + 1) || 26 dfs(&board,y,x - 1,word,wordPos + 1) 27 28 board[y][x] = temp 29 return res 30 } 31 } 192ms 1 class Solution { 2 let rowDirection = [0,0,1,-1] 3 let colDiriction = [1,-1,0,0] 4 5 func exist(_ board: [[Character]], _ word: String) -> Bool { 6 guard !board.isEmpty else { 7 return false 8 } 9 10 let rowCount = board.count 11 let colCount = board[0].count 12 13 if rowCount * colCount < word.count { 14 return false 15 } 16 17 var wordChars = [Character](word) 18 19 var tempBoard = board 20 21 for rowIndex in 0..<rowCount { 22 for colIndex in 0..<colCount { 23 var temp = tempBoard[rowIndex][colIndex] 24 if temp == wordChars[0] { 25 tempBoard[rowIndex][colIndex] = "0" 26 if existHelper(&tempBoard, 1, &wordChars, rowIndex, colIndex, 1, rowCount, colCount) { 27 return true 28 } 29 tempBoard[rowIndex][colIndex] = temp 30 } 31 } 32 } 33 34 return false 35 } 36 37 func existHelper (_ board: inout [[Character]], _ count: Int, _ word: inout [Character], _ rowIndex: Int, _ colIndex: Int, _ index: Int, _ rowCount: Int, _ colCount: Int) -> Bool { 38 39 40 if count == word.count { 41 return true 42 } 43 let newCount = count + 1 44 for i in 0..<rowDirection.count { 45 let newRow = rowIndex + rowDirection[i] 46 let newCol = colIndex + colDiriction[i] 47 48 49 50 if newRow < 0 || newRow >= rowCount 51 || newCol < 0 || newCol >= colCount 52 || board[newRow][newCol] == "0" || board[newRow][newCol] != word[index] { 53 continue 54 } 55 56 let newStr = board[newRow][newCol] 57 board[newRow][newCol] = "0" 58 59 if existHelper(&board, newCount, &word, newRow, newCol, index+1, rowCount, colCount) { 60 return true 61 } 62 63 board[newRow][newCol] = newStr 64 } 65 66 return false 67 } 68 } 316ms 1 class Solution { 2 func exist(_ board: [[Character]], _ word: String) -> Bool { 3 if board.count == 0 { 4 return false 5 } 6 var visit = Array.init(repeating: Array.init(repeating: false, count: board[0].count), count: board.count) 7 for i in 0..<board.count { 8 for j in 0..<board[0].count { 9 if exist(board, word, 0, i, j, &visit) { 10 return true 11 } 12 } 13 } 14 return false 15 16 } 17 func exist(_ board: [[Character]], _ word: String,_ index: Int, _ i: Int,_ j: Int, _ visit:inout [[Bool]]) -> Bool { 18 if index == word.count {//已经到字符串最后 19 return true 20 } 21 if i < 0 || j < 0 || i >= board.count || j >= board[0].count {//越界了 22 return false 23 } 24 if visit[i][j] {//访问过了 25 return false 26 } 27 if board[i][j] != word[word.index(word.startIndex, offsetBy: index)] { 28 return false 29 } 30 //该字符符合条件，搜索下一个字符 31 visit[i][j] = true 32 let result = exist(board, word, index + 1, i + 1, j, &visit) || exist(board, word, index + 1, i - 1, j, &visit) || exist(board, word, index + 1, i , j - 1, &visit) || exist(board, word, index + 1, i , j + 1, &visit) 33 visit[i][j] = false 34 return result 35 } 36 }
|
请发表评论