[Swift]LeetCode647.回文子串|PalindromicSubstrings

OStack程序员社区-中国程序员成长平台 › 门户 › 编程› 移动开发›Swift 教程

原作者: [db:作者] 来自: [db:来源] 收藏邀请

★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★
➤微信公众号：山青咏芝（shanqingyongzhi）
➤博客园地址：山青咏芝（https://www.cnblogs.com/strengthen/）
➤GitHub地址：https://github.com/strengthen/LeetCode
➤原文地址：https://www.cnblogs.com/strengthen/p/10482491.html
➤如果链接不是山青咏芝的博客园地址，则可能是爬取作者的文章。
➤原文已修改更新！强烈建议点击原文地址阅读！支持作者！支持原创！
★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★

热烈欢迎，请直接点击！！！

进入博主App Store主页，下载使用各个作品！！！

注：博主将坚持每月上线一个新app！！！

Given a string, your task is to count how many palindromic substrings in this string.

The substrings with different start indexes or end indexes are counted as different substrings even they consist of same characters.

Example 1:

Input: "abc"
Output: 3
Explanation: Three palindromic strings: "a", "b", "c".

Example 2:

Input: "aaa"
Output: 6
Explanation: Six palindromic strings: "a", "a", "a", "aa", "aa", "aaa".

Note:

The input string length won't exceed 1000.

给定一个字符串，你的任务是计算这个字符串中有多少个回文子串。

具有不同开始位置或结束位置的子串，即使是由相同的字符组成，也会被计为是不同的子串。

示例 1:

输入: "abc"
输出: 3
解释: 三个回文子串: "a", "b", "c".

示例 2:

输入: "aaa"
输出: 6
说明: 6个回文子串: "a", "a", "a", "aa", "aa", "aaa".

注意:

输入的字符串长度不会超过1000。

16ms

 1 class Solution {
 2     func countSubstrings(_ s: String) -> Int {
 3         var count = 0
 4         var s = Array(s)
 5         for i in 0..<s.count {
 6             if i + 1 < s.count, s[i] == s[i + 1] {
 7                 count += numPalindromes(s, i, i + 1)
 8             }
 9             count += numPalindromes(s, i, i)
10         }
11         return count
12     }
13 
14     func numPalindromes(_ s: [Character], _ i: Int, _ j: Int) -> Int {
15         var count = 0, i = i, j = j
16         while i >= 0, j < s.count, s[i] == s[j] {
17             i -= 1
18             j += 1
19             count += 1
20         }
21         return count
22     }
23 }

20ms

 1 class Solution {
 2     func countSubstrings(_ s: String) -> Int {
 3         var result = 0
 4         let input = Array(s)
 5         for i in 0..<input.count {
 6             checkPalindrom(i,i,input,&result)
 7             checkPalindrom(i,i + 1,input,&result)
 8         }
 9         return result
10     }
11     
12     func checkPalindrom(_ left: Int, _ right: Int, _ input: [Character], _ result: inout Int) {
13         let count = input.count
14         var i = left, j = right
15         while i >= 0, j < count {
16             if input[i] == input[j] {
17                 result += 1
18                 i -= 1
19                 j += 1
20             }else{
21                 break
22             }
23         }
24     }
25 }

28ms

 1 class Solution {
 2     func countSubstrings(_ s: String) -> Int {
 3         let arr = Array(s)        
 4         let cnt = s.count
 5         if cnt == 0 {
 6             return 0
 7         }        
 8         var result = 0
 9 
10         for center in 0..<cnt {
11             var left = center
12             var right = center
13             
14             while left >= 0 && right < cnt && arr[left] == arr[right] {
15                 result += 1
16                 left -= 1
17                 right += 1
18             }
19         }
20 
21         for center in 1..<cnt {
22             var left = center-1
23             var right = center
24             
25             while left >= 0 && right < cnt && arr[left] == arr[right] {
26                 result += 1
27                 left -= 1
28                 right += 1
29             }
30         }
31         return result
32     }    
33 }

32ms

 1 class Solution {
 2     func countSubstrings(_ s: String) -> Int {
 3         let s = Array(s)
 4         var n = s.count, ans = 0
 5         for center in 0..<2*n {
 6             var left = center / 2
 7             var right = left + center % 2
 8             while (left >= 0 && right < n && 
 9                    s[s.index(s.startIndex,offsetBy:left)] == 
10                    s[s.index(s.startIndex,offsetBy:right)]) {
11                 ans+=1
12                 left-=1
13                 right+=1
14             }
15         }
16         return ans
17     }
18 }

40ms

 1 class Solution {
 2     func countSubstrings(_ s: String) -> Int {
 3         let chars = Array(s)
 4         func extend(_ left: Int, _ right: Int) -> Int {
 5             var (left, right) = (left, right)
 6             var count = 0
 7             while left >= 0
 8                 && right < chars.count
 9                 && chars[left] == chars[right] {
10                     left -= 1
11                     right += 1
12                     count += 1
13                 }
14 
15             return count
16         }
17 
18         return chars.indices.map {
19             extend($0, $0) + extend($0, $0 + 1)
20         }
21         .reduce(0, +)
22     }
23 }

56ms

 1 class Solution {
 2     func countSubstrings(_ s: String) -> Int {
 3     guard s.count > 1 else{
 4         return 1
 5     }
 6     
 7     var manipulationStr : [Character] = []
 8     for char in Array(s){
 9         manipulationStr.append("#")
10         manipulationStr.append(char)
11     }
12     manipulationStr.append("#")
13     
14     var count : Int = 0
15     for movingIndex in 1..<manipulationStr.count - 1{
16         var leftIndex = movingIndex
17         var rightIndex = movingIndex
18         while leftIndex >= 0 && rightIndex < manipulationStr.count{
19             if manipulationStr[leftIndex] != manipulationStr[rightIndex]{
20                 break
21             }else{
22                 if manipulationStr[leftIndex] != "#"{
23                     count += 1
24                 }
25                 leftIndex -= 1
26                 rightIndex += 1
27             }
28         }
29     }
30     return count
31   }
32 }