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Each car A car can never pass another car ahead of it, but it can catch up to it, and drive bumper to bumper at the same speed. The distance between these two cars is ignored - they are assumed to have the same position. A car fleet is some non-empty set of cars driving at the same position and same speed. Note that a single car is also a car fleet. If a car catches up to a car fleet right at the destination point, it will still be considered as one car fleet. How many car fleets will arrive at the destination? Example 1: Input: target = [2,4,1,1,3]
Output: 3
Explanation:
The cars starting at 10 and 8 become a fleet, meeting each other at 12.
The car starting at 0 doesn't catch up to any other car, so it is a fleet by itself.
The cars starting at 5 and 3 become a fleet, meeting each other at 6.
Note that no other cars meet these fleets before the destination, so the answer is 3.
Note:
每辆车 一辆车永远不会超过前面的另一辆车,但它可以追上去,并与前车以相同的速度紧接着行驶。 此时,我们会忽略这两辆车之间的距离,也就是说,它们被假定处于相同的位置。 车队 是一些由行驶在相同位置、具有相同速度的车组成的非空集合。注意,一辆车也可以是一个车队。 即便一辆车在目的地才赶上了一个车队,它们仍然会被视作是同一个车队。 会有多少车队到达目的地? 示例: 输入:target = 12, position = [10,8,0,5,3], speed = [2,4,1,1,3] 输出:3 解释: 从 10 和 8 开始的车会组成一个车队,它们在 12 处相遇。 从 0 处开始的车无法追上其它车,所以它自己就是一个车队。 从 5 和 3 开始的车会组成一个车队,它们在 6 处相遇。 请注意,在到达目的地之前没有其它车会遇到这些车队,所以答案是 3。 提示:
232ms 1 class Solution { 2 3 func carFleet(_ target: Int, _ position: [Int], _ speed: [Int]) -> Int { 4 let cars = zip(position, speed).map{Car(position: $0.0, speed: $0.1)}.sorted{$0.position > $1.position} 5 6 var fleets = 0 7 var currentTime = 0.0 8 for c in cars { 9 let carTime = c.time(toTarget: target) 10 if carTime > currentTime { 11 currentTime = carTime 12 fleets += 1 13 } 14 } 15 return fleets 16 } 17 } 18 19 struct Car { 20 let position : Int 21 let speed : Int 22 23 func time(toTarget target: Int) -> Double { 24 return Double(target - position) / Double(speed) 25 } 26 } 240ms 1 class Solution { 2 func carFleet(_ target: Int, _ position: [Int], _ speed: [Int]) -> Int { 3 guard position.count == speed.count else { return -1 } 4 let n = position.count 5 var cars = [Car]() 6 for i in 0..<n { 7 cars.append(Car(position: position[i], time: (Float)(target - position[i]) / Float(speed[i]))) 8 } 9 cars.sort(by:{ 10 $0.position < $1.position 11 }) 12 var t = n - 1 13 var ret = 0 14 while (t > 0) { 15 if cars[t].time < cars[t-1].time { 16 ret += 1 17 } else { 18 cars[t-1].time = cars[t].time 19 } 20 t -= 1 21 } 22 return ret + (t == 0 ? 1: 0) 23 } 24 25 struct Car { 26 let position: Int 27 var time: Float 28 } 29 } Runtime: 248 ms
Memory Usage: 19.4 MB
1 class Solution { 2 func carFleet(_ target: Int, _ position: [Int], _ speed: [Int]) -> Int { 3 var map:[Int:Double] = [Int:Double]() 4 for i in 0..<position.count 5 { 6 map[target - position[i]] = Double(speed[i]) 7 } 8 var res:Int = 0 9 var cur:Double = 0.0 10 var nums = Set(map.keys).sorted(by:<) 11 for key in nums 12 { 13 var time:Double = Double(key) / map[key,default:0] 14 if time > cur 15 { 16 cur = time 17 res += 1 18 } 19 } 20 return res 21 } 22 } 252ms 1 class Solution { 2 func carFleet(_ target: Int, _ position: [Int], _ speed: [Int]) -> Int { 3 var orders: [Int: Double] = [:] 4 for (index, pos) in position.enumerated() { 5 let steps = Double(target - pos) / Double(speed[index]) 6 orders[pos] = steps 7 } 8 9 var stack: [Double] = [] 10 for pair in orders.sorted(by: { $0.key > $1.key }) { 11 if stack.isEmpty { 12 stack.append(pair.value) 13 } else { 14 if stack.last! < pair.value { 15 stack.append(pair.value) 16 } 17 } 18 } 19 return stack.count 20 } 21 } 280ms 1 class Solution { 2 func carFleet(_ target: Int, _ position: [Int], _ speed: [Int]) -> Int { 3 var times: [Int: Double] = [:] 4 let n = position.count 5 for i in 0..<n { 6 let time = Double(target - position[i])/Double(speed[i]) 7 times[position[i]] = time 8 } 9 var res = 0 10 var prevTime = 0.0 11 for (_, time) in times.sorted(by: { $0.key > $1.key }) { 12 if time > prevTime { 13 res += 1 14 prevTime = time 15 } 16 } 17 return res 18 } 19 } 288ms 1 class Solution { 2 func carFleet(_ target: Int, _ position: [Int], _ speed: [Int]) -> Int { 3 var fleets = 0 4 var max = -1.0 5 6 var distribution = [Double](repeating: -1, count: target+1) 7 8 for i in 0..<position.count { 9 distribution[position[i]] = Double(target - position[i])/Double(speed[i]) 10 } 11 12 var i = distribution.count - 1 13 while i>=0 { 14 if distribution[i] > max { 15 max = distribution[i] 16 fleets += 1 17 } 18 i -= 1 19 } 20 return fleets 21 } 22 }
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