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★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★ There are 8 prison cells in a row, and each cell is either occupied or vacant. Each day, whether the cell is occupied or vacant changes according to the following rules:
(Note that because the prison is a row, the first and the last cells in the row can't have two adjacent neighbors.) We describe the current state of the prison in the following way: Given the initial state of the prison, return the state of the prison after Example 1: Input: cells = 7
Output: [0,0,1,1,0,0,0,0]
Explanation:
The following table summarizes the state of the prison on each day:
Day 0: [0, 1, 0, 1, 1, 0, 0, 1]
Day 1: [0, 1, 1, 0, 0, 0, 0, 0]
Day 2: [0, 0, 0, 0, 1, 1, 1, 0]
Day 3: [0, 1, 1, 0, 0, 1, 0, 0]
Day 4: [0, 0, 0, 0, 0, 1, 0, 0]
Day 5: [0, 1, 1, 1, 0, 1, 0, 0]
Day 6: [0, 0, 1, 0, 1, 1, 0, 0]
Day 7: [0, 0, 1, 1, 0, 0, 0, 0]
Example 2: Input: cells = 1000000000
Output: [0,0,1,1,1,1,1,0]
Note:
8 间牢房排成一排,每间牢房不是有人住就是空着。 每天,无论牢房是被占用或空置,都会根据以下规则进行更改:
(请注意,由于监狱中的牢房排成一行,所以行中的第一个和最后一个房间无法有两个相邻的房间。) 我们用以下方式描述监狱的当前状态:如果第 根据监狱的初始状态,在 示例 1: 输入:cells = [0,1,0,1,1,0,0,1], N = 7 输出:[0,0,1,1,0,0,0,0] 解释: 下表概述了监狱每天的状况: Day 0: [0, 1, 0, 1, 1, 0, 0, 1] Day 1: [0, 1, 1, 0, 0, 0, 0, 0] Day 2: [0, 0, 0, 0, 1, 1, 1, 0] Day 3: [0, 1, 1, 0, 0, 1, 0, 0] Day 4: [0, 0, 0, 0, 0, 1, 0, 0] Day 5: [0, 1, 1, 1, 0, 1, 0, 0] Day 6: [0, 0, 1, 0, 1, 1, 0, 0] Day 7: [0, 0, 1, 1, 0, 0, 0, 0] 示例 2: 输入:cells = [1,0,0,1,0,0,1,0], N = 1000000000 输出:[0,0,1,1,1,1,1,0] 提示:
16ms
1 class Solution { 2 func prisonAfterNDays(_ cells: [Int], _ N: Int) -> [Int] { 3 var cells = cells 4 var N:Int = N % 14 5 if N == 0 6 { 7 N = 14 8 } 9 for i in 0..<N 10 { 11 var temp:[Int] = [Int](repeating:0,count:cells.count) 12 temp[0] = 0 13 temp[7] = 0 14 for j in 1..<7 15 { 16 temp[j] = 1 - cells[j - 1]^cells[j + 1] 17 } 18 cells = temp 19 } 20 return cells 21 } 22 } 16ms 1 class Solution { 2 func prisonAfterNDays(_ cells: [Int], _ N: Int) -> [Int] { 3 var currentDay = processDay(cells) 4 let originalCells = currentDay 5 var count = 0 6 7 repeat { 8 currentDay = processDay(currentDay) 9 count += 1 10 } while currentDay != originalCells 11 12 let fullCycle = (N-1) % count 13 14 if fullCycle == 0 { 15 return currentDay 16 } else { 17 for _ in 1...fullCycle { 18 currentDay = processDay(currentDay) 19 } 20 return currentDay 21 } 22 } 23 24 func processDay(_ cells: [Int]) -> [Int] { 25 var newCells = [0] 26 27 for i in 1..<cells.count - 1 { 28 newCells.append(cells[i-1] == cells[i+1] ? 1 : 0) 29 } 30 31 newCells.append(0) 32 33 return newCells 34 } 35 } 20ms 1 class Solution { 2 func prisonAfterNDays(_ cells: [Int], _ N: Int) -> [Int] { 3 var arr:[Int] = [Int](repeating:0,count:512) 4 var pre:[Int] = cells 5 var cur:[Int] = [Int]() 6 arr[getSum(pre)] = 0 7 for i in 1...N 8 { 9 cur = [Int](repeating:0,count:8) 10 for j in 1..<7 11 { 12 if pre[j - 1] == pre[j + 1] 13 { 14 cur[j] = 1 15 } 16 } 17 if arr[getSum(cur)] == 0 18 { 19 arr[getSum(cur)] = i 20 } 21 else 22 { 23 var p:Int = arr[getSum(cur)] 24 var d:Int = (N - i) % (i - p) 25 for k in 0..<512 26 { 27 if arr[k] == p + d 28 { 29 return getArr(k) 30 } 31 } 32 } 33 pre = cur 34 } 35 return pre 36 } 37 38 func getArr(_ n:Int) -> [Int] 39 { 40 var n = n 41 var result:[Int] = [Int](repeating:0,count:8) 42 for i in (0...7).reversed() 43 { 44 let num:Int = Int(pow(2, Double(i))) 45 if n >= num 46 { 47 result[i] = 1 48 n -= num 49 } 50 } 51 return result 52 } 53 54 func getSum(_ arr:[Int])->Int 55 { 56 var result:Int = 0 57 for i in 0...7 58 { 59 if arr[i] == 1 60 { 61 result += Int(pow(2, Double(i))) 62 } 63 } 64 return result 65 } 66 } 24ms 1 class Solution { 2 func prisonAfterNDays(_ cells: [Int], _ N: Int) -> [Int] { 3 if N == 0 { return cells } 4 var cells = cells 5 var copy1day: [Int] = [] 6 var newDays = -1 7 for i in 1...N { 8 var prev = -1 9 for i in 0..<7 { 10 if cells[i + 1] == prev { 11 prev = cells[i] 12 cells[i] = 1 13 } else { 14 prev = cells[i] 15 cells[i] = 0 16 } 17 } 18 cells[7] = 0 19 //print("\(i): \(cells)") 20 if i == 1 { 21 copy1day = cells 22 } else if copy1day == cells { 23 let cycle = i - 1 24 newDays = (N - 1) % cycle 25 //print(cycle) 26 //print(newDays) 27 break 28 } 29 } 30 guard newDays >= 0 else { return cells } 31 for i in 0..<newDays { 32 var prev = -1 33 for i in 0..<7 { 34 if cells[i + 1] == prev { 35 prev = cells[i] 36 cells[i] = 1 37 } else { 38 prev = cells[i] 39 cells[i] = 0 40 } 41 } 42 } 43 44 return cells 45 } 46 } 36ms 1 class Solution { 2 func prisonAfterNDays(_ cells: [Int], _ N: Int) -> [Int] { 3 let seq = sequence(first: cells, next: next) 4 return seq.extrapolate(to: N) 5 } 6 } 7 8 func next(_ cells: [Int]) -> [Int] { 9 var result = Array(repeating: 0, count: cells.count) 10 11 for (index, equal) in zip(1..., zip(cells, cells.dropFirst(2)).lazy.map(==)) { 12 result[index] = equal ? 1 : 0 13 } 14 15 return result 16 } 17 18 extension Sequence where Element: Hashable { 19 func extrapolate(to targetIndex: Int) -> Element { 20 precondition(targetIndex >= 0) 21 22 var indices: [Element: Int] = [:] 23 var elements: [Element] = [] 24 25 for (index, element) in enumerated() { 26 if index == targetIndex { 27 return element 28 } else if let previous = elements.lastIndex(of: element) { 29 let cycle = index - previous 30 let remaining = (targetIndex - index) % cycle 31 return elements[previous + remaining] 32 } else { 33 indices[element] = index 34 elements.append(element) 35 } 36 } 37 38 preconditionFailure("sequence terminated too early") 39 } 40 } 64ms 1 class Solution { 2 func prisonAfterNDays(_ cells: [Int], _ N: Int) -> [Int] { 3 var currentDay = processDay(cells) 4 var originalCells = currentDay 5 var count = 0 6 7 repeat { 8 currentDay = processDay(currentDay) 9 count += 1 10 } while currentDay != originalCells 11 12 let cyclesToComplete = (N-1)%count 13 14 if cyclesToComplete == 0 { 15 return currentDay 16 } else { 17 for _ in 1...cyclesToComplete { 18 currentDay = processDay(currentDay) 19 } 20 } 21 22 return currentDay 23 } 24 25 func processDay(_ cells: [Int]) -> [Int] { 26 var newCells = [Int]() 27 newCells.append(0) 28 for index in 1..<cells.count-1 { 29 newCells.append(cells[index-1] == cells[index+1] ? 1 : 0) 30 } 31 newCells.append(0) 32 print(newCells) 33 return newCells 34 } 35 }
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