[Swift]LeetCode1106.解析布尔表达式|ParsingABooleanExpression

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Return the result of evaluating a given boolean expression, represented as a string.

An expression can either be:

"t", evaluating to True;
"f", evaluating to False;
"!(expr)", evaluating to the logical NOT of the inner expression expr;
"&(expr1,expr2,...)", evaluating to the logical AND of 2 or more inner expressions expr1, expr2, ...;
"|(expr1,expr2,...)", evaluating to the logical OR of 2 or more inner expressions expr1, expr2, ...

Example 1:

Input: expression = "!(f)"
Output: true

Example 2:

Input: expression = "|(f,t)"
Output: true

Example 3:

Input: expression = "&(t,f)"
Output: false

Example 4:

Input: expression = "|(&(t,f,t),!(t))"
Output: false

Constraints:

1 <= expression.length <= 20000
expression[i] consists of characters in {'(', ')', '&', '|', '!', 't', 'f', ','}.
expression is a valid expression representing a boolean, as given in the description.

给你一个以字符串形式表述的布尔表达式（boolean） expression，返回该式的运算结果。

有效的表达式需遵循以下约定：

"t"，运算结果为 True
"f"，运算结果为 False
"!(expr)"，运算过程为对内部表达式 expr 进行逻辑非的运算（NOT）
"&(expr1,expr2,...)"，运算过程为对 2 个或以上内部表达式 expr1, expr2, ... 进行逻辑与的运算（AND）
"|(expr1,expr2,...)"，运算过程为对 2 个或以上内部表达式 expr1, expr2, ... 进行逻辑或的运算（OR）

示例 1：

输入：expression = "!(f)"
输出：true

示例 2：

输入：expression = "|(f,t)"
输出：true

示例 3：

输入：expression = "&(t,f)"
输出：false

示例 4：

输入：expression = "|(&(t,f,t),!(t))"
输出：false

提示：

1 <= expression.length <= 20000
expression[i] 由 {'(', ')', '&', '|', '!', 't', 'f', ','} 中的字符组成。
expression 是以上述形式给出的有效表达式，表示一个布尔值。

Runtime: 32 ms

Memory Usage: 20.8 MB

 1 class Solution {
 2     func parseBoolExpr(_ expression: String) -> Bool {
 3         var op:[Character] = [Character]()
 4         var num:[Int] = [Int]()
 5         for ch in expression
 6         {
 7             if ch == "t" {num.append(1)}
 8             else if ch == "f" {num.append(0)}
 9             else if (ch == "|") || (ch == "&") || (ch == "!") {op.append(ch)}
10             else if ch == "(" {num.append(-1)}
11             else if ch == "," {continue}
12             else if ch == ")"
13             {
14                 var ans:Int = num.popLast()!
15                 let p:Character = op.popLast()!
16                 while(num.last! != -1)
17                 {
18                     let a:Int = num.popLast()!
19                     if p == "&" {ans = ans & a}
20                     else if p == "|" {ans = ans | a}
21                 }
22                 num.popLast()
23                 if p == "!" {ans =  1 - ans}
24                 num.append(ans)
25             }
26         }
27         if num.last! == 1
28         {
29             return true
30         }
31         return false
32     }
33 }

72ms

 1 class Solution {
 2     var expressions : [Character] = ["&","|","!"]
 3     var bools : [Character] = ["t","f"]
 4     func parseBoolExpr(_ expression: String) -> Bool {
 5         var stack : String = ""
 6         let expression = Array(expression)
 7         
 8         _ = true
 9         var currentBools = [Character]()
10         for i in 0..<expression.count {
11             
12             if expression[i] == ")" {
13                 while let head = stack.popLast(), head != "(" {
14                     if head == "t" || head == "f" {
15                         currentBools.append(head)
16                     }
17                 }
18                 if let op = stack.popLast() {
19                     if op == "&" {
20                         stack.append(evaluateAND(currentBools))
21                         currentBools.removeAll()
22                     } else if op == "|" {
23                         stack.append(evaluateOR(currentBools))
24                         currentBools.removeAll()
25                     } else if op == "!" {
26                         stack.append(evaluateNot(currentBools.first!))
27                         currentBools.removeAll()
28                     }
29                     continue
30                 }
31             }
32             if bools.contains(expression[i]) {
33                 currentBools.append(expression[i])
34                 continue
35             }
36             
37             stack.append(expression[i])
38         }
39         if stack.popLast() == "t" {return true}
40         return false
41     }
42     
43     func evaluateOR (_ input: [Character]) -> Character {
44         if input.contains("t") {return "t"}
45         return "f"
46     }
47     
48     func evaluateAND (_ input: [Character]) -> Character {
49         if input.contains("f") {return "f"}
50         return "t"
51     }
52     
53     func evaluateNot(_ input: Character) -> Character {
54         if input == ("f") {return "t"}
55         return "f"
56     }
57 }