客服电话
APP下载
迪恩网络APP
随时随地掌握行业动态
官方微信
扫描二维码
关注迪恩网络微信公众号
|
C. Removing Columns
time limit per test
2 secondsmemory limit per test
256 megabytesinput
standard inputoutput
standard outputYou are given an n × m rectangular table consisting of lower case English letters. In one operation you can completely remove one column from the table. The remaining parts are combined forming a new table. For example, after removing the second column from the table
we obtain the table:
A table is called good if its rows are ordered from top to bottom lexicographically, i.e. each row is lexicographically no larger than the following one. Determine the minimum number of operations of removing a column needed to make a given table good. Input
The first line contains two integers — n and m (1 ≤ n, m ≤ 100). Next n lines contain m small English letters each — the characters of the table. Output
Print a single number — the minimum number of columns that you need to remove in order to make the table good. Sample test(s)
Input
1 10 Output
0 Input
4 4 Output
2 Input
5 4 Output
4 Note
In the first sample the table is already good. In the second sample you may remove the first and third column. In the third sample you have to remove all the columns (note that the table where all rows are empty is considered good by definition). Let strings s and t have equal length. Then, s is lexicographically larger than t if they are not equal and the character following the largest common prefix of s and t (the prefix may be empty) in s is alphabetically larger than the corresponding character of t.
看题意 我看了好久…… #include <cstdio> #include <cmath> #include <cstring> #include <ctime> #include <iostream> #include <algorithm> #include <set> #include <vector> #include <sstream> #include <queue> #include <typeinfo> #include <fstream> typedef long long ll; using namespace std; //freopen("D.in","r",stdin); //freopen("D.out","w",stdout); #define sspeed ios_base::sync_with_stdio(0);cin.tie(0) #define maxn 100001 const int inf=0x7fffffff; //无限大 int n,m,res; char c[2000][2000]; string s[2000]; int main() { cin >> n >> m; for( int i=0; i<n; i++) for( int h=0; h<m; h++) cin >> c[i][h]; bool b=0; for( int i=0; i<m; i++ ) { for( int h=1; h<n; h++ ) { if( s[h-1]+c[h-1][i] > s[h]+c[h][i] ) { b=1; break; } } if(!b) { for(int h=0;h<n;h++) s[h]+=c[h][i]; } b=0; } cout << m-s[0].length(); return 0; }
|
2023-10-27
2022-08-15
2022-08-17
2022-09-23
2022-08-13
六六分期app的软件客服如何联系？不知道吗？加qq群【895510560】即可！标题：六六分期
今天小编告诉大家如何处理win10系统火狐flash插件总是崩溃的问题，可能很多用户都不知
今天小编告诉大家如何对win10系统删除桌面回收站图标进行设置，可能很多用户都不知道
今天小编告诉大家如何对win10系统电脑设置节能降温的设置方法，想必大家都遇到过需要
我们在使用xp系统的过程中,经常需要对xp系统无线网络安装向导设置进行设置，可能很多
今天小编告诉大家如何处理win7系统玩cf老是与主机连接不稳定的问题，可能很多用户都不
电脑对日常生活的重要性小编就不多说了，可是一旦碰到win7系统设置cf烟雾头的问题，很
我们在日常使用电脑的时候，有的小伙伴们可能在打开应用的时候会遇见提示应用程序无法
今天小编告诉大家如何对win7系统打开vcf文件进行设置，可能很多用户都不知道怎么对win
今天小编告诉大家如何对win10系统s4开启USB调试模式进行设置，可能很多用户都不知道怎
请发表评论