1 #include<iostream>
   2 #include<time.h>
   3 #include<stdio.h>
   4 #include <stdlib.h>
   5 using namespace std;
   6 struct pai
   7 {
   8 int paifu;
   9 int huase;
  10 int yanse;
  11 int dianshu;
  12 int leixing;
  13 int changdu;
  14 void Kanpai()
  15 {
  16 if(paifu==0||paifu==1);
  17 else
  18 printf("牌副参数错误！\n");
  19 switch(huase)
  20 {
  21 case 0:cout<<"黑桃";break;
  22 case 1:cout<<"红桃";break;
  23 case 2:cout<<"草花";break;
  24 case 3:cout<<"方片";break;
  25 case -1:cout<<"无色";break;
  26 default:printf("花色错误！\n");break;
  27 }
  28 switch(dianshu)
  29 {
  30 case 0:cout<<"A ";break;
  31 case 1:cout<<"2 ";break;
  32 case 2:cout<<"3 ";break;
  33 case 3:cout<<"4 ";break;
  34 case 4:cout<<"5 ";break;
  35 case 5:cout<<"6 ";break;
  36 case 6:cout<<"7 ";break;
  37 case 7:cout<<"8 ";break;
  38 case 8:cout<<"9 ";break;
  39 case 9:cout<<"10 ";break;
  40 case 10:cout<<"J ";break;
  41 case 11:cout<<"Q ";break;
  42 case 12:cout<<"K ";break;
  43 case -1:cout<<"无点数";break;
  44 default:printf("点数错误！\n");break;
  45 }
  46 switch(leixing)
  47 {
  48 case 101:cout<<"【杀】"<<endl;break;
  49 case 102:cout<<"【闪】"<<endl;break;
  50 case 103:cout<<"【桃】"<<endl;break;
  51 case 201:cout<<"【过河拆桥】"<<endl;break;
  52 case 202:cout<<"【顺手牵羊】"<<endl;break;
  53 case 203:cout<<"【无中生有】"<<endl;break;
  54 case 204:cout<<"【决斗】"<<endl;break;
  55 case 205:cout<<"【借刀杀人】"<<endl;break;
  56 case 206:cout<<"【桃园结义】"<<endl;break;
  57 case 207:cout<<"【五谷丰登】"<<endl;break;
  58 case 208:cout<<"【南蛮入侵】"<<endl;break;
  59 case 209:cout<<"【万箭齐发】"<<endl;break;
  60 case 210:cout<<"【无懈可击】"<<endl;break;
  61 case 251:cout<<"【乐不思蜀】"<<endl;break;
  62 case 252:cout<<"【闪电】"<<endl;break;
  63 case 301:cout<<"【诸葛连弩(1)】"<<endl;break;
  64 case 302:cout<<"【雌雄双股剑(2)】"<<endl;break;
  65 case 303:cout<<"【青釭剑(2)】"<<endl;break;
  66 case 304:cout<<"【青龙偃月刀(3)】"<<endl;break;
  67 case 305:cout<<"【丈八蛇矛(3)】"<<endl;break;
  68 case 306:cout<<"【贯石斧(3)】"<<endl;break;
  69 case 307:cout<<"【方天画戟(4)】"<<endl;break;
  70 case 308:cout<<"【麒麟弓(5)】"<<endl;break;
  71 case 331:cout<<"【八卦阵】"<<endl;break;
  72 case 361:cout<<"【赤兔(-1)】"<<endl;break;
  73 case 362:cout<<"【大宛(-1)】"<<endl;break;
  74 case 363:cout<<"【紫辛(-1)】"<<endl;break;
  75 case 381:cout<<"【爪黄飞电(+1)】"<<endl;break;
  76 case 382:cout<<"【的卢(+1)】"<<endl;break;
  77 case 383:cout<<"【绝影(+1)】"<<endl;break;
  78 default:printf("类型参数错误！");break;
  79 }
  80 }
  81 };
  82 void Qishixipai(pai A[2][4][13],pai paidui[104])
  83 {
  84 int i,m,x,y,z,a[104]={0};
  85 srand((unsigned)time(NULL));
  86 for(i=1;i<=104;i++)
  87 {
  88 while(a[m=rand()%104]);
  89 a[m]=i;
  90 }
  91 for(i=0;i<=103;i++)
  92 {
  93 x=(a[i]-1)/52;
  94 y=((a[i]-1)-52*x)/13;
  95 z=(a[i]-1)%13;
  96 paidui[i]=A[x][y][z];
  97 }
  98 }
  99 void Xipai(pai paidui[104],int*paiduishu,pai qipaidui[104],int*qipaishu)
 100 {
 101 int i,m,a[104]={0};
 102 srand((unsigned)time(NULL));
 103 for(i=1;i<=(*qipaishu);i++)
 104 {
 105 while(a[m=rand()%(*qipaishu)]);
 106 a[m]=i;
 107 }
 108 for(i=0;i<=((*qipaishu)-1);i++)
 109 {
 110 paidui[i]=qipaidui[a[i]];
 111 qipaidui[a[i]].leixing=-1;
 112 (*paiduishu)++;
 113 (*qipaishu)--;
 114 }
 115 for(i=(*paiduishu);i<=103;i++)paidui[i].leixing=-1;
 116 }
 117 pai Mo1pai(pai A[104],int *x,pai B[104],int*y,int *b)
 118 {
 119 pai p;
 120 if((*x)==0)Xipai(A,x,B,y);
 121 else if((*x)<0)printf("摸牌参数错误！");
 122 else;
 123 p=A[104-(*x)];
 124 (*x)--;
 125 (*b)++;
 126 return(p);
 127 }
 128 struct wujiang
 129 {
 130 char name;
 131 int tili;
 132 int tilishangxian;
 133 int shoupaishangxian;
 134 int huihekaishi;
 135 int panding;
 136 int mopai;
 137 int chupai;
 138 int qipai;
 139 int huihejieshu;
 140 int juese;
 141 pai shoupai[20];
 142 int shoupaishu;
 143 pai zhuangbei[4];
 144 int zhuangbeishu;
 145 pai pandingpai[3];
 146 int pandingshu;
 147 int juli[1];
 148 void Kanshoupai()
 149 {
 150 printf("玩家当前手牌：\n");
 151 if(shoupaishu)
 152 {
 153 int m;
 154 for(m=0;m<=(shoupaishu-1);m++)
 155 {
 156 printf("%d ",m);
 157 (shoupai[m]).Kanpai();
 158 }
 159 }
 160 else printf("空城！\n");
 161 printf("\n");
 162 }
 163 void Kanzhuangbei()
 164 {
 165 if(juese)printf("玩家");
 166 else printf("电脑");
 167 printf("当前装备：\n");
 168 printf("0 武器： ");
 169 if((zhuangbei[0]).leixing==-1)printf("空\n");
 170 else (zhuangbei[0]).Kanpai();
 171 printf("1 防具： ");
 172 if((zhuangbei[1]).leixing==-1)printf("空\n");
 173 else (zhuangbei[1]).Kanpai();
 174 printf("2 进攻马： ");
 175 if((zhuangbei[2]).leixing==-1)printf("空\n");
 176 else (zhuangbei[2]).Kanpai();
 177 printf("3 防御马： ");
 178 if((zhuangbei[3]).leixing==-1)printf("空\n");
 179 else (zhuangbei[3]).Kanpai();
 180 printf("\n");
 181 }
 182 void Kanpandingpai()
 183 {
 184 if(juese)printf("玩家");
 185 else printf("电脑");
 186 printf("当前判定区：\n");
 187 if((pandingpai[0]).leixing==-1)printf("空\n");
 188 else
 189 {
 190 printf("0 ");
 191 (pandingpai[0]).Kanpai();
 192 if((pandingpai[1]).leixing==-1);
 193 else
 194 {
 195 printf("1 ");
 196 (pandingpai[1]).Kanpai();
 197 if((pandingpai[2]).leixing==-1);
 198 else
 199 {
 200 printf("2 ");
 201 (pandingpai[2]).Kanpai();
 202 }
 203 }
 204 }
 205 }
 206 };
 207 void Mopai(int*shoupaishu,pai shoupai[20],pai A[104],int *x,pai B[104],int*y,int juese)
 208 {
 209 if(juese)printf("玩家从牌堆摸2张牌\n");
 210 else printf("电脑从牌堆摸2张牌\n");
 211 pai p;
 212 p=Mo1pai(A,x,B,y,shoupaishu);
 213 shoupai[*shoupaishu-1]=p;
 214 pai q;
 215 q=Mo1pai(A,x,B,y,shoupaishu);
 216 shoupai[*shoupaishu-1]=q;
 217 int m;
 218 if(juese)
 219 {
 220 printf("玩家当前手牌：\n");
 221 for(m=0;m<=(*shoupaishu-1);m++)
 222 {
 223 printf("%d ",m);
 224 (shoupai[m]).Kanpai();
 225 }
 226 }
 227 printf("牌堆还剩%d张牌！\n\n",*x);
 228 }
 229 void Qishishoupai(wujiang *w,pai A[104],int *x,pai B[104],int*y)
 230 {
 231 pai a;
 232 a=Mo1pai(A,x,B,y,&((*w).shoupaishu));
 233 (*w).shoupai[(*w).shoupaishu-1]=a;
 234 pai b;
 235 b=Mo1pai(A,x,B,y,&((*w).shoupaishu));
 236 (*w).shoupai[(*w).shoupaishu-1]=b;
 237 pai c;
 238 c=Mo1pai(A,x,B,y,&((*w).shoupaishu));
 239 (*w).shoupai[(*w).shoupaishu-1]=c;
 240 pai d;
 241 d=Mo1pai(A,x,B,y,&((*w).shoupaishu));
 242 (*w).shoupai[(*w).shoupaishu-1]=d;
 243 int m;
 244 if((*w).juese)printf("玩家从牌堆摸4张牌\n");
 245 else printf("电脑从牌堆摸4张牌\n");
 246 if((*w).juese)
 247 {
 248 printf("玩家当前手牌：\n");
 249 for(m=0;m<=((*w).shoupaishu-1);m++)
 250 {
 251 printf("%d ",m);
 252 ((*w).shoupai[m]).Kanpai();
 253 }
 254 }
 255 printf("牌堆还剩%d张牌！\n\n",*x);
 256 }
 257 void Panding(pai paidui[104],int*paiduishu,pai qipaidui[104],int*qipaishu)
 258 {
 259 paidui[*paiduishu].Kanpai();
 260 qipaidui[*qipaishu]=paidui[*paiduishu];
 261 (*paiduishu)--;
 262 (*qipaishu)++;
 263 }
 264 pai Zhangba(wujiang*w,pai qipaidui[104],int*qipaishu)
 265 {
 266 int x,y;
 267 pai p;
 268 for(;;)
 269 {
 270 int i,j;
 271 printf("请输入任意两张手牌之前的编号，以空格隔开，以回车结束！\n");
 272 scanf("%d",&x);
 273 scanf("%d",&y);
 274 if((x>=0)&&(x<(*w).shoupaishu)&&(y>=0)&&(y<(*w).shoupaishu-1))
 275 {
 276 switch((((*w).shoupai[x].huase)%2)+(((*w).shoupai[y].huase)%2))
 277 {
 278 case 0:p.yanse=0;break;
 279 case 2:p.yanse=1;break;
 280 case 1:p.yanse=2;break;
 281 default:printf("【丈八蛇矛】函数参数错误！\n");
 282 }
 283 qipaidui[*qipaishu]=(*w).shoupai[x];
 284 (*w).shoupai[x].leixing=-1;
 285 ((*w).shoupaishu)--;
 286 (*qipaishu)++ 
                       
                    
                    
 
                      




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