在线时间:8:00-16:00
迪恩网络APP
随时随地掌握行业动态
扫描二维码
关注迪恩网络微信公众号
★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★ Given a non-negative integer, you could swap two digits at most once to get the maximum valued number. Return the maximum valued number you could get. Example 1: Input: 2736 Output: 7236 Explanation: Swap the number 2 and the number 7. Example 2: Input: 9973 Output: 9973 Explanation: No swap. Note:
给定一个非负整数,你至多可以交换一次数字中的任意两位。返回你能得到的最大值。 示例 1 : 输入: 2736 输出: 7236 解释: 交换数字2和数字7。 示例 2 : 输入: 9973 输出: 9973 解释: 不需要交换。 注意:
Runtime: 8 ms
Memory Usage: 19 MB
1 class Solution { 2 func maximumSwap(_ num: Int) -> Int { 3 var arr:[Character] = Array(String(num)) 4 var res:Int = num 5 var n:Int = arr.count 6 var str:String = String() 7 for i in 0..<n 8 { 9 for j in (i + 1)..<n 10 { 11 arr.swapAt(i,j) 12 str = String(arr) 13 res = max(res, Int(str) ?? 0) 14 arr.swapAt(i,j) 15 } 16 } 17 return res 18 } 19 } 8ms 1 class Solution { 2 func maximumSwap(_ num: Int) -> Int { 3 let str = String(num) 4 var arr = Array(str) 5 var sortedNumbers = arr.sorted() 6 sortedNumbers = sortedNumbers.reversed() 7 8 var index = 0 9 while index < arr.count - 1 && arr[index] == sortedNumbers[index]{ 10 index += 1 11 } 12 if index >= arr.count - 1 { 13 return num 14 } 15 let temp = arr[index] 16 var indexNeedChanged = index 17 for i in (index ..< arr.count).reversed() { 18 if arr[i] == sortedNumbers[index] { 19 indexNeedChanged = i 20 break 21 } 22 } 23 arr[index] = sortedNumbers[index] 24 arr[indexNeedChanged] = temp 25 let ns = String(arr) 26 return Int(ns)! 27 } 28 } 20ms 1 class Solution { 2 func maximumSwap(_ num: Int) -> Int { 3 var nums = [String]() 4 for char in "\(num)" { 5 nums.append(char.description) 6 } 7 8 let count = nums.count 9 for i in 0..<count - 1 { 10 var mark = count - 1 11 for j in (i + 1..<count).reversed() { 12 if nums[j] > nums[mark] { 13 mark = j 14 } 15 } 16 print(i) 17 print(mark) 18 if nums[mark] > nums[i] { 19 let temp = nums[i] 20 nums[i] = nums[mark] 21 nums[mark] = temp 22 return Int(nums.joined()) ?? 0 23 } 24 } 25 return num 26 } 27 } 24ms 1 class Solution { 2 func maximumSwap(_ num: Int) -> Int { 3 var num = num 4 var nums: [Int] = [] 5 6 while num > 0 { 7 nums.append(num % 10) 8 num /= 10 9 } 10 11 for n in stride(from: nums.count-1, to: -1, by: -1) { 12 var mx = nums[0] 13 var idx = 0 14 for k in 0..<n { 15 if nums[k] > mx { 16 mx = nums[k] 17 idx = k 18 } 19 } 20 if mx > nums[n] { 21 nums.swapAt(idx, n) 22 break 23 } 24 } 25 26 var res = 0 27 for n in nums.reversed() { 28 res = res * 10 + n 29 } 30 31 return res 32 } 33 }
|
请发表评论