• 设为首页
  • 点击收藏
  • 手机版
    手机扫一扫访问
    迪恩网络手机版
  • 关注官方公众号
    微信扫一扫关注
    公众号

[Swift]LeetCode492.构造矩形|ConstructtheRectangle

原作者: [db:作者] 来自: [db:来源] 收藏 邀请

★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★
➤微信公众号:山青咏芝(shanqingyongzhi)
➤博客园地址:山青咏芝(https://www.cnblogs.com/strengthen/
➤GitHub地址:https://github.com/strengthen/LeetCode
➤原文地址:https://www.cnblogs.com/strengthen/p/9804151.html 
➤如果链接不是山青咏芝的博客园地址,则可能是爬取作者的文章。
➤原文已修改更新!强烈建议点击原文地址阅读!支持作者!支持原创!
★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★

热烈欢迎,请直接点击!!!

进入博主App Store主页,下载使用各个作品!!!

注:博主将坚持每月上线一个新app!!!

For a web developer, it is very important to know how to design a web page's size. So, given a specific rectangular web page’s area, your job by now is to design a rectangular web page, whose length L and width W satisfy the following requirements:

1. The area of the rectangular web page you designed must equal to the given target area.

2. The width W should not be larger than the length L, which means L >= W.
3. The difference between length L and width W should be as small as possible.

You need to output the length L and the width W of the web page you designed in sequence. 

Example:

Input: 4
Output: [2, 2]
Explanation: The target area is 4, and all the possible ways to construct it are [1,4], [2,2], [4,1]. 
But according to requirement 2, [1,4] is illegal; according to requirement 3,  [4,1] is not optimal compared to [2,2]. So the length L is 2, and the width W is 2.

 Note:

  1. The given area won't exceed 10,000,000 and is a positive integer
  2. The web page's width and length you designed must be positive integers.

作为一位web开发者, 懂得怎样去规划一个页面的尺寸是很重要的。 现给定一个具体的矩形页面面积,你的任务是设计一个长度为 L 和宽度为 W 且满足以下要求的矩形的页面。要求:

1. 你设计的矩形页面必须等于给定的目标面积。

2. 宽度 W 不应大于长度 L,换言之,要求 L >= W 。

3. 长度 L 和宽度 W 之间的差距应当尽可能小。

你需要按顺序输出你设计的页面的长度 L 和宽度 W。

示例:

输入: 4
输出: [2, 2]
解释: 目标面积是 4, 所有可能的构造方案有 [1,4], [2,2], [4,1]。
但是根据要求2,[1,4] 不符合要求; 根据要求3,[2,2] 比 [4,1] 更能符合要求. 所以输出长度 L 为 2, 宽度 W 为 2。

说明:

  1. 给定的面积不大于 10,000,000 且为正整数。
  2. 你设计的页面的长度和宽度必须都是正整数。

 8ms

1 class Solution {
2     func constructRectangle(_ area: Int) -> [Int] {
3         var w = Int(sqrt(Double(area)))
4         while area % w != 0 {
5             w -= 1
6         }
7         return [area / w, w]
8     }
9 }

8ms

 1 class Solution {
 2     func constructRectangle(_ area: Int) -> [Int] {
 3         var minDiff = Int.max
 4         var minDiffWidth: Int?
 5         let maxWidth = Int(ceil(sqrt(Double(area))))
 6         
 7         for width in 1 ... maxWidth {
 8             guard area % width == 0 else { continue }
 9             
10             let length = area / width
11             if length >= width, length - width < minDiff {
12                 minDiff = length - width
13                 minDiffWidth = width
14             }
15         }
16         if let minDiffWidth = minDiffWidth {
17             return [area / minDiffWidth, minDiffWidth]
18         } else {
19             return [area, 1]
20         }
21     }
22 }

12ms

 1 class Solution {
 2     func constructRectangle(_ area: Int) -> [Int] {
 3          let maxW = Int(sqrt(Double(area)))
 4         var result = [area,1]
 5          if maxW >= 2 {
 6             for i in 2...maxW {
 7                 if area % i == 0 {
 8                     result = [area / i,i]
 9                 }
10             }
11         }
12         return result
13     }
14 }

12ms

1 class Solution {
2     func constructRectangle(_ area: Int) -> [Int] {
3         var n = Int(sqrt(Double(area)))
4         while area % n != 0 {
5             n -= 1
6         }
7         return [max(n, area/n), min(n, area/n)]
8     }
9 }

20ms

 1 class Solution {
 2     func constructRectangle(_ area: Int) -> [Int] {
 3         var maxW = Int(sqrt(Double(area)))
 4         var result = [area,1]
 5         while maxW >= 2 {
 6             if area % maxW == 0 {
 7                 result = [area / maxW,maxW]
 8                 break
 9             }
10             maxW -= 1
11         }       
12         return result
13     }
14 }

116ms

 1 class Solution {
 2     func constructRectangle(_ area: Int) -> [Int] {
 3         guard area > 0 else { return [0, 0] }
 4         let sqr = sqrt(Double(area))
 5         var i = Int(sqr)
 6         var j = Int(sqr)
 7         var prod = i*j
 8         while prod != area {
 9             if prod > area {
10                 i -= 1
11             } else if prod < area {
12                 j += 1
13             }
14             prod = i*j
15         }
16         return [j, i] 
17         
18     }
19 }

 


鲜花

握手

雷人

路过

鸡蛋
该文章已有0人参与评论

请发表评论

全部评论

专题导读
上一篇:
Swift中的类型转换发布时间:2022-07-13
下一篇:
Moving Swiftly(从OC切换到Swift)发布时间:2022-07-13
热门推荐
热门话题
阅读排行榜

扫描微信二维码

查看手机版网站

随时了解更新最新资讯

139-2527-9053

在线客服(服务时间 9:00~18:00)

在线QQ客服
地址:深圳市南山区西丽大学城创智工业园
电邮:jeky_zhao#qq.com
移动电话:139-2527-9053

Powered by 互联科技 X3.4© 2001-2213 极客世界.|Sitemap