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★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★ Given a 2D binary matrix filled with 0's and 1's, find the largest rectangle containing only 1's and return its area. Example: Input: [ ["1","0","1","0","0"], ["1","0","1","1","1"], ["1","1","1","1","1"], ["1","0","0","1","0"] ] Output: 6 给定一个仅包含 0 和 1 的二维二进制矩阵,找出只包含 1 的最大矩形,并返回其面积。 示例: 输入: [ ["1","0","1","0","0"], ["1","0","1","1","1"], ["1","1","1","1","1"], ["1","0","0","1","0"] ] 输出: 6 160ms 1 class Solution { 2 func maximalRectangle(_ matrix: [[Character]]) -> Int { 3 if matrix.count == 0 || matrix[0].count == 0{ 4 return 0 5 } 6 var ans = 0 7 var rowArr = Array(repeating:0,count:matrix[0].count + 1) 8 for y in stride(from:0,to:matrix.count,by:1) { 9 for x in stride(from:0,to:matrix[0].count,by:1) { 10 if matrix[y][x] == "1" { 11 rowArr[x] += 1 12 } else { 13 rowArr[x] = 0 14 } 15 } 16 ans = max(ans,getLargetRect(rowArr)) 17 } 18 return ans 19 } 20 21 func getLargetRect(_ rowArr:[Int]) -> Int { 22 var stack = [Int]() 23 var maxArea = 0 24 for (index,height) in rowArr.enumerated() { 25 while let last = stack.last, rowArr[last] > height { 26 stack.removeLast() 27 var width = 0 28 if stack.isEmpty { 29 width = index 30 } else { 31 width = index - stack.last! - 1 32 } 33 maxArea = max(maxArea, width * rowArr[last] ) 34 } 35 36 stack.append(index) 37 } 38 return maxArea 39 } 40 } 168ms 1 class Solution { 2 func maximalRectangle(_ matrix: [[Character]]) -> Int { 3 let n = matrix.count 4 guard n > 0 else { 5 return 0 6 } 7 let m = matrix[0].count 8 9 var mark = Array(repeatElement(Array(repeatElement(0, count: m)), count: n)) 10 for i in (0..<n).reversed() { 11 var count = 0 12 for j in (0..<m).reversed() { 13 if matrix[i][j] == "1" { 14 count += 1 15 } else { 16 count = 0 17 } 18 mark[i][j] = count 19 } 20 } 21 22 var result = 0 23 for i in 0..<n { 24 for j in 0..<m { 25 var minColumn = m 26 var row = i 27 while row < n && mark[row][j] != 0 { 28 minColumn = min(minColumn, mark[row][j]) 29 result = max(result, (row - i + 1) * minColumn) 30 row += 1 31 } 32 } 33 } 34 return result 35 } 36 } 200ms 1 class Solution { 2 3 func maximalRectangle(_ matrix: [[Character]]) -> Int { 4 5 if matrix.count == 0 || matrix[0].count == 0 { 6 return 0 7 } 8 9 var heights = [Int](repeating: 0, count: matrix[0].count) 10 var s = 0 11 12 for i in 0..<matrix.count { 13 14 for j in 0..<matrix[i].count { 15 16 if matrix[i][j] == "1" { 17 18 heights[j] += 1 19 20 } else { 21 heights[j] = 0 22 } 23 } 24 25 s = max(s, largestRectangleArea(heights)) 26 } 27 28 return s 29 } 30 31 func largestRectangleArea(_ heights: [Int]) -> Int { 32 33 if heights.count == 0 { 34 return 0 35 } 36 37 var myHeights: [Int] = heights 38 myHeights.append(0) 39 40 41 var s = 0 42 //swift中没有栈,使用数组代替,永远操作最后一位 43 var stack: [Int] = [] 44 var i = 0 45 46 while i < myHeights.count { 47 48 if stack.count == 0 || myHeights[stack.last!] < myHeights[i] { 49 50 stack.append(i) 51 i += 1 52 } else { 53 54 let j = stack.last! 55 stack.removeLast() 56 57 //如果栈为空,说明数组第一位即构成矩形的左侧边界,此时索引大小即矩形长度 58 //如果不为空,用栈顶索引和当前索引计算矩形长度 59 s = max(s, myHeights[j]*(stack.isEmpty ? i : i - 1 - stack.last!)) 60 } 61 } 62 return s 63 } 64 65 } 416ms 1 class Solution { 2 func maximalRectangle(_ matrix: [[Character]]) -> Int { 3 guard matrix.count > 0 && matrix[0].count > 0 else { 4 return 0 5 } 6 let m = matrix.count 7 let n = matrix[0].count 8 var left = [Int](repeating: 0, count: n) 9 var right = [Int](repeating: n, count: n) 10 var height = [Int](repeating: 0, count: n) 11 var result = 0 12 for i in 0..<m { 13 var currentLeft = 0 14 var currentRight = n 15 for j in 0..<n { 16 if (matrix[i][j] == "1") { 17 left[j] = max(left[j], currentLeft) 18 height[j] = height[j] + 1 19 } else { 20 left[j] = 0 21 currentLeft = j + 1 22 height[j] = 0 23 } 24 if (matrix[i][n - j - 1] == "1") { 25 right[n - j - 1] = min(right[n - j - 1], currentRight) 26 } else { 27 currentRight = n - j - 1 28 right[n - j - 1] = n 29 } 30 } 31 for j in 0..<n { 32 result = max(result, (right[j] - left[j]) * height[j]) 33 } 34 } 35 return result 36 } 37 } 436ms 1 class HistoArea { 2 func largestRectangleArea(_ heights: [Int]) -> Int { 3 var stack = [Int]() 4 var max = 0 5 for i in 0..<heights.count { 6 if stack.count == 0 || heights[i]>=heights[stack[stack.count-1]] { 7 stack.append(i) 8 } else { 9 while stack.count > 0 && heights[i] < heights[stack[stack.count-1]] { 10 let area = eval(&stack, heights, i) 11 if area > max { 12 max = area 13 } 14 } 15 stack.append(i) 16 } 17 } 18 while stack.count > 0 { 19 let area = eval(&stack, heights, heights.count) 20 if area > max { 21 max = area 22 } 23 } 24 return max 25 } 26 27 func eval(_ stack: inout [Int], _ heights: [Int], _ end: Int) -> Int { 28 let idx = stack.last! 29 stack.removeLast() 30 var area = 0 31 32 if let start = stack.last { 33 area = heights[idx]*(end-start-1) 34 } else { 35 area = heights[idx]*end 36 } 37 return area 38 } 39 } 40 41 class Solution { 42 func maximalRectangle(_ matrix: [[Character]]) -> Int { 43 let hist = HistoArea() 44 var histogram = [Int]() 45 if matrix.count == 0 { 46 return 0 47 } 48 for i in 0..<matrix[0].count { 49 histogram.append(0) 50 } 51 var maxArea = 0 52 53 for i in 0..<matrix.count { 54 for j in 0..<matrix[0].count { 55 if matrix[i][j] == "1" { 56 histogram[j] += 1 57 } else { 58 histogram[j] = 0 59 } 60 } 61 let area = hist.largestRectangleArea(histogram) 62 if area > maxArea { 63 maxArea = area 64 } 65 } 66 return maxArea 67 } 68 } 452ms 1 class Solution { 2 func maximalRectangle(_ matrix: [[Character]]) -> Int { 3 if matrix.count == 0 || matrix[0].count == 0 { 4 return 0 5 } 6 7 let rLen = matrix.count 8 let cLen = matrix[0].count 9 var h = [Int](repeating: 0, count: cLen + 1) 10 var maxValue = 0 11 12 for row in 0..<rLen { 13 var stack = [Int]() 14 for i in 0..<(cLen + 1) { 15 if i < cLen { 16 if matrix[row][i] == "1" { 17 h[i] += 1 18 } else { 19 h[i] = 0 20 } 21 } 22 if stack.isEmpty || h[stack.last!] <= h[i] { 23 stack.append(i) 24 } else { 25 while !stack.isEmpty && h[i] < h[stack.last!] { 26 let top = stack.removeLast() 27 let area = h[top] * (stack.isEmpty ? i : (i - stack.last! - 1)) 28 if area > maxValue { 29 maxValue = area 30 } 31 } 32 stack.append(i) 33 } 34 } 35 } 36 return maxValue 37 } 38 } 588ms 1 class Solution { 2 func maximalRectangle(_ matrix: [[Character]]) -> Int { 3 let n = matrix.count 4 guard n > 0 else { 5 return 0 6 } 7 let m = matrix[0].count 8 9 var mark = Array(repeatElement(Array(repeatElement(0, count: m)), count: n)) 10 for i in (0..<n).reversed() { 11 var count = 0 12 for j in (0..<m).reversed() { 13 if matrix[i][j] == "1" { 14 count += 1 15 } else { 16 count = 0 17 } 18 mark[i][j] = count 19 } 20 } 21 22 var result = 0 23 for i in 0..<n { 24 for j in 0..<m { 25 var minColumn = m 26 var row = i 27 while row < n && mark[row][j] != 0 { 28 minColumn = min(minColumn, mark[row][j]) 29 result = max(result, (row - i + 1) * minColumn) 30 row += 1 31 } 32 } 33 } 34 return result 35 } 36 }
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