c/c++ 标准库 迭代器
begin和end运算符返回的具体类型由对象是否是常量决定,如果对象是常量,begin和end返回const_iterator;如果对象不是常量,返回iteraotor
### 1,但凡是使用了迭代器的循环体,都不要向迭代器所属的容器添加元素。
2,不能在范围for循环中向vector对象添加元素
标准库 迭代器(iterator)的小例子
test1~test8
#include <iostream>
#include <string>
#include <vector>
using namespace std;
int main(){
//test1
/*
string s("abc bdc");
auto it = s.begin();
while(it != s.end()){
*it = toupper(*it);
++it;
}
cout << s << endl;
*/
//test2
/*
string s("abd ddd");
for(auto it = s.begin(); it != s.end() && !isspace(*it); ++it){
*it = toupper(*it);
}
cout << s << endl;
*/
//test3 不可改变vector::const_iterator类型
/*
vector<int>:: iterator it;
vector<int>:: const_iterator it2;
vector<int> v(5,1);
it = v.begin();
it2 = v.begin();
vector<int> const cv(5,2);
//it = cv.begin();//it是可改变的vector::iterator,所以编译错误
for(auto s : v){
cout << s;
}
cout << endl;
*/
//test4 不可改变string::const_iterator类型
/*
string::iterator sit;
string::const_iterator sit2;
string s1("abc");
sit2 = s1.begin();
while(sit2 != s1.end()){
//*sit2 = toupper(*sit2);
cout << *sit2;
++sit2;
}
cout << endl;
*/
//test5 cbegin和cend,返回const类型的iterator
/*
string s1("aaaa");
auto it1 = s1.cbegin();
//*it1 = 'c';//不可以通过const类型的iterator改变原来的对象
cout << s1 << endl;
vector<int> v(4,2);
auto vit1 = v.cbegin();
//*vit1 = 5;//不可以通过const类型的iterator改变原来的对象
*/
//test6 string迭代器运算
/*
string s("abcd");
string s1("abc");
vector<int> v(5,3);
auto it1 = s.begin();
auto it2 = s.begin();
if(it1 == it2){
cout << "=" << endl;
}
++it1;
it1 += 1;
if(it1 > it2){
cout << ">" << endl;
cout << it1 - it2 << endl;
}
string::difference_type juli = it1 - it2;
cout << juli << endl;
*/
//test7 vector迭代器运算
/*
vector<string> s(4,"abcd");
vector<string> s1(5,"abc");
auto it1 = s.begin();
auto it2 = s.begin();
if(it1 == it2){
cout << "=" << endl;
}
++it1;
it1 += 1;
if(it1 > it2){
cout << ">" << endl;
cout << it1 - it2 << endl;
}
vector<string>::difference_type juli = it1 - it2;
cout << juli << endl;
*/
//test8 利用迭代器实现二分法
vector<string> v{"a","b","c","d","e"};
string target("b");
vector<string>::size_type idx = 0;
auto beg = v.begin();
auto mid = v.begin() + v.size() / 2;
auto end = v.end();
while(mid != end && *mid != target){
if(target < *mid)
end = mid;
else
beg = mid + 1;
mid = beg + (end - beg) / 2;
}
if(mid == end){
cout << "not found" << endl;
}
else{
idx = mid - v.begin();
cout << idx << ":" << *mid << endl;
}
}
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