传统的C++获取时间的方法须要分平台来定义。

相信百度代码也不少。

我自己写了下，例如以下。

const std::string getCurrentSystemTime()
{
	
	if (PLATFORM_ANDROID || PLATFORM_IOS)
	{
		struct timeval s_now;
		struct tm* p_tm;
		gettimeofday(&s_now,NULL);
		p_tm = localtime((const time_t*)&s_now.tv_sec);
		char date[60] = {0};
		sprintf(date, "%d-%02d-%02d      %02d:%02d:%02d",
			(int)p_tm->tm_year + 1900,(int)p_tm->tm_mon + 1,(int)p_tm->tm_mday,
			(int)p_tm->tm_hour,(int)p_tm->tm_min,(int)p_tm->tm_sec);
		return std::string(date);
	}
	if (PLATFORM_W32)
	{
		struct tm* p_tm;
		time_t timep;
		time(&timep);
		p_tm = localtime(&timep);
		char date[60] = {0};
		sprintf(date, "%d-%02d-%02d      %02d:%02d:%02d",
			(int)p_tm->tm_year + 1900,(int)p_tm->tm_mon + 1,(int)p_tm->tm_mday,
			(int)p_tm->tm_hour,(int)p_tm->tm_min,(int)p_tm->tm_sec);
		log("%s",date);
		return std::string(date);
	}
	return "";
}

二、C++11 std标准库跨平台方法

答案是肯定的。

非常easy的。代码例如以下：

const std::string getCurrentSystemTime()
{
	auto tt = std::chrono::system_clock::to_time_t
	(std::chrono::system_clock::now());
	struct tm* ptm = localtime(&tt);
	char date[60] = {0};
	sprintf(date, "%d-%02d-%02d      %02d:%02d:%02d",
		(int)ptm->tm_year + 1900,(int)ptm->tm_mon + 1,(int)ptm->tm_mday,
		(int)ptm->tm_hour,(int)ptm->tm_min,(int)ptm->tm_sec);
	return std::string(date);
}

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http://blog.csdn.net/q229827701/article/details/41015483