vue.js使用typescript踩坑记

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原作者: [db:作者] 来自: [db:来源] 收藏邀请

最近在把https://github.com/renrenio/renren-fast-vue这个项目转为typescript，在此记录一下遇到的小坑

name坑

原代码如下图

<script>
  import SubMenu from './main-sidebar-sub-menu'
  export default {
    name: 'sub-menu',
    props: {
      menu: {
        type: Object,
        required: true
      },
      dynamicMenuRoutes: {
        type: Array,
        required: true
      }
    },
    components: {
      SubMenu
    },
    computed: {
      sidebarLayoutSkin: {
        get () { return this.$store.state.common.sidebarLayoutSkin }
      }
    },
    methods: {
      // 通过menuId与动态(菜单)路由进行匹配跳转至指定路由
      gotoRouteHandle (menu) {
        var route = this.dynamicMenuRoutes.filter(item => item.meta.menuId === menu.menuId)
        if (route.length >= 1) {
          this.$router.push({ name: route[0].name })
        }
      }
    }
  }
</script>

转TS后代码如下：

<script lang="ts">
import {  Component,  Prop,  Vue,  Watch,  Provide,  Inject} from "vue-property-decorator";
import  SubMenu from "./main-sidebar-sub-menu.vue";
import { isURL } from "../utils/validate";

@Component({  
  components: {
    "sub-menu": SubMenu
  }
})
export default class MainSidebarSubMenu extends Vue {
  name:'sub-menu';

  @Prop({ type: Object, required: true }) readonly menu!: object;

  @Prop({ type: Array, required: true }) readonly dynamicMenuRoutes!: any[];

  get sidebarLayoutSkin() {
    return this.$store.state.common.sidebarLayoutSkin
  }

  // 通过menuId与动态(菜单)路由进行匹配跳转至指定路由
  gotoRouteHandle(menu:any) {
    var route = this.dynamicMenuRoutes.filter(
      item => item.meta.menuId === menu.menuId
    );
    if (route.length >= 1) {
      this.$router.push({ name: route[0].name });
    }
  }
}
</script>

报错如下：

[Vue warn]: Unknown custom element: <sub-menu> - did you register the component correctly? For recursive components, make sure to provide the "name" option.

很明显，提示没有提供name属性，但是代码里面明显是有写name='sub-menu'的，查了一下vue的api，发现这个name并不是一个普通的属性，作为特殊的选项，基本是放在@Component这个装饰器中，查看文档后添加name，正常运行