题目太长了!下载地址【传送门】
第1题
简述:识别图片上的数字。
第1步:读取数据文件:
%% Setup the parameters you will use for this part of the exercise input_layer_size = 400; % 20x20 Input Images of Digits num_labels = 10; % 10 labels, from 1 to 10 % (note that we have mapped "0" to label 10) % Load Training Data fprintf(\'Loading and Visualizing Data ...\n\') load(\'ex3data1.mat\'); % training data stored in arrays X, y m = size(X, 1); % Randomly select 100 data points to display rand_indices = randperm(m); sel = X(rand_indices(1:100), :); displayData(sel);
第2步:实现displayData函数:
function [h, display_array] = displayData(X, example_width) % Set example_width automatically if not passed in if ~exist(\'example_width\', \'var\') || isempty(example_width) example_width = round(sqrt(size(X, 2))); end % Gray Image colormap(gray); % Compute rows, cols [m n] = size(X); example_height = (n / example_width); % Compute number of items to display display_rows = floor(sqrt(m)); display_cols = ceil(m / display_rows); % Between images padding pad = 1; % Setup blank display display_array = - ones(pad + display_rows * (example_height + pad), ... pad + display_cols * (example_width + pad)); % Copy each example into a patch on the display array curr_ex = 1; for j = 1:display_rows for i = 1:display_cols if curr_ex > m, break; end % Copy the patch % Get the max value of the patch max_val = max(abs(X(curr_ex, :))); display_array(pad + (j - 1) * (example_height + pad) + (1:example_height), ... pad + (i - 1) * (example_width + pad) + (1:example_width)) = ... reshape(X(curr_ex, :), example_height, example_width) / max_val; curr_ex = curr_ex + 1; end if curr_ex > m, break; end end % Display Image h = imagesc(display_array, [-1 1]); % Do not show axis axis image off drawnow; end
运行结果:
第3步:计算θ:
lambda = 0.1; [all_theta] = oneVsAll(X, y, num_labels, lambda);
其中oneVsAll函数:
function [all_theta] = oneVsAll(X, y, num_labels, lambda) % Some useful variables m = size(X, 1); n = size(X, 2); % You need to return the following variables correctly all_theta = zeros(num_labels, n + 1); % Add ones to the X data matrix X = [ones(m, 1) X]; for c = 1:num_labels, initial_theta = zeros(n+1, 1); options = optimset(\'GradObj\', \'on\', \'MaxIter\', 50); [theta] = ... fmincg(@(t)(lrCostFunction(t, X, (y==c), lambda)), initial_theta, options); all_theta(c,:) = theta; end; end
第4步:实现lrCostFunction函数:
function [J, grad] = lrCostFunction(theta, X, y, lambda) % Initialize some useful values m = length(y); % number of training examples % You need to return the following variables correctly J = 0; grad = zeros(size(theta)); theta2 = theta(2:end,1); h = sigmoid(X*theta); J = 1/m*(-y\'*log(h)-(1-y\')*log(1-h)) + lambda/(2*m)*sum(theta2.^2); theta(1,1) = 0; grad = 1/m*(X\'*(h-y)) + lambda/m*theta; grad = grad(:); end
第5步:实现sigmoid函数:
function g = sigmoid(z) g = 1.0 ./ (1.0 + exp(-z)); end
第6步:计算预测的准确性:
pred = predictOneVsAll(all_theta, X); fprintf(\'\nTraining Set Accuracy: %f\n\', mean(double(pred == y)) * 100);
其中predictOneVsAll函数:
function p = predictOneVsAll(all_theta, X) m = size(X, 1); num_labels = size(all_theta, 1); % You need to return the following variables correctly p = zeros(size(X, 1), 1); % Add ones to the X data matrix X = [ones(m, 1) X]; g = zeros(size(X, 1), num_labels); for c = 1: num_labels, theta = all_theta(c, :); g(:, c) = sigmoid(X*theta\'); end [value, p] = max(g, [], 2); end
运行结果:
第2题
简介:使用神经网络实现数字识别(Θ已提供)
第1步:读取文档数据:
%% Setup the parameters you will use for this exercise input_layer_size = 400; % 20x20 Input Images of Digits hidden_layer_size = 25; % 25 hidden units num_labels = 10; % 10 labels, from 1 to 10 % (note that we have mapped "0" to label 10) % Load Training Data fprintf(\'Loading and Visualizing Data ...\n\') load(\'ex3data1.mat\'); m = size(X, 1); % Randomly select 100 data points to display sel = randperm(size(X, 1)); sel = sel(1:100); displayData(X(sel, :)); % Load the weights into variables Theta1 and Theta2 load(\'ex3weights.mat\');
第2步:实现神经网络:
pred = predict(Theta1, Theta2, X); fprintf(\'\nTraining Set Accuracy: %f\n\', mean(double(pred == y)) * 100);
其中predict函数:
function p = predict(Theta1, Theta2, X) % Useful values m = size(X, 1); num_labels = size(Theta2, 1); % You need to return the following variables correctly p = zeros(size(X, 1), 1); X = [ones(m,1) X]; z2 = X*Theta1\'; a2 = sigmoid(z2); a2 = [ones(size(a2, 1), 1) a2]; z3 = a2*Theta2\'; a3 = sigmoid(z3) [values, p] = max(a3, [], 2) end
运行结果:
第3步:实现单个数字识别:
rp = randperm(m); for i = 1:m % Display fprintf(\'\nDisplaying Example Image\n\'); displayData(X(rp(i), :)); pred = predict(Theta1, Theta2, X(rp(i),:)); fprintf(\'\nNeural Network Prediction: %d (digit %d)\n\', pred, mod(pred, 10)); % Pause with quit option s = input(\'Paused - press enter to continue, q to exit:\',\'s\'); if s == \'q\' break end end
运行结果:
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