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没测试过这个 var Source: TMemoryStream; Response: TStringStream ; begin try // Set the properties for HTTP idHTTP.Request.Username := 'www '; idHTTP.Request.Password := 'www '; // idHTTP1.Request.ProxyServer := '11.133.190.13 '; // idHTTP1.Request.ProxyPort := StrToIntDef( '80 ', 80); idHTTP.Request.ContentType := 'application/x-www-form-urlencoded '; Response := TStringStream.Create( ' '); try Source := TMemoryStream.Create; try Source.LoadFromFile( 'unsub.xml '); //发送这个XML包,反向取消请求 idHTTP.Post( 'http://222.333.444.555/dsmp/dsmp.wsdl ', Source, Response); finally // Source.Free; end; memo.Lines.Text := Response.DataString;//返回的字串,可以把它存为XML就可以 memo.Lines.SaveToFile( 'unsubresp.xml '); //返回的反向取消应答包 finally Response.Free; end; finally end 这个方法试了 可以用 以下仅供参考,要求在web页面写特殊的字符,根据返回的结果判断是否登陆成功,用户名,密码方式见下:
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procedure TForm1.Button1Click(Sender: TObject); var Url: string; Response : TStringStream; Request : TStrings; begin Memo1.Clear; Response := TStringStream.Create( ' '); try Request := TStringList.Create; try Request.Append( 'txtUserId=hengli&txtPassword=ysj); url := 'http://192.168.1.33/nmmis/index.aspx '; IdHTTP1.Request.ContentType := 'application/x-www-form-urlencoded '; IdHTTP1.Post(Url, Request, Response); Memo1.Lines.Text := Response.DataString; finally FreeAndNil(Request); end; finally FreeAndNil(Response); end; end; 通过idhttp上传文件到web上,然后返回上传的文件路径。
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function UpLoagFile(FileName: String): string; var obj : TIdMultiPartFormDataStream; Url: String; begin obj := TIdMultiPartFormDataStream.Create; try obj.AddFile( 'Image ',FileName, GetMIMETypeFromFile(FileName)); http.Request.ContentType := obj.RequestContentType; obj.Position := 0; Url := 'http://192.168.1.44/insertImage.aspx '; Result := http.Post(Url, obj); finally obj.Free; end; end; 服务端,C#: private void Page_Load(object sender, System.EventArgs e) { foreach(string f in Request.Files.AllKeys) { string fileName, fullName; HttpPostedFile postFile = Request.Files[f]; if (postFile.ContentLength > 10) { fileName = postFile.FileName; //GetFileName( fileName, out fullName ); fullName = "UpLoad/aaa.jpg " postFile.SaveAs ( Server.MapPath ( fullName ) ); Response.Write (fullName); } } }
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