在做相关项目需要解决B样条插值问题,记录如下
感谢以下参考资料的帮助
% ref: 闭合 B 样条曲线控制点的快速求解算法及应用
% http://www.doc88.com/p-5714423317458.html
% https://blog.csdn.net/liumangmao1314/article/details/54588155
=============================
%计算B样条曲线控制点
function px = LU_B1(CPnum, V)
a = 1;
b = 4;
c = 1;
d = 1;
e = 1;
f = zeros(CPnum-1,1);
g = zeros(CPnum-2,1);
h = zeros(CPnum,1);
k = zeros(CPnum-1,1);
% get h[] & f[]
h(1) = b;
for i=1:CPnum-2
f(i) = a/h(i);
h(i+1) = b - f(i)*c;
end
% get g[] & f[n-1]
g(1) = d/h(1);
for i=1:CPnum-3
g(i+1) = -g(i)*c/h(i+1);
end
f(CPnum-1) = ( a-g(CPnum-2)*c )/h(CPnum-1);
% get k[] & h[n]
k(1) = e;
for i=1:CPnum-3
k(i+1) = -f(i)*k(i);
end
k(CPnum-1) = c - f(CPnum-2)*k(CPnum-2);
gksum = 0;
for i=1:CPnum-2
gksum = gksum + g(i)*k(i);
end
h(CPnum) = b - gksum - f(CPnum-1)*c;
% 矩阵求解过程,追的过程
x = zeros(CPnum,1);
x(1) = 6*V(end);
for i=1:CPnum-2
x(i+1) = 6*V(i) - f(i)*x(i);
end
gxsum = 0;
for i=1:CPnum-2
gxsum = gxsum + g(i)*x(i);
end
x(CPnum) = 6*V(CPnum-1) - gxsum - f(CPnum-1)*x(CPnum-1);
% 赶的过程
px = zeros(CPnum+2,1);
px(CPnum) = x(CPnum)/h(CPnum);
px(CPnum-1) = ( x(CPnum-1)-k(CPnum-1)*px(CPnum) )/h(CPnum-1);
for i=CPnum-2:-1:1
px(i) = ( x(i)-c*px(i+1)-k(i)*px(CPnum) )/h(i);
end
px(CPnum+1) = px(1);
px(CPnum+2) = px(2);
end
% 插值计算三次周期性b样条曲线
function p = Cubic_Bsp(u,x)
b(1) = ((1-u)^3)/6;
b(2) = (3*u^3-6*u^2+4)/6;
b(3) = (-3*u^3+3*u^2+3*u+1)/6;
b(4) = (u^3)/6;
p = x*b';
end
%test.m 测试
clear;clc
x = [-1;-1;1;1;0.2];
y = [1;-0.5;-1;1;0.8];
z = zeros(6,1);
z(3) = 1;
CPnum = size(x,1);
%x,y,z坐标分别计算B样条曲线控制点
px = LU_B1(CPnum, x);
py = LU_B1(CPnum, y);
pz = LU_B1(CPnum, z);
%首尾相连,曲线闭合
x(CPnum+1) = x(1);
y(CPnum+1) = y(1);
z(CPnum+1) = z(1);
figure;
plot3(x,y,z,'ro-');
hold on;
for i=1:CPnum%用这个循环
c=num2str(i);
c=[' ',c];
text(x(i),y(i),z(i),c)
%text(x(i),y(i),c)
end
plot3(px,py,pz,'g-');
for i=1:CPnum+1%用这个循环
c=num2str(i);
c=[' ',c];
text(px(i),py(i),pz(i),c)
plot3(px(i),py(i),pz(i),'*');
end
axis equal
px(CPnum+3) = px(3);
py(CPnum+3) = py(3);
pz(CPnum+3) = pz(3);
px(CPnum+4) = px(4);
py(CPnum+4) = py(4);
pz(CPnum+4) = pz(4);
%两点之间对10个点进行插值计算
nP = 10;
delta = 1.0/nP;
for j=1:CPnum
u = 0.0;
for i=1:nP
p = px';
Xi = p(j:j+3);
xx(i+(j-1)*nP) = Cubic_Bsp(u,Xi);
p = py';
Yi = p(j:j+3);
yy(i+(j-1)*nP) = Cubic_Bsp(u,Yi);
p = pz';
Zi = p(j:j+3);
zz(i+(j-1)*nP) = Cubic_Bsp(u,Zi);
u = u + delta;
end
end
xx(end+1) = x(1);
yy(end+1) = y(1);
zz(end+1) = z(1);
plot3(xx,yy,zz,'b--')
结果如图所示,红色为三维空间5个不共面点
绿色为B样条曲线控制点
蓝色为B样条拟合曲线
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