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标题: ios - JSQMessages ViewController 聊天而不在数据库中创建任何 child [打印本页]

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作者: 菜鸟教程小白    时间: 2022-12-11 19:19
标题: ios - JSQMessages ViewController 聊天而不在数据库中创建任何 child

我在 Viewcontroller 中使用了 JSQMessagesViewController。聊天以匿名用户打开。聊天工作正常，但我需要对数据库进行一些更改。因为数据库是它的火力基地。当任何消息进入它显示的数据库时，我正在我的数据库中创建一个 child ，首先它显示名为“消息”的 child ，并在消息下显示所有聊天消息，我想删除这个 child ，直接聊天应该在它进入数据库时​​显示，并且还应该直接接收所有消息，而不会干扰数据库中的任何子项。我的聊天代码是这样的，

import UIKit
import Firebase

import FirebaseDatabase

@objc class ChatViewViewController: JSQMessagesViewController, UINavigationControllerDelegate{

 var ref: DatabaseReference!
var Name : String?


 private var messages = [JSQMessage]()
lazy var messageRef = Database.database().reference().child("Message")
 var newMessageRefHandle: DatabaseHandle?
lazy var outgoingBubbleImageView: JSQMessagesBubbleImage = self.setupOutgoingBubble()
lazy var incomingBubbleImageView: JSQMessagesBubbleImage = self.setupIncomingBubble()
 private var updatedMessageRefHandle: DatabaseHandle?
override func viewDidLoad() {
    super.viewDidLoad()
    self.title = "Chat Room"
    navigationItem.leftBarButtonItem = UIBarButtonItem(title: "Back", style: .plain, target: self, action: #selector(addTapped))

    self.ref = Database.database().reference(fromURL: "Database URL")

    guard let str = UserDefaults.standard.string(forKey: "name") else {
        return
    }
    senderDisplayName = str

    self.senderId = Auth.auth().currentUser?.uid as NSString?! as String!

    collectionView!.collectionViewLayout.incomingAvatarViewSize = CGSize.zero
    collectionView!.collectionViewLayout.outgoingAvatarViewSize = CGSize.zero

    observeMessages()
    // Do any additional setup after loading the view.

}

发送按钮代码是这个，

 override func didPressSend(_ button: UIButton!, withMessageText text: String!, senderId: String!, senderDisplayName: String!, date: Date!) {
    let itemRef = messageRef.childByAutoId()
    let messageItem = [
        "senderId": senderId!,
        "senderName": senderDisplayName!,
        "text": text!,
        ]

    itemRef.setValue(messageItem)

    JSQSystemSoundPlayer.jsq_playMessageSentSound()

    collectionView.reloadData()

    finishSendingMessage()


}

在 UI 中显示消息是这样的，

 private func observeMessages() {
    //messageRef = channelRef!.child("messages")


    // 1.
    let messageQuery = messageRef.queryLimited(toLast:25)

    // 2. We can use the observe method to listen for new
    // messages being written to the Firebase DB
    newMessageRefHandle = messageQuery.observe(.childAdded, with: { (snapshot) -> Void in
        // 3
        let messageData = snapshot.value as! Dictionary<String, String>

        if let id = messageData["senderId"] as String!, let name = messageData["senderName"] as String!, let text = messageData["text"] as String!, text.characters.count > 0 {
            // 4
            self.addMessage(withId: id, name: name, text: text)

            // 5
            self.finishReceivingMessage()

                }

    })

    updatedMessageRefHandle = messageRef.observe(.childChanged, with: { (snapshot) in
                          })
}

这就是我的数据库的外观

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Best Answer-推荐答案

我不知道我是否完全理解您的问题，但据我所知，您正试图从数据库中删除 Message 层。您应该可以通过更改文件顶部的这一行来完成此操作

lazy var messageRef = Database.database().reference().child("Message") to -> lazy var messageRef = Database.database().reference()

这将删除该层。如果这不是您所描述的问题，请告诉我。

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