我是编程新手,可能被一个简单的问题挂断了。我在我的表格 View 中为我的数组使用解析。选择该行后,我想转到另一个 View Controller 上的搜索栏。 segue 工作正常,tableview 工作正常,但我似乎无法让 objectId 通过。
#import "bookmarkViewController.h"
#import "arse/Parse.h"
#import <arseUI/ParseUI.h>
#import "ViewController.h"
@implementation bookmarkViewController
@synthesize postArray;
#pragma mark - View lifecycle
- (void)viewDidLoad
{
[super viewDidLoad];
[self.navigationItem setLeftBarButtonItem:[[UIBarButtonItem alloc]
initWithBarButtonSystemItem:UIBarButtonSystemItemRefresh target:self
actionselector(refreshButtonHandler]];
}
- (void)viewWillAppearBOOL)animated
{
if ([PFUser currentUser])
[self refreshButtonHandler:nil];
}
#pragma mark - Button handlers
- (void)refreshButtonHandlerid)sender
{
//Create query for all Post object by the current user
PFQuery *postQuery = [PFQuery queryWithClassName"ost"];
[postQuery whereKey"author" equalTo:[PFUser currentUser]];
// Run the query
[postQuery findObjectsInBackgroundWithBlock:^(NSArray *objects, NSError *error) {
if (!error) {
//Save results and update the table
postArray = objects;
[self.tableView reloadData];
}
}];
}
#pragma mark - Table view data source
- (NSInteger)tableViewUITableView *)tableView numberOfRowsInSection:
(NSInteger)section
{
// Return the number of rows in the section.
return postArray.count;
}
- (UITableViewCell *)tableViewUITableView *)tableView cellForRowAtIndexPath:
(NSIndexPath *)indexPath
{
static NSString *CellIdentifier = @"Cell";
UITableViewCell *cell = [tableView
dequeueReusableCellWithIdentifier:CellIdentifier];
if (cell == nil) {
cell = [[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault
reuseIdentifier:CellIdentifier];
}
// Configure the cell with the textContent of the Post as the cell's text label
PFObject *post = [postArray objectAtIndex:indexPath.row];
[cell.textLabel setText:[post objectForKey"textContent"]];
return cell;
}
- (void)tableViewUITableView *)tableView didSelectRowAtIndexPathNSIndexPath
*)indexPath{
NSLog(@"cell tapped");
PFObject *post = [postArray objectAtIndex:indexPath.row];
NSLog(@"%@", post.objectId);
[self performSegueWithIdentifier"searchBookmark" sender:self];
}
- (void)prepareForSegueUIStoryboardSegue *)segue senderid)sender
{
ViewController *vc = [segue destinationViewController];
vc.labelText = post.objectId;
}
}
@end
在 vc.label.text 中,我总是使用未声明的标识符“post”,但我似乎不知道如何识别它。就是在上面的方法中。
NSLogs 正确回复 16:17:27.513 [App] 单元被点击 [应用] cgdVY7Eu9h
将您的 didSelectRowAtIndexPath 和 prepareForSegue 更改为:
- (void)tableViewUITableView *)tableView didSelectRowAtIndexPathNSIndexPath* )indexPath{
[self performSegueWithIdentifier"searchBookmark" sender:self];
}
- (void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender
{
NSIndexPath *indexPath = [self.tableView indexPathForSelectedRow];
NSLog(@"cell tapped");
PFObject *post = [postArray objectAtIndex:indexPath.row];
NSLog(@"%@", post.objectId);
ViewController *vc = [segue destinationViewController];
vc.labelText = post.objectId;
}
}
关于ios - tableview segue 到另一个 View Controller ,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/27238999/
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