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标题: ios - 登录时禁用(登录)按钮 [打印本页]

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作者: 菜鸟教程小白    时间: 2022-12-12 15:29
标题: ios - 登录时禁用(登录)按钮

您好，我正在开发这个有登录部分的应用程序。我想要的是当我单击登录按钮时，该按钮必须是不可点击的，直到登录成功或失败。我已经尝试添加这一行 doLogin.enabled = NO; 但这没有用。请帮忙。这是我的代码:

- (IBAction)doLoginid)sender {

    [self loginUser];
}

- (void)loginUser
{

    if (![self.usernameBox.text isEqualToString""] && ![self.passwordBox.text isEqualToString""])
    {
        //TODO: check id email pattern is correct
        [self showLoginProcess:true];
        [[AuthSingleton getInstance] attemptLoginWithUsername:self.usernameBox.text andPassword:self.passwordBox.text withSuccesBlock:^(AFHTTPRequestOperation *operation, id responseObject)
         {
             [self showLoginProcess:false];

             UIViewController *newFrontController = nil;
             PaMapViewController * vc = [[PaMapViewController alloc] init];
             newFrontController = [[UINavigationController alloc] initWithRootViewController:vc];

             SWRevealViewController *revealController = self.revealViewController;
             [revealController pushFrontViewController:newFrontController animated:YES];
         } andFailureBlock:^(AFHTTPRequestOperation *operation, NSError *error)
         {
             NSDictionary *dic = [error.userInfo objectForKey"JSONResponseSerializerWithDataKey"];
             #ifdef DEBUG
             NSLog(@"dic = %@", dic);
             #endif
             if ([[dic objectForKey"error_uri"] isEqual"phone"])
             {
                 NSError *jsonError;
                 NSData *objectData = [[dic objectForKey"error_description"] dataUsingEncoding:NSUTF8StringEncoding];
                 NSDictionary *json = [NSJSONSerialization JSONObjectWithDatabjectData
                                                                      options:NSJSONReadingMutableContainers
                                                                        error:&jsonError];
                 [self loginFailed:json];
             }
             else
             {
                 [self loginFailed:dic];
             }
         }];
    }
    else
    {
        //TODO: show proper message Test
        NSLog(@"username or password is empty %@", kBaseURL);
    }
}

- (void)showLoginProcessBOOL) show
{
    [self.spinner setColor:[UIColor whiteColor]];
    self.spinner.hidden = !show;
    self.usernameBox.hidden = show;
    self.passwordBox.hidden = show;
    if (show)

    {
        [self.spinner startAnimating];
    } else
    {
        [self.spinner stopAnimating];
    }
}

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Best Answer-推荐答案

希望您已经为登录按钮声明了一个属性。让它成为“doLogin”。

你需要做的是

- (IBAction)doLoginid)sender

{

[self loginUser];
doLogin.userInteractionEnabled = NO;

}

当登录成功或失败时写入

doLogin.userInteractionEnabled = YES;

在相应的区 block 内。

关于ios - 登录时禁用(登录)按钮，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/30751906/

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