所以我有一个基于 webview 的应用程序。我做了一些键盘修改(不是问题,将它们全部删除以进行故障排除)。
在 iPhone 6+ 模拟器上,当处于横向模式时,如果复制了某些内容,并且您使用键盘粘贴按钮(不是上下文按钮),应用程序会崩溃。我在尝试使用键盘剪切按钮时也注意到了这一点。
以下崩溃如下:
-[UIThreadSafeNode _responderForEditing]: unrecognized selector sent to instance 0x7ff4364344c0
*** Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: '-[UIThreadSafeNode _responderForEditing]: unrecognized selector sent to instance 0x7ff4364344c0'
*** First throw call stack:
(
0 CoreFoundation 0x000000010df98f45 __exceptionPreprocess + 165
1 libobjc.A.dylib 0x000000010da12deb objc_exception_throw + 48
2 CoreFoundation 0x000000010dfa156d -[NSObject(NSObject) doesNotRecognizeSelector:] + 205
3 CoreFoundation 0x000000010deeeeea ___forwarding___ + 970
4 CoreFoundation 0x000000010deeea98 _CF_forwarding_prep_0 + 120
5 UIKit 0x000000010c31eb4a -[UIKeyboardLayoutStar touchDownWithKey:atPoint:executionContext:] + 1445
6 UIKit 0x000000010c878ef0 -[UIKeyboardTaskExecutionContext returnExecutionToParentWithInfo:] + 278
7 UIKit 0x000000010c3169de -[UIKeyboardLayoutStar performHitTestForTouchInfo:touchStage:executionContextPassingUIKBTree:] + 1525
8 UIKit 0x000000010c31de57 -[UIKeyboardLayoutStar touchDown:executionContext:] + 533
9 UIKit 0x000000011df96fb5 -[UIKeyboardLayoutStarAccessibility touchDown:executionContext:] + 61
10 UIKit 0x000000010c8793ab -[UIKeyboardTaskQueue continueExecutionOnMainThread] + 332
11 UIKit 0x000000010c1347bd -[UIKeyboardLayout touchDown:] + 159
12 UIKit 0x000000010c1352ef -[UIKeyboardLayout touchesBegan:withEvent:] + 415
13 UIKit 0x000000010bee2cc2 -[UIWindow _sendTouchesForEvent:] + 308
14 UIKit 0x000000010bee3c06 -[UIWindow sendEvent:] + 865
15 UIKit 0x000000010be932fa -[UIApplication sendEvent:] + 263
16 UIKit 0x000000011df66a29 -[UIApplicationAccessibility sendEvent:] + 77
17 UIKit 0x000000010be6dabf _UIApplicationHandleEventQueue + 6844
18 CoreFoundation 0x000000010dec5011 __CFRUNLOOP_IS_CALLING_OUT_TO_A_SOURCE0_PERFORM_FUNCTION__ + 17
19 CoreFoundation 0x000000010debaf3c __CFRunLoopDoSources0 + 556
20 CoreFoundation 0x000000010deba3f3 __CFRunLoopRun + 867
21 CoreFoundation 0x000000010deb9e08 CFRunLoopRunSpecific + 488
22 GraphicsServices 0x000000010ead2ad2 GSEventRunModal + 161
23 UIKit 0x000000010be7330d UIApplicationMain + 171
显然,因为我使用的是 webview,所以没有实际的 textview 可以绑定(bind)到它。
我将如何解决这个问题?我不关心通过应用商店审查,所以欢迎私有(private) API 或其他非苹果批准的方法。
任何帮助将不胜感激。谢谢。
这是Apple的错误,因为这个选择器应该传递给UIResponder
,但UIThreadSafeNode
是NSObject
的子类。为了解决这个问题,您可以实现 NSObject
类别:
@interface UIView (FirstResponder)
-(id)findFirstResponder;
@end
@implementation UIView (FirstResponder)
- (id)findFirstResponder
{
if (self.isFirstResponder) {
return self;
}
for (UIView *subView in self.subviews) {
id responder = [subView findFirstResponder];
if (responder) return responder;
}
return nil;
}
@end
@interface NSObject (KeyboardBUI)
-(_Nonnull id)_responderForEditing;
@end
@implementation NSObject (KeyboardBUI)
-(_Nonnull id)_responderForEditing
{
return self;
}
-(void)cutnullable id)sender
{
NSString *selection = [[self getWebView] stringByEvaluatingJavaScriptFromString"window.getSelection().toString()"];
[[self getWebView] stringByEvaluatingJavaScriptFromString"document.execCommand('delete', false, null)"];
[UIPasteboard generalPasteboard].string = selection;
}
-(void)pastenullable id)sender
{
NSString *text = [UIPasteboard generalPasteboard].string;
[[self getWebView] stringByEvaluatingJavaScriptFromString:[NSString stringWithFormat"document.execCommand('insertHTML', false, '%@')", text]];
}
-(void)copynullable id)sender
{
NSString *selection = [[self getWebView] stringByEvaluatingJavaScriptFromString"window.getSelection().toString()"];
[UIPasteboard generalPasteboard].string = selection;
}
-(void)toggleItalicsnullable id)sender
{
[[self getWebView] stringByEvaluatingJavaScriptFromString"document.execCommand(\"Italic\")"];
}
-(void)toggleUnderlinenullable id)sender
{
[[self getWebView] stringByEvaluatingJavaScriptFromString"document.execCommand(\"Underline\")"];
}
-(void)toggleBoldfacenullable id)sender
{
[[self getWebView] stringByEvaluatingJavaScriptFromString"document.execCommand(\"Bold\")"];
}
-(UIWebView * __nullable)getWebView
{
UIWebView *retVal = nil;
id obj = [[[[[UIApplication sharedApplication] keyWindow] findFirstResponder] superview] superview];
if ([obj isKindOfClass:[UIWebView class]]) {
retVal = obj;
}
return retVal;
}
@end
注意:我不知道这是否会通过 Apple Appstore 审核。
UIView (FirstResponder)
类别来自 answer .
从此 answer 复制/粘贴/剪切
关于ios - UIWebview [UIThreadSafeNode _responderForEditing] 崩溃,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/33807812/
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