{
duration = "00:06:29";
id = 7;
}
NSNumberFormatter *numberFormatter = [[NSNumberFormatter alloc] init];
numberFormatter.numberStyle = NSNumberFormatterDecimalStyle;
float value = [numberFormatter numberFromString:currentAutio.duration].floatValue;
NSLog(@"Current audio %f",value);
out 是 当前音频 0.0000
如何将持续时间字符串设为浮点值?
最简单的方法是
NSString *duration = @"00:06:29";
NSArray *array = [duration componentsSeparatedByString":"];
NSLog(@"Current hrs %ld",(long)[(NSString *)(array[0]) integerValue]);
NSLog(@"Current min %ld",(long)[(NSString *)(array[1]) integerValue]);
NSLog(@"Current sec %ld",(long)[(NSString *)(array[2]) integerValue]);
否则你也可以使用 NSDate
& NSDateFormatter
。
使用 NSDate
,注意小时部分不应超过 23 否则结果可能与预期不符。
NSString *duration = @"00:06:29";
NSDateFormatter *formatter = [NSDateFormatter new];
formatter.dateFormat = @"HH:mm:ss";
NSDate *date = [formatter dateFromString:duration];
NSCalendar *calendar = [NSCalendar currentCalendar];
NSDateComponents *components = [calendar components:NSCalendarUnitHour | NSCalendarUnitMinute | NSCalendarUnitSecond fromDate:date];
NSLog(@"hrs %ld", (long)components.hour);
NSLog(@"min %ld", (long)components.minute);
NSLog(@"sec %ld", (long)components.second);
关于ios - 获取音频持续时间字符串以 float 值,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/41329321/
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