OStack程序员社区-中国程序员成长平台

标题: ios - 基于另一个 UIPickerView 显示 UIPickerView [打印本页]

---

作者: 菜鸟教程小白    时间: 2022-12-13 09:52
标题: ios - 基于另一个 UIPickerView 显示 UIPickerView

我有两个不同的 UIPickerView 用户选择第一个 UIPickerView 并从第一个选择器的 didSelectRow 中，我得到第二个的输入 UIPickerView。我尝试为单个选择器设置标签，但没有任何效果。我的代码如下。

//Picker-1
pickerView1 = [[UIpickerView alloc] init];
pickerView1 setDataSource: self];
[pickerView1 setDelegate: self];
[pickerView1 setFrame: CGRectMake(85,360,99,162)];
pickerView1.showsSelectionIndicator = YES;
[pickerView1 selectRow:2 inComponent:0 animated:YES];

//Picker-2
pickerView2 = [[UIpickerView alloc] init];
pickerView2 setDataSource: self];
[pickerView2 setDelegate: self];
[pickerView2 setFrame: CGRectMake(191,360,99,162)];
pickerView2.showsSelectionIndicator = YES;
[pickerView2 selectRow:2 inComponent:0 animated:YES];

//Picker -1 rows
- (NSInteger)numberOfComponentsInPickerViewUIPickerView *)pickerView{
    return 1;
}
 - (NSInteger)pickerViewUIPickerView *)pickerView numberOfRowsInComponentNSInteger)component{
    return getvalue1.count;
}
- (NSString *)pickerViewUIPickerView *)pickerView titleForRowNSInteger)row forComponentNSInteger)component{
        return [getvalue1 objectAtIndex: row];
    } 
-(void)pickerViewUIPickerView *)pickerView didSelectRowNSInteger)row inComponentNSInteger)component{  
        NSLog(@"You selected this: %@", [getvalue1 objectAtIndex: row]);
        NSArray *getvalue2 =[getvalue1 objectAtIndex: row];

    }

//Picker-2 rows

-(NSInteger)numberOfComponentsInPickerView2UIPickerView *)pickerView{
    return 1;
}

-(NSInteger)pickerView2:(UIPickerView *)pickerView numberOfRowsInComponent:(NSInteger)component{  
    return getvalue2.count;
}

-(NSString *)pickerView2:(UIPickerView *)pickerView titleForRow:(NSInteger)row forComponent:(NSInteger)component{     
    return [getvalue2 objectAtIndex: row];
}

-(void)pickerView2:(UIPickerView *)pickerView didSelectRow:(NSInteger)row inComponent:(NSInteger)component{
    NSLog(@"You selected this: %@", [getvalue2 objectAtIndex: row]);
}

问题是在显示时都获得了第一个选择器值。选择器 2 行没有被调用。

---

Best Answer-推荐答案

您只能拥有一组选取器 View 委托(delegate)方法。使用每个的 pickerView 参数来做正确的事情:

- (NSInteger)numberOfComponentsInPickerView:(UIPickerView *)pickerView{
    return 1;
}

- (NSInteger)pickerView:(UIPickerView *)pickerView numberOfRowsInComponent:(NSInteger)component{
    if (pickerView == pickerView1) {
        return getvalue1.count;
    } else {
        return getValue2.count;
    }
}

- (NSString *)pickerView:(UIPickerView *)pickerView titleForRow:(NSInteger)row forComponent:(NSInteger)component{
    if (pickerView == pickerView1) {
        return [getvalue1 objectAtIndex: row];
    } else {
        return [getvalue2 objectAtIndex: row];
    }
} 

- (void)pickerView:(UIPickerView *)pickerView didSelectRow:(NSInteger)row inComponent:(NSInteger)component{  
    if (pickerView == pickerView1) {
        NSLog(@"You selected this: %@", [getvalue1 objectAtIndex: row]);
        NSArray *getvalue2 =[getvalue1 objectAtIndex: row];
    } else {
        NSLog(@"You selected this: %@", [getvalue2 objectAtIndex: row]);
    }
}

关于ios - 基于另一个 UIPickerView 显示 UIPickerView，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/32061357/

---

欢迎光临 OStack程序员社区-中国程序员成长平台 (https://ostack.cn/)

Powered by Discuz! X3.4