如何提取带有路径的 UIImage?
我需要将路径内的内容放入新的 UIImage。我需要的是旋转矩形的内容。这是我用来获取矩形角的代码。 (x,y = 图像的中心。图像的宽度、高度)。
UIBezierPath* aPath = [UIBezierPath bezierPath];
//1
[aPath moveToPoint:CGPointMake(
x+(width/2)*cosf(A)-(height/2)*sinf(A),
y+(height/2)*cosf(A)+(width/2)*sinf(A))];
NSLog(@"%f, %f", x+(width/2)*cosf(A)-(height/2)*sinf(A),
y+(height/2)*cosf(A)+(width/2)*sinf(A));
//2
[aPath moveToPoint:CGPointMake(
x-(width/2)*cosf(A)-(height/2)*sinf(A),
y+(height/2)*cosf(A)-(width/2)*sinf(A))];
NSLog(@"%f, %f", x-(width/2)*cosf(A)-(height/2)*sinf(A),
y+(height/2)*cosf(A)-(width/2)*sinf(A));
//3
[aPath moveToPoint:CGPointMake(
x-(width/2)*cosf(A)+(height/2)*sinf(A),
y-(height/2)*cosf(A)-(width/2)*sinf(A))];
NSLog(@"%f, %f", x-(width/2)*cosf(A)+(height/2)*sinf(A),
y-(height/2)*cosf(A)-(width/2)*sinf(A));
//4
[aPath moveToPoint:CGPointMake(
x+(width/2)*cosf(A)+(height/2)*sinf(A),
y-(height/2)*cosf(A)+(width/2)*sinf(A))];
NSLog(@"%f, %f", x+(width/2)*cosf(A)+(height/2)*sinf(A),
y-(height/2)*cosf(A)+(width/2)*sinf(A));
//5
[aPath moveToPoint:CGPointMake(
x+(width/2)*cosf(A)-(height/2)*sinf(A),
y+(height/2)*cosf(A)+(width/2)*sinf(A))];
NSLog(@"%f, %f", x+(width/2)*cosf(A)-(height/2)*sinf(A),
y+(height/2)*cosf(A)+(width/2)*sinf(A));
[aPath closePath];
我在想这样的事情:A picture of the problem. (这里的形状不同。)我希望那个黄色部分是一个新的 UIImage。
使用您的 UIBezierPath
作为剪切路径。有 addClip
方法。
见 the Quartz2D Programming Guide , 特别是 this part了解详情。
这个想法是创建一个新的位图上下文,使用您的路径应用剪辑,然后在此位图上下文上绘制图像(因此将被剪辑),最后从中生成一个 UIImage。
此外,与其自己做一些数学运算来旋转您要用于剪辑的 CGRect
,不如创建一个没有任何旋转的 CGRect
,并且使用 CGAffineTransform
旋转它。这将避免使用 cos
/sin
函数自己进行计算的需要,并使您的代码更易于阅读。
[编辑] 这是一个完整的例子:
我确实检查过它,它就像一个魅力。
// Generate a UIBezierPath of a rounded rect rotated by angle radians
-(UIBezierPath*)computePathWithRectCGRect)rect
cornerRadiusCGFloat)cornerRadius
angleCGFloat)radians;
{
// Compute basic path
UIBezierPath* path = [UIBezierPath bezierPathWithRoundedRect:rect cornerRadius:cornerRadius];
// Apply rotation.
// Don't forget that rotations are around origin 0,0 so if you want to rotate around the rect's center,
// you need to apply a translation so that the rect's center is at 0,0, then rotate, and translate it back at its original position.
CGAffineTransform restoreCenterPosition = CGAffineTransformMakeTranslation(CGRectGetMidX(rect), CGRectGetMidY(rect));
CGAffineTransform rotateFromOrigin = CGAffineTransformRotate(restoreCenterPosition,radians);
CGAffineTransform rotateFromRectCenter = CGAffineTransformTranslate(rotateFromOrigin, -CGRectGetMidX(rect), -CGRectGetMidY(rect));
[path applyTransform:rotateFromRectCenter];
return path;
}
// Generate a new image from srcImage but clipped with the given path
-(UIImage*)clipImageUIImage*)srcImage withPathUIBezierPath*)path
{
UIGraphicsBeginImageContextWithOptions(srcImage.size, NO, 0.0);
// Add clipping path
// Actually UIBezierPath has a method for that, that is equivalent to CGContextClip(currentContext, bezierPath.CGPath), so better use it
[path addClip];
// Flip coordinates before drawing image as UIKit and CoreGraphics have inverted coordinate system
CGContextTranslateCTM(UIGraphicsGetCurrentContext(), 0, srcImage.size.height);
CGContextScaleCTM(UIGraphicsGetCurrentContext(), 1, -1);
// Draw image, that will thus be clipped, on the bitmap context
CGContextDrawImage(UIGraphicsGetCurrentContext(), CGRectMake(0, 0, srcImage.size.width, srcImage.size.height), srcImage.CGImage);
// Generate final (clipped) image
UIImage* clippedImage = UIGraphicsGetImageFromCurrentImageContext();
UIGraphicsEndImageContext();
return clippedImage;
}
// Usage example
- (void)doClipping
{
UIImage* originalImage = ...
UIBezierPath* path = [self computePathWithRect:CGRectMake(100,100,184,94)
cornerRadius:10.f
angle:30*M_PI/180.f];
UIImage* clippedImage = [self clipImageriginalImage withPath:path];
self.resultImageView.image = clippedImage;
}
关于ios - 用路径提取 UIImage,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/12265834/
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