我见过使用选择器 View 的示例,其中选择器的值像这样硬编码到源代码中
- (NSString *)pickerViewUIPickerView *)pickerView titleForRowNSInteger)row forComponentNSInteger)component {
NSString * title = nil;
switch(row) {
case 0:
title = @"a";
break;
case 1:
title = @"b";
break;
case 2:
title = @"c";
break;
}
但是,如果要在选择器 View 中显示 100 个数字,那将是非常不切实际的。我相信你可以在下面看到我想要做的事情。它给了我错误
expression is not an integer constant expression
如何在选择器 View 中获取 0 到 100 的数字?如果有更好的方法来获取用户选择 1 到 100 之间的数字的输入,请随时发表评论。
- (NSString *)pickerViewUIPickerView *)pickerView titleForRowNSInteger)row forComponentNSInteger)component {
NSString * title = nil;
if (pickerView.tag == 1) // this is otherPickerview
{
otherpickerview
for (int i = 2; i < 100; i++){
switch(row) {
case i:
title = [NSString stringWithFormat"%d", i];
break;
}
}
}
Best Answer-推荐答案 strong>
让我们试试吧:
- (NSInteger)numberOfComponentsInPickerViewUIPickerView *)pickerView
{
return 3;
}
- (NSInteger)pickerViewUIPickerView *)pickerView numberOfRowsInComponentNSInteger)component
{
return _arr.count;
}
- (NSString *)pickerViewUIPickerView *)pickerView titleForRow:(NSInteger)row forComponent:(NSInteger)component
{
// you can switch to other UIPickerView, and return title for row which you want.
// don't need to loop whenever titleForRow is called.
return _arr[row];
}
- (void)viewDidLoad
{
[super viewDidLoad];
// Do any additional setup after loading the view, typically from a nib.
[self.navigationController setNavigationBarHidden:YES];
_arr = [[NSMutableArray alloc]init];
for (int i = 0; i<100; i++) {
NSString *str = [NSString stringWithFormat"%d",i];
[_arr addObject:str];
}
_pickerView.dataSource = self;
_pickerView.delegate = self;
}
关于ios - 具有大量数值的 PickerView,我们在Stack Overflow上找到一个类似的问题:
https://stackoverflow.com/questions/23190292/
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