我目前正在尝试发布到一个 php Web 服务,该服务将查询一个 mysql 数据库并 [应该] 返回一个字符串值。我研究了 AFNetworking,但不明白如何使用从查询返回的值。例如:
AFHTTPRequestOperationManager *manager = [AFHTTPRequestOperationManager manager];
[manager POST"http://samwize.com/api/poo/"
parameters{@"color": @"green"}
success:^(AFHTTPRequestOperation *operation, id responseObject) {
NSLog(@"JSON: %@", responseObject);
} failure:^(AFHTTPRequestOperation *operation, NSError *error) {
NSLog(@"Error: %@", error);
}];
我猜我操纵 responseObject 来得到我期望的字符串?任何帮助将不胜感激
Best Answer-推荐答案 strong>
AFHTTPRequestOperationManager *manager = [AFHTTPRequestOperationManager manager];
[manager POST"http://samwize.com/api/poo/"
parameters{@"color": @"green"}
success:^(AFHTTPRequestOperation *operation, id responseObject) {
NSError *error = nil;
NSDictionary *JSON = [NSJSONSerialization JSONObjectWithData:responseObject options:NSJSONReadingAllowFragments error:&error];
if (error) {
NSLog(@"Error serializing %@", error);
}
NSLog(@"JSON: %@", JSON);
} failure:^(AFHTTPRequestOperation *operation, NSError *error) {
NSLog(@"Error: %@", error);
}];
这会将您的 JSON 响应转换为 NSDictionary
关于iOS AFNetworking 发布问题,我们在Stack Overflow上找到一个类似的问题:
https://stackoverflow.com/questions/29807696/
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