ios - Json 代码不起作用

NSString *urlString = @"http://chkdin.com/dev/api/peoplearoundmexy/?";
NSURL *url = [NSURL URLWithString:urlString];

NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init];

NSString *parameterString=[NSString stringWithFormat"skey=%@&user_id=%@",@"XXXXXXX",@"3225"];


NSLog(@"%@",parameterString);


[request setHTTPMethod"OST"];

[request setURL:url];

[request setValue:parameterString forHTTPHeaderField"Content-Length"];
[request setValue"application/x-www-form-urlencoded" forHTTPHeaderField"Content-Type"];


NSData *postData = [parameterString dataUsingEncoding:NSUTF8StringEncoding];

[request setHTTPBody:postData];

    NSData *data = [NSURLConnection sendSynchronousRequest:request returningResponse:nil error:&error];
    NSLog(@"%@",[NSJSONSerialization JSONObjectWithData:data options:kNilOptions error:&error]);
    NSDictionary *dict = [NSJSONSerialization JSONObjectWithData:data options:kNilOptions error:&error];
    NSLog(@"%@",dict);

这是我的 json 解析，我的问题是当我点击这个 api 时它正在显示

{
  message = "Valid skey required.";
status = 0;
}

但是这个 api 在 safari 中工作。我认为问题是请求添加到 url 错误。你能帮我吗....

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Best Answer-推荐答案

我通过 AFNetworking 3 得到响应

试试这个

 AFHTTPSessionManager *manager = [AFHTTPSessionManager manager];
    manager.responseSerializer = [AFJSONResponseSerializer serializer];
    [manager GET"http://chkdin.com/dev/api/peoplearoundmexy/?" parameters{@"skey""sa6rw9er7twefc9a7dvcxcheckedin",@"user_id""3225"} progress:nil success:^(NSURLSessionTask *task, id responseObject) {
        NSLog(@"%@",responseObject);
    } failure:^(NSURLSessionTask *operation, NSError *error) {
    }];

关于ios - Json 代码不起作用，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/40839384/