我想在 Twitter 中使用 SLRequest 获取用户个人资料信息?
目前我正在编写代码
NSURL *url = [NSURL URLWithString"https://api.twitter.com/1.1/users/show.json"];
NSDictionary *params = [NSDictionary dictionaryWithObjectsAndKeys"ali",@"screen_name",nil];
account = [[ACAccountStore alloc] init];
ACAccountType *twitterAccountType = [account accountTypeWithAccountTypeIdentifier:ACAccountTypeIdentifierTwitter];
NSArray *twitterAccounts = [account accountsWithAccountType:twitterAccountType];
// Runing on iOS 6
if ([LoginViewController isTwitterAvailable])
{
NSLog(@"In the IFF...... ");
[account requestAccessToAccountsWithType:twitterAccountType options:NULL completion:^(BOOL granted, NSError *error)
{
NSLog(@"in body ");
if (granted)
{
NSLog(@"in granted ..");
SLRequest *request = [SLRequest requestForServiceType:SLServiceTypeTwitter requestMethod:SLRequestMethodGET URL:url parameters:params];
[request setAccount:[twitterAccounts lastObject]];
dispatch_async(dispatch_get_main_queue(), ^
{
[NSURLConnection sendAsynchronousRequest:request.preparedURLRequest queue:[[NSOperationQueue alloc] init] completionHandler:^(NSURLResponse *response1, NSData *data, NSError *error)
{
dispatch_async(dispatch_get_main_queue(), ^
{
if (data)
{
//NSString *string = [[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding] ;
//NSLog(@"data:%@",string);
NSError* error;
NSDictionary* dicUser = [NSJSONSerialization
JSONObjectWithData:data
options:kNilOptions
error:&error];
它返回整个信息,而不是个人资料信息,
如何获取登录用户的个人资料?
谢谢
Best Answer-推荐答案 strong>
尝试遵循来自实时项目之一的代码,您可以根据现有结构进行修改。如果有任何问题,请告诉我。
_accountStore = [[ACAccountStore alloc] init]; //Declare accountStore as property and initialize
ACAccountType *accountType = [_accountStore accountTypeWithAccountTypeIdentifier:ACAccountTypeIdentifierTwitter];
[_accountStore requestAccessToAccountsWithType:accountType options:nil completion:^(BOOL granted, NSError *error){
if (granted){
NSArray *accounts = [_accountStore accountsWithAccountType:accountType];
if (accounts.count > 0){
ACAccount *twitterAccount = [accounts lastObject];
NSDictionary *dict1 = [twitterAccount dictionaryWithValuesForKeys:[NSArray arrayWithObject"properties"]];
NSDictionary *properties = dict1[@"properties"];
NSDictionary *returnDict = @{@"TwitterID":properties[@"user_id"],@"UserName":twitterAccount.username};
NSLog(@"rofile details->%@",properties);
}else{
NSMutableDictionary* details = [NSMutableDictionary dictionary];
[details setValue:kTwitterErrorMsg forKey:NSLocalizedDescriptionKey];
error = [NSError errorWithDomain"Domain" code:error.code userInfo:details];
NSLog(@"Error occured->%@",error.localizedDescription);
}
} else {
NSMutableDictionary* details = [NSMutableDictionary dictionary];
if(error.code == ACErrorAccountNotFound){
[details setValue:kTwitterErrorMsg forKey:NSLocalizedDescriptionKey];
}else if(error.code == ACErrorPermissionDenied || error.code == ACErrorAccessDeniedByProtectionPolicy) {
[details setValue:kTwitterAccessDeniedMsg forKey:NSLocalizedDescriptionKey];
}else {
[details setValue:kTwitterErrorMsg forKey:NSLocalizedDescriptionKey];
}
error = [NSError errorWithDomain"Domain" code:error.code userInfo:details];
NSLog(@"Error occured->%@",error.localizedDescription);
}
}];
几个宏
#define kTwitterErrorMsg @"lease set your Twitter account in Settings."
#define kTwitterAccessDeniedMsg @"Twitter Access denied."
关于ios - 如何获取正在使用 twitter SLRequest 登录的用户信息?,我们在Stack Overflow上找到一个类似的问题:
https://stackoverflow.com/questions/22478817/
|