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c - How to make gdb follow execv? Not working despite "follow-exec-mode"

i've written two simple programs:

int main(int ac, char **argv ) {
    execv( "/home/me/Desktop/execvtest2", argv );
}

and

int main(int ac, char **argv ) {
    execv( "/home/me/Desktop/execvtest1", argv );
}

I've compiled them with gcc -g to the according outputfiles. I'm running Ubuntu 10.10 using gcc (Ubuntu/Linaro 4.4.4-14ubuntu5.1) 4.4.5.

When I'm debuging the first program with GNU gdb (GDB) 7.2-ubuntu, I can step until the first execv statement, but then the two files just keep running. Even if I set the follow-exec-mode to new, I can't step into the second program. When I set catch exec, gdb stops at each call to execv (some how without linked source for the second program, and I'm not able to quit gdb, as it kind of hangs!?), but I'm not able to step over the call into the "new" (as exec replaces the process) inferior program.

So how can this be done? There must be a way to step into the new process right? Am I doing something wrong?

Cheers

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1 Answer

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by (71.8m points)

you can use "catch" command. this will give you chance to put some break points after you exec


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