You cannot "merge symbols" in Lisp.
First of all, 5
is not a symbol, but a number. If you want a symbol named "5"
you have to type it as |5|
(for example).
If a function takes the symbol A
and symbol |5|
, and produces the symbol A5
, it has not merged symbols. It has created a new symbol whose name is the catenation of the names of those input symbols.
Properly designed Lisp programs rarely depend on how a symbol is named. They depend on symbols being unique entities.
If you're using symbols to identify things, and both 5
and A
identify some entity, the best answer isn't necessarily to create a new symbol which is, in name at least, is a mashup of these two symbols. For instance, a better design might be to accept that names are multi-faceted or compound in some way. Perhaps the list (A 5)
can serve as a name.
Common Lisp functions themselves can have compound names. For instance (setf foo)
is a function name. Aggregates like lists can be names.
If you simply need the machine to invent unique symbols at run-time, consider using the gensym
function. You can pass your own prefix to it:
(gensym "FOO") -> #:FOO0042
Of course, the prefix can be the name of some existing symbol, pulled out via symbol-name
. The symbol #:FOO0042
is not unique because of the 0042
but because it is a freshly allocated object in the address space. The #:
means it is not interned in any package. The name of the symbol is FOO0042
.
If you still really want to, a simple way to take the printed representation of a bunch of input objects and turn it into a symbol is this:
(defun mashup-symbol (&rest objects)
(intern (format nil "~{~a~}" objects)))
Examples:
(mashup-symbol 1 2 3) -> |123|
(mashup-symbol '(a b) 'c 3) -> |(A B)C3|
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