Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
619 views
in Technique[技术] by (71.8m points)

python - How to create a binary list based on inclusion of list elements in another list

Given two lists of words, dictionary and sentence, I'm trying to create a binary representation based on the inclusion of words of dictionary in the sentence such as [1,0,0,0,0,0,1,...,0] where 1 indicates that the ith word in the dictionary shows up in the sentence.

What's the fastest way I can do this?

Example data:

dictionary =  ['aardvark', 'apple','eat','I','like','maize','man','to','zebra', 'zed']
sentence = ['I', 'like', 'to', 'eat', 'apples']
result = [0,0,1,1,1,0,0,1,0,0]

Is there something faster than the following considering that I'm working with very large lists of approximately 56'000 elements in size?

x = [int(i in sentence) for i in dictionary]
See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)
set2 = set(list2)
x = [int(i in set2) for i in list1]

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...