python - 如何从Python路径中获取不带扩展名的文件名？(How to get the filename without the extension from a path in Python?)

Question

如何从Python路径中获取不带扩展名的文件名？

  ask by Joan Venge translate from so

Answer 1

Getting the name of the file without the extension:

(获取不带扩展名的文件名：)

import os
print(os.path.splitext("/path/to/some/file.txt")[0])

Prints:

(印刷品：)

/path/to/some/file

Important Note: If the filename has multiple dots, only the extension after the last one is removed.

(重要说明：如果文件名有多个点，则仅删除最后一个扩展名之后的扩展名。)

For example:

(例如：)

import os
print(os.path.splitext("/path/to/some/file.txt.zip.asc")[0])

Prints:

(印刷品：)

/path/to/some/file.txt.zip

See other answers below if you need to handle that case.

(如果您需要处理这种情况，请参见下面的其他答案。)