python - 如果不存在，则Python中的open（）不会创建文件(open() in Python does not create a file if it doesn't exist)

Question

What is the best way to open a file as read/write if it exists, or if it does not, then create it and open it as read/write?

(如果文件以读/写方式打开，或者以不存在的方式创建，然后以读/写方式打开，最好的方法是什么？)

From what I read, file = open('myfile.dat', 'rw') should do this, right?

(根据我的阅读， file = open('myfile.dat', 'rw')应该这样做，对吗？)

It is not working for me (Python 2.6.2) and I'm wondering if it is a version problem, or not supposed to work like that or what.

(它对我不起作用（Python 2.6.2），我想知道这是否是版本问题，或者不应该那样工作或做什么。)

The bottom line is, I just need a solution for the problem.

(最重要的是，我只需要解决这个问题。)

I am curious about the other stuff, but all I need is a nice way to do the opening part.

(我对其他东西很好奇，但是我所需要的只是做开始部分的好方法。)

The enclosing directory was writeable by user and group, not other (I'm on a Linux system... so permissions 775 in other words), and the exact error was:

(封闭目录可由用户和组而非其他用户（我在Linux系统上...因此权限775）可写，确切的错误是：)

IOError: no such file or directory.

(IOError：没有这样的文件或目录。)

  ask by trh178 translate from so

Answer 1

您应该在w+模式下使用open ：

file = open('myfile.dat', 'w+')