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mysql - 关系代数SQL(Relational Algebra SQL)

Hello everyone i was wondering if i could get some help with a problem

(大家好,我想知道我是否可以得到一些帮助)

Postimi(status)(Post_ID:integer,user_ID:integer,test:string, data:date,time:integer)

(Postimi(状态)(Post_ID:整数,user_ID:整数,test:字符串,数据:日期,时间:整数))

I need to fing the Relational Algebra related to Postimi

(我需要找出与Postimi有关的关系代数)

the question is

(问题是)

List users who posted two or more statuses yesterday while today have not posted any statuses?

(列出昨天发布了两个或更多状态而今天没有发布任何状态的用户?)

if someone could help me.

(如果有人可以帮助我。)

Thank you in Advance

(先感谢您)

  ask by Arbnor Jusufi translate from so

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
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与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
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